An easier way is to use the Vy formula to find "t". When Vy=0 you have reached the highest point in the parabola. That "t" represents the time it takes the projectile to reach its peak. t=2.58s you multiply "t" 2 because the peak always occurs halfway. (t/2). This way is easier than start doing all these calculations.
@@ShareInfos516 No, 281 would be wrong. Remember, the object isn't projected from the same elevation so it's not gonna hit the ground at 20m above the ground (datum). The method suggested may be easier if projected from the same level ground. In this case, if you want to use that, then you'd have to account for the x distance it travels below the 20m mark. So the solution given in the video is correct. and that method is better because it works all the time.
Good Afternoon, I noticed in the Lindeburg practice problems there was a few examples similar to the one shown in this video. In the solutions to the Lindeburg examples they multiply t by 2 because when solving for t you find the time to the apex of the projectile. Why did you not multiple t by 2?
Yes, this is the predicament that I am in right now. In the FE Practice Review Practice problems, they multiply the time (t) by 2 since the first t was shown to be the time it takes the object to get to the halfway point, or the apex??
Firstly, you've earned a new subscriber :) Secondly, have you tested the Casio Classwizz FX-991EX. I have also noticed that TI calcs are more popular in USA. Cheers from Montenegro! :)
@@Genieprep Thank you for your solutions and yes, for the FE, I recommend the casino fx-115ES plus (same as the 991Ex outside US) over TI 36X pro. That is if one is familiar with both. If they're used to TI 36X, they're better off sticking to that.
Hello, thank you for watching! So you can find the equations on the FE reference handbook by the NCEES, you can download it for free after you log in at account.ncees.org/login.
Can I submit a question I’m having a hard time with in dynamics I’ve been 5 years out of school and I never actually took dynamics so it’s a bit confusing
Hello John, you can email me at engenieeronline@gmail.com and I will help you on how to study for the FE exam and I will also try to help you with your dynamics question. I have helped many clients pass their FE exam and they were out of school for 10-15 years. Being out of school 5 years should not be a problem, you just need to study smart and you will pass this exam. Good luck with your studying!
That is really good question and I am really glad you brought it up. It is also a very common mistake. Vy = 0 usually at the peak of the projectile, because the kinetic energy (KE = 1/2mv^2) gets converted to gravitational energy, so V= 0 at your highest point. Also your final velocity is not zero, the projectile will land with a velocity.
An easier way is to use the Vy formula to find "t". When Vy=0 you have reached the highest point in the parabola. That "t" represents the time it takes the projectile to reach its peak. t=2.58s you multiply "t" 2 because the peak always occurs halfway. (t/2). This way is easier than start doing all these calculations.
Yes, the answer should be 281m
@@ShareInfos516 No, 281 would be wrong. Remember, the object isn't projected from the same elevation so it's not gonna hit the ground at 20m above the ground (datum). The method suggested may be easier if projected from the same level ground. In this case, if you want to use that, then you'd have to account for the x distance it travels below the 20m mark. So the solution given in the video is correct. and that method is better because it works all the time.
You’re always doing a great job
Thank you! Good luck with your studying!
You had me at bonjour. Lol great video, very helpful
Enjoy your videos....keep them coming!
Great example thanks
Good Afternoon,
I noticed in the Lindeburg practice problems there was a few examples similar to the one shown in this video. In the solutions to the Lindeburg examples they multiply t by 2 because when solving for t you find the time to the apex of the projectile. Why did you not multiple t by 2?
Yes, this is the predicament that I am in right now. In the FE Practice Review Practice problems, they multiply the time (t) by 2 since the first t was shown to be the time it takes the object to get to the halfway point, or the apex??
@@JoJustCreate That only applies for the special case where it lands at the same elevation it launches.
Firstly, you've earned a new subscriber :)
Secondly, have you tested the Casio Classwizz FX-991EX. I have also noticed that TI calcs are more popular in USA. Cheers from Montenegro! :)
Thank you and no I never really used Casio Classwizz FX-991EX, do you recommend it over TI?
@@Genieprep Thank you for your solutions and yes, for the FE, I recommend the casino fx-115ES plus (same as the 991Ex outside US) over TI 36X pro. That is if one is familiar with both. If they're used to TI 36X, they're better off sticking to that.
How can I get that formula sheet. It looks well put together.
Hello, thank you for watching! So you can find the equations on the FE reference handbook by the NCEES, you can download it for free after you log in at account.ncees.org/login.
@@Genieprep not working
@@theconversation5574 Please email at hello@engenieer.com and we will send you how to access the reference handbook.
Can I submit a question I’m having a hard time with in dynamics I’ve been 5 years out of school and I never actually took dynamics so it’s a bit confusing
Hello John, you can email me at engenieeronline@gmail.com and I will help you on how to study for the FE exam and I will also try to help you with your dynamics question. I have helped many clients pass their FE exam and they were out of school for 10-15 years. Being out of school 5 years should not be a problem, you just need to study smart and you will pass this exam. Good luck with your studying!
Great videos. Thank you.
You're welcome! Happy to help 😊
I didn’t see the second part 😢
Hello Mohammed, I have actually posted it on Patreon, here is the link in case you want to check it out, www.patreon.com/engenieer. Thank you!
Thanks a lot
@@mohmmedallaz No problem!
why cant we initially use final velocity of Y to be zero and solve for the time ????
That is really good question and I am really glad you brought it up. It is also a very common mistake. Vy = 0 usually at the peak of the projectile, because the kinetic energy (KE = 1/2mv^2) gets converted to gravitational energy, so V= 0 at your highest point. Also your final velocity is not zero, the projectile will land with a velocity.