For question 4 why do you take into account theta in terms of only the weight of the bar for the moment of `A but when you are resolving upwards you take theta in consideration at c not the weight and vice versa
probably too late but for anyone watching now, it's because the question says that P is *moving* in that direction, meaning that, when particle P is in motion, its *velocity* (speed with a given direction) is in the direction of (3i-4j), hence why V=3x + 4xj. x is the speed in the given direction btw
because you're resolving horizontally, the 20g weight is only vertical and its components create a vertically acting force which won't affect F. It's a bit easier to see if you draw a really neat diagram and make the component forces properly perpendicular just to make sure you don't mix them up
Because that would give us the horizontal displacement, whereas we are just trying to find horizontal velocity, which stays the same throughout the flight of the balls due to the lack of acceleration in the horizontal direction.
Great explanation, I'm watching this before my A Level Exam on Tuesday!
how did it go
@@rbshieldstar0075 got an a but retaking to get an a star, honestly stats and mechs is so easy if you just do every exam question
@@intheskies8081 how first 2 papers been for you.
For question 4 why do you take into account theta in terms of only the weight of the bar for the moment of `A but when you are resolving upwards you take theta in consideration at c not the weight and vice versa
why is V=3xi + 4xj ? Why wouldn't S(the displacement) be 3i + 4j instead ?? I thought position vector meant displacement ?
probably too late but for anyone watching now, it's because the question says that P is *moving* in that direction, meaning that, when particle P is in motion, its *velocity* (speed with a given direction) is in the direction of (3i-4j), hence why V=3x + 4xj. x is the speed in the given direction btw
@@riley2476 LOL i got an A lessgo🔥🔥🔥
@@ratofalady8125 haha congrats G
My only question is for the last question, why do you use subway for horizontal as well?
bless for this bro very well explained
Love from Bangladesh 🇧🇩 ❤ 💕 💖
How do you know when to give the angle when asking for velocity? Bc sometimes they need it
This isn't at all a criticism, but if it takes you over an hour how are we meant to do it :/
because hes explaining some of it as well and is taking his time.
you have ab hour for stats and 1 hour mechanics
Bro hes doing it slowly, explaining his steps so that's obv gonna take longer then just straight up answering the question.
Amazing explanation bro very helpful to understand the questions 👍
for question 4 why do you only resolve left/right = F at Rc and not at the weight 20g going downwards ???
because you're resolving horizontally, the 20g weight is only vertical and its components create a vertically acting force which won't affect F. It's a bit easier to see if you draw a really neat diagram and make the component forces properly perpendicular just to make sure you don't mix them up
thank you so much for this, very helpful!!
50:44 why don't you leave it as a vector?
I have this paper tomorrow thx i will do my exams seriously just need good grades rn
How did you do?
Thank you, very kind of you to give your time
In the last question why isn’t it 10 square root 3 multiplied by 2?
Because that would give us the horizontal displacement, whereas we are just trying to find horizontal velocity, which stays the same throughout the flight of the balls due to the lack of acceleration in the horizontal direction.
@@freshavocado5205 this number 5 stinks
@@whiteboy4226 not really
Brilliant vid
Very clear and understandable
Nice bro