it's because (kgms^-2) is entirely multiplied by 'p' but let's say hypothetically, if it was s^-2+p, where p=1/2, (S) would end up being -1.5 considering (-2+1/2 = -1.5) and we need our S to be equal to (s^-1). While, s^-2p would mean (where p is equal to 1/2) s^-1 as (2 x 1/2 = 1) and that's pretty much how indices work
God bless you. You've just ended hours of confusion and mayhem in my brain.
youre saving my life , please continue these series
Im reappearing for AS this oct/nov you're a huge help thank you
thank you both sm if i pass itll be cos of u guys
Thank you Soo much I couldn't understand this topic you helped a lot
Thanks u very much for your lesson
Great explanations. Thanks so much
please do maths as well your explanations are helpful
Thanks. That was so helpful.
I fw miss Ellie hard🔥🔥
miss lee cold too
@@iamlost2967 frfr
Could you please explain me the point at 3:50. What does validity here refer to ? Does this mean that the equation mentioned is invalid ?
Thank you miss
W video
10:38
Umm why was s^-2p? Wouldn't it be s^-2+p
it's because (kgms^-2) is entirely multiplied by 'p' but let's say hypothetically, if it was s^-2+p, where p=1/2, (S) would end up being -1.5 considering (-2+1/2 = -1.5) and we need our S to be equal to (s^-1).
While, s^-2p would mean (where p is equal to 1/2) s^-1 as (2 x 1/2 = 1) and that's pretty much how indices work
brother asked a very good question and the sister answered beautifully
Guys after this if we fail we have a problem 😅