4 Variable K-Map Simplification | SOP Examples | Part 1

[@siddharthagupta-hd3sz]

IN question no 2 the quad has to give the first priority rather than pairs{ACCORDING TO THE RULES}

[@sachinkumar_1029]

Yes, that's what I was going to comments🎉

[@knightridergaming1106]

I got 60+/70 in dld bcs of you , while the class avg was 23/70 , PK

[@jonathantony99]

Tq soooo much mammmmm....
U made me perfect in k mapp...
Once again Tqqqq❤

[@TECHNICALD]

f(a,b,c,d) = ∑ (2,4,6,8,12,14)=a'b'cd'+a'bc'd'+a'bcd'+ab'c'd'+abc'd'+abcd' using k-map simplification (Please solve)

[@SourabhKumar-ye9hq]

Solve

[@sachinkumar_1029]

I don't know why you have written that terms after = sign. I have solved the question and it is comming out to be:-
F= BD'+A'CD'+AC'D'

[@Songcookenjoy1548]

Thanks , bohat ache se samjane k liye . Take love 🇧🇩

[@AyushSingh-nm6tq]

Bangali entertainment

[@mohdgulab929]

Bahut achhi video hai ma'am
Bahut hi understandable hai... Easy samjh me aa gyiii...
Thank you sooo much

[@vinita.kushwaha]

Thank you 😌

[@mohdgulab929]

@@vinita.kushwaha bahut achhi video bnati hai aap.. Thanks to hame bolna chahiye... 👍

[@dkvlogerider9278]

Hii Mam million views wala vedio dekhe but samajh me ny aaya but apka wala vedio me bahut jaldi or aache se samjh aaya

[@RiyaPatel-tq9sp]

Exactly

[@dkvlogerider9278]

Yes

[@nanyaar]

10:05 mam if i grouped four incenter i can have 5 equations than 4 it is also correct mam..? If i get 5 rather than 4 clear my doubt

[@aditidump]

this is agood example taken by maam. see in k map ur final goal is to get the most simplified form. toh 4 terms is anyday better than 5 no? there is no need for the group of 4 then

[@yoshitadwivedi9287]

​@@aditidump but we could have grouped 4 in centers and then 4 left at corners that makes one more quad? More simplified?

[@saritathapamagar12]

Best teacher😍🥰

[@NotyourType113]

There's a glitch in 2nd question...we should give priority to quad over pair...5,7,13,15 are easily making a quad... But instead you made 4 pairs first... please rectify the error...

[@filmydissect]

In K-map we should eliminate redundant groups,if all 1's in a group is already involved in other groups that's called redundant groups.We should elimate such groups as it increases number of gates required.So instead of quad group pairing is done.

[@thakurviratsingh4189]

Absolutely right bro

[@infotainment4327]

Helpful video

[@VarshaSingh-b1b]

Thanks mam😊

[@md.alaminrahamanmollick4022]

Thank you so much 🥰 ma'am 😊

[@DhavalParmar3264]

Thank You Very Much

[@TuriHembrom-bo5co]

Thank you mam ❤❤❤

[@blackheart5192]

Mam mene different grouping ki h uska answer v different aya h to konsa sahi hoga ?

[@DANISH_SIDDIQUE]

Same doubt

[@KanchanKashyap-v5r]

Mam acha padhati h aap

[@SrushtiButale]

Amazing mam,🤗

[@Jitendrasinghnayal0808]

Thankiu ma'am ...👍

[@aaryabhardwaj9255]

Thank you ma'am

[@DANISH_SIDDIQUE]

Simplify following expression using K-Map f (A,B,C,D) = ∑m (1,4,7,12,13, 14,15) + d (0, 5, 8)
Please anyone give its equation

[@sabbirandbrothers4536]

Thanks mam

[@savitpandita1993]

I guess 2nd example mein quad group form ho rha hai ?? Isn't it??
5,7,13,15 ??

[@ashwinpanurkar4471]

Quad is not formed in second example

[@AdeshSingh-u1k]

Tq ❤

[@delightedfacts2554]

Good

[@kdaksh1996]

Thank you mam

[@vinita.kushwaha]

Welcome 😄

[@ShoaibMunawer-ip6fx]

Wow

[@ritesh0kushwaha]

Thanks

[@M-S-D-UNIVERSE]

5,7,13,15 us ka quard nahi banay ga ?

[@ishitatomar2325]

Why

[@ishitatomar2325]

Bn toh rha.

[@dataisbeauty5512]

Best

[@dkvlogerider9278]

Y(ABCD)= πM(0 2 8 9 12 13 15) please mam solve kar dejeye na

[@todaytrend_09]

❤❤❤❤❤❤❤❤❤❤

[@LaxmanSingh-z5e9j]

Equau nikalna sikhao dang se

[@RabiaKhan-c6t]

Where is part b plzzz

[@Vedantkharatmol]

😂

[@Vedantkharatmol]

Today internals right?

[@Pupu8wu]

🎉🎉🎉🎉🎉

[@dkvlogerider9278]

Kuch questions solve karwana tha ny kar pa rahe hai

[@Rahulofficial1138]

Ok

[@Rahulofficial1138]

Wp koro

[@skreelscreator5107]

Abe mam to glat bta di

[@2way942]

Open krke dikhaeye

[@JitheshUthaiah]

Thank you so much ma'am 👍🏻😄