Solving Systems of Equations With 3 Variables & Word Problems
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- Опубликовано: 10 сен 2024
- This algebra video tutorial explains how to solve system of equations with 3 variables and with word problems. It contains two example word problems on investment and on total value.
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Systems of Linear Equations - 3 Variables:
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Systems of Equations - Word Problems:
• Algebra 2 Math Problem
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Systems of Nonlinear Equations:
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hell yeah
@@fabianousim6716 yeah bro this dude is insane
exactly👍
@@afifmasian7685 sometimes we need a best tcer to teach maths
Factual
Recently went back to university for a new degree. First time I've been in classes in about ten years. Algebra and trig are absolutely killing me as I'm realising how utterly weak my foundations are in most maths at the moment. Your channel has been amazing to help me relearn and catch up on things. I'm still far behind, but you definitely help relax some of that stress. I will always smash that like button.
Hope you’re doing well because I’m taking AP Calculus BC. Ext year as a sophomore
I was in the same boat. 12 years since I had taken a math class and jumped into pre calculus algebra. Just keep trying and don't give up. If you fail a class take it again and consider it a learning experience. In a year you will be amazed how much you have learned and what you can do.
I am in the same boat lol, these videos are bangers.
Honestly, I have never seen equation systems solved in this way. At my school we always isolate the first variable, so it can be but into the next equation, to solve the next variable so it can be put into the last: so you'll end up with an equation with only 1 variable. Therefore this is mindblowing to me. Thank you!
this ia elimination method suitable for some equations...
I learned this originally for Algebra 2 but now 4 years later I need it for linear algebra. Thanks for the video!
Bro made short maths explanation videos I actually understand (yes, I'm the dumbest one in class), instead of watching tiktok or RUclips shorts I started watching this guy's videos because it made me feel smart and now I basically caught up with all math I lost during the years due to poor explanation. Thank you sir, I mean it
You’re not the only one here lol
for me i think it is not due to poor explanation on why us are having a hard time learn a math like this. i think because of we cannot repeat our teacher explanation just like what we do in this video. repeat again and again until we get it.
Wish me luck for my final exam❤
Thank you so much. I've been struggling for 5 days LITERALLY. your video made me a pro with this ☺️
MR. Organic Chemistry Tutor, thank you for another great video/lecture on Solving Systems of Equations.
this guy does a better explanation than my uni lin alg textbook ever did
Do some word problems using 3 variables...
I guess I am kind of off topic but does anybody know of a good site to watch new movies online ?
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@@andreclay9324 very off topic
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Thanks! This video really helped me with a question on my math final!
same
Thanks ❤❤
Hopefully this video can help me with algebra 2 this year
Honestly, you've helped me a lot, thank you tutor
This video just saved my hope for better grades. Keep it up
I'm in 3rd and going to kumon and I LOVE your videos, you helped me with level G.
Learning linear algebra, forgot about systems of equation so this helps!
I was watching a video, made by my school, which explained this topic... it was not helpful. After a bit of searching, I found this video and now I understand how to solve a system of equations with 3 variables in it. Thank you.
Thank you for this! My teacher speaks and works really fast and it’s hard to catch it all, so I really needed this :)
I love this guy, always helps
how about this problem:
(pls help me out)
There are three types of vehicles, one is the motorcycle, tricycle, and van. the next day, there are 36 vehicles made a trip, but were not able to count the number of each vehicle. If you saw 102 wheels, how many motorcycle, tricycle, and van made a trip? Considering that motorcycle has 2 wheels, tricycle has 3, and van has 4 wheels.
1 - Spend one second
looking at the exercise.
2 - write it wrong.
3 - spent houres trying different increasingly complex methods to solve an impossible equation.
Always really helpful when I forgot or when I just learned a formula, thank you kind sir
you’re literally the best
You are the best teacher I've ever seen even my lectures don't explain like you..... we appreciate your assistance, may God bless you with more wisdom and knowledge.......❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Super simple, easy to understand
my math teacher doesnt teach us and this helped me tremendously on a quiz that we had. Amazing!!!!!!!!!!!!!
dude always helps me out but his voice is so soothing holy shit
Bro this guy teaches me more than my teacher and helps me more than my parents
thanks dude, you just saved my grade and I even speak diff language
My ONLY problem with this video is how he solved the first equation. I have on my paper a problem that can’t be solved with that second equation multiplication, so I need to have a different set of steps to complete it. This video only does something you can do in a specific group of situations, and doesn’t help when the 3 variable system of equations isn’t able to do that last elimination that you did. It would help many people to see how else you can solve a system without that last shortcut.
Wow please slow it down!!!!!!! Blew my mind
But why do you need to get rid of the y and why do you need to multiply one of the resulting equations by -1?
You have to get rid of one variable, in this case Y was just easier
And he multiplied following equations by -1 so they could subtract eachother rather than just add
Hope this helped
@@Mlmylji but why not -2 or -3
@@footballomegabecause it would not compute together I think( I am just a kid 😅)
Like if u did this (4x+3z=13)-2
(5x+3z=14)
It would come out like this
-8x-6z=-26
+ 5x +3z=14
--------
-3x-6z=-12
And so it would not have been able to subtract anything or delete any variable@footballomega
I was referred here by your electronics playlist. A really great explanation!
Why do you have to multiply the first equation by two and the one next to it by -1?
its still works if you didnt multiply em
The reason you have to multiply the first equation by 2 is so the Y’s cancel out. At first you’ll see that the first equation has y and the 3rd has -2y. Since we’re trying to cancel them out they have to have the same value with opposite signs, which would be 2y and -2y. After you multiply the 1st equation by two now the 1st equation has 2y, the 2nd equation still has -2y so they cancel out when you add. You would pretty much follow the same logic for the one that gets multiplied by -1, it’s to make it so one of the variables gets canceled out. Also, incase you were confused on this multiplying the whole thing doesn’t matter because it can still be divided by that same value to get the original equation. I hope this helped! :)
so you can just add the equations instead of subtracting them because subtracting isn't always accurate
“A, B, and C have 2150 yen collectively. A has 120 yen more than B does. After C gives B 2/5ths of his money, B now has 220 yen more than A. How much money did A originally have?”
They say it's a problem that even middle schoolers can solve, but wow. Maybe I'm just dumb. I can't figure anything out.
(B+120) + B + C = 2150
An + (B+2/5C) + 3/5C = 2150
?
A = 710
B = 590
C = 850
A originally had 710 yen. The A, B, and C values are all BEFORE they gave money to each other.
I was able to gather the following equations from this problem.
A + B + C = 2150
A = B + 120
(2/5) C + B = A + 220
Now I will replace "A" with "B + 120".
(B + 120) + B + C = 2150
(2/5)C + B = B + 120 + 220
In the second equation, it looks like I can solve C since the B's cancel each other out.
(2/5)C + B = B + 120 + 220
(2/5)C = 340
C = 850
Using C, I can solve for B in the first equation.
(B + 120) + B + 850 = 2150
2B = 1180
B = 590
Now, I can use the very first equation I wrote and solve for A.
A + 850 + 590 = 2150
A = 710
I can now use the three original equations and check my work.
710 + 590 + 850 = 2150
710 = 590 + 120
(2/5)850 + 590 = 710 + 220
The above statements are true.
Unless you find that my original equations are incorrect, this is one way to solve.
To be fair in canada we don't do any of this till 9th or 10th but I just like being ahead
As simple and understanding as always, thank you very much.
2:39 why did u multiply by -1
So he multiplied by -1 because he want to do it more simpler so he can do it and also because subtracting is kind of confusing when you have a negative stacked on top of each other you can accidentally miss the sign and that will ruin the whole thing.
Example: 2x+y=7
11x+2y=20
------
2x+y=7(2)
11x+2y=20 -
------
4x+2y=14
11x+2y=20 -
--------
7x=7
x=1 ( I know this is wrong because the x is supposed to be negative because 4-11=-7)
So we sub the x=1 into prob 1
2+y=7
----
y=7-2
----
y=5
BUT if we do it the right way where x is equal to -1
2x+y=7
----
-2+y=7
----
y=7+2
----
Y=9
As you can see if we get the signs wrong on the first one that you solve it will become wrong for the entire thing
This took like 20 minutes
How do ypu do it if there is only 2 equations?
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My problem is I don’t understand how your getting negative numbers to divide the equations by (5A+8b=6.55)(-7)
9a+7b=9.20 where does the -7 come from does it come from reversing the 7b?
I'm here again. Thanks for sharing it with us
common the coefficients in order to compare and calculate
Thank you so much!
Thank you so much for your help!
As always, thank u!
Please help me sir a+b-c=-1...(1)
2a-2b+3c=8..... (2)
2a-b+2c=9..... (3)
Did you ever find the answers though
@@shanegilliam4896 I see someone else has a bad teacher this year
@@endgameisbad2733 lmao yup
@@shanegilliam4896 it do be like that sometimes
a=2, b=-1, c =2
Why do you multiply by -1 and 2?
But what can you do if the factors of the variables aren't constants so you can't cancel. For example:
x*sin a + y *sin b + z*sin c = 0
x*cos a + y*cos b + z*cos c =0
x*sin a * 2l + y*cos b * 3l + z* sin c * 4l = 0
Thanks for this video it helped sooo much
Thanks It helped me a lot
Whenever you hear this voice, just know that you are in the right place 🍻
you are amazing bro keep up the amazing work
You the best 👍
I got a math test in one hour, at 3:30 why do I multiply 5 by one?
your calculator sounds great😋😋😋😋
you're awesome!
Best math guy
nice explanation keep it up bro
THANK FOR HELP ME NOT FAIL ALGEBRA
Ok but you’re gonna fail English lol
you are good bro
THANK YOU
THANKS MY FRIEND
Very helpful!☺
Thank you sir, you really saved me😂
youre always the man
For the first one, I would assume that x=1, y=2, and z=3!?
I should not have taken college algebra before learning this stuff why didn’t anyone warn me i was told it was easier than algebra 1😭😭😭
Thank you 😊
Thank you
teacher i want more of these
I DONT UNDERSTAND, HOW ARE THE TWO NEW EQUATIONS GOING TO MAGICALLY CANCEL EACHOTHER OUT
you multiply one equation by a certain number to make a specific variable cancel out, like if one equation was : 2x+3y+2z = 25 : and the second equation was : 5x+7y-z = 25 : and you wanted z to cancel out, you multiply the entire second equation by 2 so -z could turn into -2z which cancels out the first equation's z which is positive 2z
@@ak09168 THANK YOU 🙏🏽
This is Top G status teaching. Keep it up!
Is this substitution or elimination?
his voice is still mesmerising
This does not work with equations ending with the same value
love you
How to know u need to + or - during counting??
I LOVE YOU THANK YOU 🙏🙏🙏🙏
Is this elimination by substitution?
What if the my 3rd equation is 0y I can’t cancel it out bc it’s 2y and 0y 😅 stressing out
use Cramer's Rule!
But why multiplied by two? Is there a reason
US education system never heard of Gauss? Just do the Gauß-Jordan algorithm, way easier and way way faster than this technique.
literally
Or heck just go with 1/|a|*adj(a) for a amtrix.
hi just need to know where the -1 came from
U need to add when u sub it is not so easy
At 1:45, why did you choose 2? It wasn't explained.
He used the third equation and he had to multiply by to so he could cancel z out
Where did you get -1 from ?
to cancel out 3z
Thanks m8
1:42. How do you know when you need to multiply by 2?
When the variables do not have the correct number to cancel out prob
Pretty sure im a bit late, but it is because you would need to have two equations with only two variables to make this work, and he had chosen Y to be taken out, and the top equations Y was 1/2 of the third equations Y so to make them the same value so they cancel out, you have to multiply the whole top equation by 2 so when you add the first and third equations, the Y cancels out
x + y + z = 6
x + -2y + 3z = 1
x + 3y + -z = 8
ANS: X,Y,Z (1,3,2) Is my answer correct?
Yes u are correct
Probs from kumon math area
I'm doing this online bc my fucking teacher decided not to finish her lesson on time and now I'm doing this
how do you know which number to multiply with
The number is your choice, kind of. The goal of using a constant is to be able to add two variables together and have one of them cancel each other out, for example:
2y+3z=4
4y+2z=3
we want a 2y to become a number where it would cancel out 4y, therefore we multiply by a constant of -2 giving us:
-4y-6z=-8
+ 4y+2z=3
------------------
-4z=5
hope this helped, if you have any more questions feel free to reply!
I love U
be honest we’re all sophomores here struggling with algebra 2
Doing this in ninth grade is a movie
???? huh?
What do you mean by movie? Nate??
Hello and welcome to whoever is taking electrical circuits and saying “I should’ve actually studied this well in high school” 💀
GOD BLESS
Sir please strat lectures on general aptitude
#lifesaver
The matrix method? 😢