A Very Nice Math Olympiad Problem | Solve for x | Algebra

In this video, I'll be showing you step by step on how to solve this Olympiad Maths Exponential problem using a simple trick.
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[@organicfarmingapproachs9843]

Thank you for your clear explanation

[@SpencersAcademy]

You are welcome! I'm glad it was helpful 😊

[@PrithwirajSen-nj6qq]

9^(x +1) -9^(x -1)=20
> 9^x(9 -1/9)=20
>9^x = 20*9/80=9/4=(3/2)^2
>( 3^x)^2=(3/2)^2
>3^x =3/2
Take log
x log 3 = log 3 -log 2
> x = 1-log2/log3
=1-0.3010 /0.4771
=1- 0.6308 =0.3692(approx)
=

[@SpencersAcademy]

Great job 👏

[@RealQinnMalloryu4]

9^{x+x ➖}{ 1+1 ➖} ➖ 9(x)^2 ➖ (1)^2=9^{x^2+2} ➖ 9^{x^2 ➖ 1}=9^2x^2 ➖ 9^{x^0+x^0 ➖ }=9^2x^2 ➖ 9^x^1={18x^2 ➖ 9x}=9'^2 3^2x^2 1^1x^2 1x^2 (x ➖ 2x+1).

[@charlottesphie7037]

Yikes log ..

[@AliEzadkhaha]

9^x=a=> 9a-a/9=20=>a(9-1/9)=20=>a=20/(80/9)=9/4=>9^x=9/4=>x=ln(9/4)/ln(9)=0.36907024642

[@PrithwirajSen-nj6qq]

Enjoyed