Yes I realise this and the video has been remade some while ago. Many have pointed it out (see below) The remake is here ruclips.net/video/F3WcEAW-M80/видео.html
-Random Guy On The Internet **Teaches Subject In 10 Minutes For Free** -Payed Teacher “Takes An Hour To Overcomplicate Subject For A Hefty Fee” _Isn’t the school system amazing?_
OMFG You are literally the best RUclips Teacher Ever We spent like 3 hours learning this, and I learnt nothing, but with your video it made it soo much easier... Thank you sooooooooooooooooooooooooooo much
I love how you have to side my side problems with an even data set and off data set, you made this so easy, thank you so much for these videos keep up the great work
this was very helpful. my teacher never goes into detail about how to solve these things; she just gives us really complex formulas to plug things into which i think is really unnecessary for a stats class that has no prerequisites
thanks god, finally found someone can really teach maths effectively, in my opinion, a good teacher is the one can really make difficult things turn to easy things ,just like u did, u are one of those good ones . thanks for the helpful video.
Awesome. Thanks. Very clear for my son. He likes that you don't offer peripheral info and that you speak more slowly than many people do, which gives him time to process (he is dyslexic/ADHD). We have subscribed. =)
As a trainee maths teacher, this video is an invaluable guide as to how to help the pupil understand quartiles beyond: here's the formula (n+1)/4 and 3(n+1)/4, this gives you the position of the quartiles, go work out the rest! I never once recall actually learning the quartiles were a sort of median of the lower and upper halves of the data until I actually delved a little deeper when teaching the topic... pretty inexplicable, but true! Thanks for a great video.
is there a difference between how to find the median, quartiles and interquartile range when you have discrete and continuous data, because I was reading somewhere that this affects whether or not you add 1 to n and now I feel unsure when to add it or not?
When finding the upper quartile for the ii you add 3.5 to the median. I'm confused how you got to 16.5 after moving 3.5 places along?? (Wouldn't it have just been 15 because the median was already halfway between 2 values, or have I made a mistake?
TheMysteriousCone what school and state r u in I am also in advanced classes and we learned this and it was so much easier for me to understand than the khan academy video
Explained beautifully... thank you. By the way, I noticed that in the second set of data, when you re-arranged them in ascending order you included 15 even though 15 is not part of the original data set. That 15 is actually supposed to be another 13. So instead of ...12,13,15,18 it should have been ...12,13,13,18.
If you were to take a look at the two data (i and ii), we can see by the IQR that the data in ii) is more dispersed. We can see here how the IQR is preferred to the range. Range is affected by extreme values, but IQR uses medians to calculate it. You can also use the IQR to identify the outliers within each set. Let me demonstrate with i) as an example. The formulas are used: Q1 - 1.5 * IQR Q3 + 1.5 * IQR For example, 5 - 1.5 * 8 = 5 - 12 = -7 Since no data is below this value, there are no low outliers. 18 + 1.5 * 8 = 30 Since there are no values higher than this value, there are no high outliers. The total number of outliers in i) is 0. For ii) Q1 - 1.5 * IQR = 5 - 1.5*11.5 = -12.25 No low outliers here. Q3 + 1.5 * IQR = 16.5 + 17.25 = 33.75 No high outliers here. Neither i) nor ii) has outliers.
Sir. I was stuck on the interquartile question for an hour, searched Google for help but had no idea... and finally, your video saved my life! Thank you so much!!😭
Sir, I think you made mistake, q3 should be (13+18)/2=15.5
Yes I realise this and the video has been remade some while ago. Many have pointed it out (see below) The remake is here ruclips.net/video/F3WcEAW-M80/видео.html
i think he is right
-Random Guy On The Internet **Teaches Subject In 10 Minutes For Free**
-Payed Teacher “Takes An Hour To Overcomplicate Subject For A Hefty Fee”
_Isn’t the school system amazing?_
A two minutes biology video is more intuitive then a two hours biology lesson. So freaking irony XD.
Uploaded 4 years ago and still is helping me
Yup,it helped me to understand better too actually.
Uploaded 9 years ago and still helping
OMFG You are literally the best RUclips Teacher Ever
We spent like 3 hours learning this, and I learnt nothing, but with your video it made it soo much easier...
Thank you sooooooooooooooooooooooooooo much
Not all super heroes wear capes
so true
Damn 4 years ago
Which grade r u
This is why I love studying on RUclips...so much more efficient than a lecture.
I love how you have to side my side problems with an even data set and off data set, you made this so easy, thank you so much for these videos keep up the great work
this was very helpful. my teacher never goes into detail about how to solve these things; she just gives us really complex formulas to plug things into which i think is really unnecessary for a stats class that has no prerequisites
thanks god, finally found someone can really teach maths effectively, in my opinion, a good teacher is the one can really make difficult things turn to easy things ,just like u did, u are one of those good ones .
thanks for the helpful video.
Awesome. Thanks. Very clear for my son. He likes that you don't offer peripheral info and that you speak more slowly than many people do, which gives him time to process (he is dyslexic/ADHD). We have subscribed. =)
such dicc
Thanks for that as this causes so much confusion amongst students.
stuck on some homework this really helped much better than other maths channels, subscribed.
Awesome tutorial, reminded me of my Stat Prof's way of discussion! Very informative, thanks a lot!
The number of values (observations) in the list above where I wrote this.
Uploaded 8 years ago but still helping me!!
As a trainee maths teacher, this video is an invaluable guide as to how to help the pupil understand quartiles beyond: here's the formula (n+1)/4 and 3(n+1)/4, this gives you the position of the quartiles, go work out the rest! I never once recall actually learning the quartiles were a sort of median of the lower and upper halves of the data until I actually delved a little deeper when teaching the topic... pretty inexplicable, but true! Thanks for a great video.
is there a difference between how to find the median, quartiles and interquartile range when you have discrete and continuous data, because I was reading somewhere that this affects whether or not you add 1 to n and now I feel unsure when to add it or not?
Can i take credit for this video?
When finding the upper quartile for the ii you add 3.5 to the median. I'm confused how you got to 16.5 after moving 3.5 places along?? (Wouldn't it have just been 15 because the median was already halfway between 2 values, or have I made a mistake?
Extremely helpful.
You are awesome. You made it super easy to understand. Thank you
I know i am
Thank you so much. Keep up the good work. You just made everything a 10000 times easier.
Awesome video! Thank You!
thank you so so much! this has been so much help!
so neat and easy to understand, thank you so much!!!!
Thank you that was super helpful!!!!!
Your video really helped me, thank you sooo much!
One of the better explanations of this concept thank you!!!
Your video made it easy to understand the methods of Median, quartiles, and interquartiles. I want to thank you so very, very much.
thank u so vry much sir...you jst made my day in statistics 116....great help...GOD BLESS U
Pleased to hear it helped. Thanks for your comment.
Thank you for the help!
Thanks alot for the help. Its easier and a more straight forward way of working it out
these made me pass my qm test thanx
Thank you so much !
My 6th grade teacher made everybody watch the video and you made the stuff she was teaching so much easier thanks
TheMysteriousCone Like it!
***** it was advanced math
TheMysteriousCone what school and state r u in I am also in advanced classes and we learned this and it was so much easier for me to understand than the khan academy video
Gaming Tube I can't say school but I live in florida
I live in massachusetts
Thanks for this, it's a huge help!
thank you ! helped so much !
Thank you
Brilliant work!
I actually found this better than the formula given in the video because it doesn't require you to find the median first. Thanks!
Thanks
There are videos on this on my website and app. Just look under median for grouped data
Excellent job, thank you very much.
life saver..u are an amazing human being....thanks for ur help!
Thank you so much for this explanation.
thank you so much for you lectures they are really helpful
this was explained very well ,thank you
great help mate :))
this is too informative...thanks a lot sir
Thank you so much!! You make it comprihensible!
Thank you very much this helps me alot
Thank you, had been trying to work it out by myself for hours! Really effective teaching :)
Glad you have it sorted. Best wishes.
Excellent explanation!
THANKS FOR THIS GREAT VIDEO IT REAALLYY HELPED! :D
Great video! Can you discuss the interquartile range and identifying outliers?
Thanks for posting this educating film
man you saved my life too!! thank a lot
very simple explanation , everyone can easily understand , thank you so much, its really helpfull.
very nice!thank you
exam solutions makes maths really easy thanks'!!
thanks so much
really useful
Great ! You make everything seem do easy thank you sooo much !
You're welcome. Thanks for any support you can give.
What is the range of ideal classes for ungrouped data.
Thank you so much dear
Yes
Excellent .... it helped me
May God bless you ...
Explained beautifully... thank you. By the way, I noticed that in the second set of data, when you re-arranged them in ascending order you included 15 even though 15 is not part of the original data set. That 15 is actually supposed to be another 13. So instead of ...12,13,15,18 it should have been ...12,13,13,18.
Thank you so much. You are the best :)
Thank you very much.. Helpful video clip 👍👍
Good to hear it helped. Thanks for watching.
tnx , very clear teaching
helped me a lot!!
quite helpful
thanks
Thanks a lot.
If you were to take a look at the two data (i and ii), we can see by the IQR that the data in ii) is more dispersed. We can see here how the IQR is preferred to the range. Range is affected by extreme values, but IQR uses medians to calculate it.
You can also use the IQR to identify the outliers within each set. Let me demonstrate with i) as an example.
The formulas are used:
Q1 - 1.5 * IQR
Q3 + 1.5 * IQR
For example,
5 - 1.5 * 8 = 5 - 12 = -7 Since no data is below this value, there are no low outliers.
18 + 1.5 * 8 = 30 Since there are no values higher than this value, there are no high outliers.
The total number of outliers in i) is 0.
For ii)
Q1 - 1.5 * IQR = 5 - 1.5*11.5 = -12.25 No low outliers here.
Q3 + 1.5 * IQR = 16.5 + 17.25 = 33.75 No high outliers here.
Neither i) nor ii) has outliers.
Its really helpful. I am doing a module called Business statistics. Thank you so much.
Hey, it helps me A LOT! Thank you so much, now I can hopefully pass my test, haha!
Very impressed with this video helped a lot 👍
THANK YOU!!!
My pleasure
You just saved my life!
thanks :)
Not in this video but I have discussed it in others that you will see on my website
Sir. I was stuck on the interquartile question for an hour, searched Google for help but had no idea... and finally, your video saved my life! Thank you so much!!😭
I am glad to have been of service. I hope others will help out too in times of need. Best wishes.
thanks for the video
This video pretty helpful
Great video helped me uderstand beter
U are great
Tnx It's very clear and easy method but there are many methods to answered interquartile range
Thank you sir, very helpful :)
You're welcome
This video was remade and is on my website. You must be looking at the old one.
Thanks! That really helped
+Im BerrryBug Good
literal life saver this confused me so much and my jc p2 is tomorrow morning
Hope it went well.
Thank you so much sir
thanks .. really easy to understand
Thanks and thanks for watching
wonderful learning video
Awesome. Very good explanation
Huge shout out from brazil
thank you so much
ok thanks, so in general it's almost always exactly between value x and y not a quarter, or any other fraction, right?
Thank you so much. Great help :)
Thanks
mah man examsolution XD much more helpful than my stat teacher
Thank you so much
To find the lower quartile i prefer to divide n by four to save any unnecessary calculations.
yea, it works for odd numbers but for even numbers not very well.