You can never go wrong with Master T Maths Class. I think Master T needs to have a book titled Step by Step Solution to solving Problems in Logarithms and Indices. A have a similar book I hope to share with Master T when I get his contact details. Master T is a CLASS ACT. BRAVO Sir !!! You are so good and what I admire most about your lecture is most is when we are checking whether our answer in right. Any good tutorials. Times spent listening to You is time well spent Sir !!!
You can never go wrong with Master T Maths Class. I think Master T needs to have a book titled Step by Step Solution to solving Problems in Logarithms and Indices. A have a similar book I hope to share with Master T when I get his contact details. Master T is a CLASS ACT. BRAVO Sir !!! You are so good and what I admire most about your lecture is most is when we are checking whether our answer in right. Any good tutorials. Times spent listening to You is time well spent Sir !!!
8^(Log[8,1.230769 recurring ]+2)+8^Log[8,1.230769 recurring ]=80 Input interpretation
8^(log(8, 1.(230769)^_ (repeating decimal)) + 2) + 8^log(8, 1.(230769)^_ (repeating decimal)) = 80 x=(4-Log[2,13])/3=Log[8,16/13]
Result
True
8x + 16 + 8x = 80
16x = 80 - 16
16x = 64
x = log 64 /log 16
x = 1.5
16^1.5 = 64
✌️
Записан ответ и обведён в рамку.... А где же 2 из знаменателя под логарифмом?
brooo😭
8^x(8²+1)=80
8^x=16/13
x=(log16-log13)/log8=(4log2-log13)/3log2=4/3-log13/3log2
Find log13:
log12=2log2+log3
log14=log2+log7
log13≈(log12+log14)/2≈(3log2+log3+log7)/2
So x≈4/3-(3log2+log3+log7)/6log2≈4/3-½-(log3+log7)/6log2≈⅚-(log3+log7)/6log2
x≈⅚-(0.477+0.845)/(6×0.301)≈⅚-661/903≈(5×903-6×661)/(6×903)≈183/1806≈0.1
8^(0.1+2)+8^0.1≈80.02