Calculus 1: Max-Min Problems (24 of 30) Maximum Profit

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In this video I will find maximum profit given x(p)=100-p and C(x)=3000+20x.
Next video in this series can be seen at:
• Calculus 1: Max-Min Pr...

[@ugborjifymba5171]

I don't understand

[@MichelvanBiezen]

It may help to watch the videos from the beginning of the playlist (This is # 24 in the playlist).

[@supersonik76]

whoa sir, so clearly explained, thanks so much.

[@MichelvanBiezen]

You are most welcome

[@ugborjifymba5171]

What's R(x)

[@MichelvanBiezen]

R = revenue C = cost P = profit P = R - C

[@mabbasi6793]

nicely explained sir...helped me a lot completing my assignment

[@MichelvanBiezen]

Happy to help

[@kenziemiddleton7999]

how did you get the -2x + 90?

[@MichelvanBiezen]

It is the derivative of " -x^2 + 980x - 3000"