You're very welcome, thanks for watching! I've heard that before, perhaps if they ever make an animated version of the show they can save money by hiring me for the voice acting! 😁
Thanks for explanation. Is it possible to not find any outliers in our data?! Because i did a test through this way and i didn’t have any value less than my lower bound and even not value greater than upper bound!
Hey thanks for this! I was just wondering what if the two numbers are the same when calculating the median ? E,g 1,2,3,3,4,5 if the median is still 3 would I still include the other 3s in my first and third quartile ?
Depends on the length of the data list. In your example there is an even number of points, so we split it right down the middle, half the data to the left, half to the right. If the data set is odd, like 1, 2, 3, 3, 3, 4, 5, then we exclude the median, which is 3, and split the data across that median, so our lower half is 1, 2, 3, and our upper half is 3, 4, 5. The third 3, the one actually in the middle, is excluded.
Thank you so much for this clarification! Helped me study for my RS1 progress check.
You're very welcome, I'm glad it helped!
Thank you so much for your SIMPLE AND DETAILED explanation! I understand the topic better now!!
Glad to help!
just too clear, been giving me hard time but after this video, its cool
Awesome, thanks for watching!
Thank you so much! btw I thought this was Sheldon from big bang explaining while watching.
You're very welcome, thanks for watching! I've heard that before, perhaps if they ever make an animated version of the show they can save money by hiring me for the voice acting! 😁
Hey...thanks for the explanation. Could you elaborate on the "1.5"? Any particular reason for this formula?
This was so helpful, Keep up the good work. Thank You.
Glad to help - thank you for watching!
Thanks, I needed this!!!!!!!!
Glad to help, thanks for watching!
Thanks for explanation. Is it possible to not find any outliers in our data?! Because i did a test through this way and i didn’t have any value less than my lower bound and even not value greater than upper bound!
Thanks for watching and absolutely! It's perfectly normal to find no outliers.
Thank you 🙏🏽
My pleasure, thanks for watching!
Hey thanks for this! I was just wondering what if the two numbers are the same when calculating the median ? E,g 1,2,3,3,4,5 if the median is still 3 would I still include the other 3s in my first and third quartile ?
Depends on the length of the data list. In your example there is an even number of points, so we split it right down the middle, half the data to the left, half to the right. If the data set is odd, like 1, 2, 3, 3, 3, 4, 5, then we exclude the median, which is 3, and split the data across that median, so our lower half is 1, 2, 3, and our upper half is 3, 4, 5. The third 3, the one actually in the middle, is excluded.
@@WrathofMath ahhh, fabulous thank you so much !
very helpful tysm!
Glad to hear it, thanks for watching!
when your doing your A-levels and have to come back to the basics
Thanks. However, what happens if I use 1/4(N+1)th value to find Q1, which gives 66 instead of 67? Could you kindly explain?
Hi, this is late but when you get the 3.75th position you can just round up instead of finding a weighted mean.
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