Thank you sir! 💌❤ Ans is a)3013 LCM = 504 Then we will try the values from 1-9 in the form of 504*k-11/23 Subsituting k=6 we will get 504*6-11/23 i.e 3024-11/23 here we get remainder 0 so the number is 3013.
LCM = 504 and difference btw divisor and remainder are: 11...lcm-diff/23...504-11/23 put the least value of k which is completely div of 23 .. 504k-11/23...Put k=1=>504-11/23=493/23(the value is not divisible of 23)...Put k=2=>504(2)-11/23=>1008-11/23=>997/23(not completely divisible of 23).. Put k=3,4,5....They are not completely divisible of 23... Put k=6=>504*6-11/23=>3024-11/23=>3013/23 is completely divisible of 23, So Option No1=>3013
Sir, Today is GURU PURNIMA (21/7/24) and I would like to Thank you so much for always motivating and teaching us even when you are not well. Hopefully I'll meet you soon whenever I'll get chance ❤❤ One of the most amazing teachers I have met and learning from, THANK YOU❤😊🙏
Thank you sir You super teacher sir u put great effort Sir your effort our strength Sir I always better learn your lecture But sir if you teach on the condition of illness and why I can't study on that condition Thanks for motivation
In LCM as I noticed, sir is adding the remainders to the Ans when the question says ' in each case leave the same remainder ' and subtracts the remainder when in the number leaves different remainders...….please correct if wrong...was confused with it earlier
Sir LCM vale questions me aap kahi remainder ke subtract kr rhe hain aur kahi add kr rhe hain exactly ye btaiye ki kaha pe add krna hai aur kaha pe subtract krna hai????
Sir, I have observed that your health is not good since very long, please consult with physician. Your good health will lead to benefit of students like us. Get well soon sir. Thank you for your valuable lessons.
in que ni 5 after dividion of 300 with 225, remainder is 75 so we have to didvide with 225 you mistakenly divided by 300. kindly check thoiugh it doest change the anser but makes mistake in steps
504 aaaya lcm then 18 se 7 gya =11 21-10=11 24-13=11 Ok ok ok now Jaise sir ne kaha ki k ki value rahni hai to 6 rkh lo ok 504×6 -11÷23 =0 3024-11 = 3013 aaega mtlb 23 se poora katega ❤❤❤❤❤❤
This series is literally a life saver. Thank you for doing this❤ However, I have a doubt. Sir, in Q6, you added the remainder to the LCM but in the next one, you subtracted it. Is it a mistake or am I missing something? Kindly clarify, thank you!
One thing that I noticed, When remainder is more than one, sir has has subtracted the difference, but when the remainder is same for all, then sir has added the remainder.
Hey an aspirant this side. Wanted to ask you that can i completely depend on this initiative for Csat because there are lot of online courses in the name csat initiative and most of them fall apart after few lectures. So would you suggest me to go through his videos? And I'm asking this to you because it seems that you have watched the same. Thank you.
Disclaimer " dono question me ye trick satisfy hua " I found that , agr multiple of x ko options se divide kre th Jo least no. Completely divisible h wahi answer aarha h Eg, 2nd last question 7÷ options -> 728 & 364 both divisible but 364 is least so answer is 364 Same in last question also
This is the best course for CSAT, and the commitment Sir has for his students cannot be thanked in words. Get well soon Sir
Thank you sir! 💌❤
Ans is a)3013
LCM = 504
Then we will try the values from 1-9 in the form of 504*k-11/23
Subsituting k=6 we will get 504*6-11/23 i.e 3024-11/23 here we get remainder 0 so the number is 3013.
504*k+11/23?
@@rsdogra159511 is the difference between the divisor and remainder that will be subtracted.
@@Chikky0706 , in previously same question addition is done by master...?
@@rsdogra1595 In previous question only 1 remainder is given.
@@Chikky0706 thankyou
LCM = 504 and difference btw divisor and remainder are: 11...lcm-diff/23...504-11/23 put the least value of k which is completely div of 23 .. 504k-11/23...Put k=1=>504-11/23=493/23(the value is not divisible of 23)...Put k=2=>504(2)-11/23=>1008-11/23=>997/23(not completely divisible of 23).. Put k=3,4,5....They are not completely divisible of 23... Put k=6=>504*6-11/23=>3024-11/23=>3013/23 is completely divisible of 23, So Option No1=>3013
Why you minus 11 from from LCM
..in previous question sir add LCM*k with remainder.....
@@soniyalashkan8637 because here there are multiple remainders so you have to take their difference
Right 👍👍👍👍👍❤❤❤❤❤
Best video
3013
You have indeed simplified the maths portion of CSAT thus far. Thank You for all your efforts Sir!
Sir your hard work, commitment, dedication, humbleness ..I learn a lot from you
Sir, Today is GURU PURNIMA (21/7/24) and I would like to Thank you so much for always motivating and teaching us even when you are not well. Hopefully I'll meet you soon whenever I'll get chance ❤❤
One of the most amazing teachers I have met and learning from, THANK YOU❤😊🙏
Apki vedios RUclips se chali gyi thi mai dar gyi thi ki csat kese hoga thank you again sir 😊
One of these best teacher for csat
Ur course help me to clear three time csat in state PSCs ❤
Get well soon, Sir. Because of you, we are gaining confidence. Thank You, so much.
u r humble sir....always take care of ur health
H.w. ans 3013....... Respected sir please don't delete the content... Your videos/methods are very helpful for us ❤
Sir please do not delete these videos.I have started watching these amazing content.
Thanku sir app bahut aacha padate ho
Option a is the answer 🎉 thank you sir for explaining with such precision
Very very splendid lecture...thank you sir
Home work ans 3013
Thank you sir!
Very nice sirji
Bahut acche se example ke saath explain Kiya
Thank you so much sirji
tq for providing such quality information free of cost
Home work answer
Option (a) ;3013
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how
Thank you sir.... Waiting for your next video.... From KURNOOL
Answer a) 3013
Thank you sir🎉
Thank you so much sir...Stay blessed always..
Thanku so much sir... 🙏🙏🙏🙏
Option a is correct ✅✅✅✅
We can check the opt like
3002+11(diff of divisor and remainder) divided by 23
very nice class sir I regularly seee your videos
Question 10 answer option a 3013 32:58
Thank u sir for this valueable session
india's best course on CSAT
thank you sir.........aap hamesha khush raho aur healthy raho🙏
Get well soon sir 🙏
Thank you so much sir🙏
You may get well soon sir…God bless you ..your efforts are always commendable
Guruji kamal ho app ❤❤👏👏👏👏👏👏📒📒
Thank you for the lecture Sir.
Sir thank u so much this session is really very helpful 😊 🙏
Superb Sir concept cleared.
The homework question answer is 3013, which is an option a
Thank you very much sir
Thank you sir
You super teacher sir u put great effort
Sir your effort our strength
Sir I always better learn your lecture
But sir if you teach on the condition of illness and why I can't study on that condition
Thanks for motivation
soo great iniciative by you sir. we are having a huge respect for you sir...
Option a 3013 will be the correct answer ...thank you so much sir ❤
Sir ek mein difference add kar rahe ho aur ek difference subtract kar rahe ho last ke do ques mein
Very thankfull to you sir ❤❤❤
Thank you very much sir....salute to your hard work...
God bless u sir 🍀 you are best teacher for csat ❤
The answer to the homework question is 3013
Thank you sir
thank you so much sir! you are the best!
🟠⚪ Great fruitful csat session ⚪🟠
Again Informative video sir!
Sir, aa gaya samajh
सभी जगह LCM me se reminder ko minus Kiya hai toh question number 9 m plus kio kiya
In LCM as I noticed, sir is adding the remainders to the Ans when the question says ' in each case leave the same remainder ' and subtracts the remainder when in the number leaves different remainders...….please correct if wrong...was confused with it earlier
Option A 3013
Thank you very much Sir 🙏
Homework ans.
Option (b)
option a
thnku sir
Thank you soo so much sir 😇🎊💙
Great video sir
Sir LCM vale questions me aap kahi remainder ke subtract kr rhe hain aur kahi add kr rhe hain exactly ye btaiye ki kaha pe add krna hai aur kaha pe subtract krna hai????
Awesome classes
Keep going
bohot hi shandaar sir😊
Ques 10 - ans option a
Sir, I have observed that your health is not good since very long, please consult with physician. Your good health will lead to benefit of students like us. Get well soon sir. Thank you for your valuable lessons.
in que ni 5 after dividion of 300 with 225, remainder is 75 so we have to didvide with 225 you mistakenly divided by 300. kindly check thoiugh it doest change the anser but makes mistake in steps
Sir answer is a. Thanks a lot sir😊
Hw ans 3013 sir thankyou so much
Sir you open my eyes by saying pani k saath to lassh bhi ter leti h.
Option A is a right ans 33:01
Thank you vishnu sir 😄
Very helpful class
helping in last moment
Nicely clear concept
504 aaaya lcm then
18 se 7 gya =11
21-10=11
24-13=11
Ok ok ok now
Jaise sir ne kaha ki k ki value rahni hai to 6 rkh lo ok
504×6 -11÷23 =0
3024-11 = 3013 aaega mtlb 23 se poora katega ❤❤❤❤❤❤
10)option a)3013
This series is literally a life saver. Thank you for doing this❤
However, I have a doubt. Sir, in Q6, you added the remainder to the LCM but in the next one, you subtracted it. Is it a mistake or am I missing something? Kindly clarify, thank you!
One thing that I noticed, When remainder is more than one, sir has has subtracted the difference, but when the remainder is same for all, then sir has added the remainder.
Not really subtracting the remainder, he subtracted the difference of (divisor - remainder) with the HCF in case when the remainders are different.
Exactly even I also have the same prblm😢
Thanks sir ans. A3013
KING OF CSAT ....
thanks sir for ur effort
Sir please solve the last question I'm getting confused
Opt c is right sir
Sir,aap basic basic question se upsc ke question krvao q ki sir direct upsc ka question samaj mein nhi atha hain
Best course for UPSC CSAT.🙏
Hey an aspirant this side. Wanted to ask you that can i completely depend on this initiative for Csat because there are lot of online courses in the name csat initiative and most of them fall apart after few lectures. So would you suggest me to go through his videos? And I'm asking this to you because it seems that you have watched the same. Thank you.
@@a.k4394 yes you can rely on this series... this the best one...
@@a.k4394 yes its perfect platform for csat dear.
Nice class
A - 3013
Lekin kaise please samjha dijiye na
Question no . 9 me difference krenge 4 ka ya add
Thank You, Sir. ❤
The answer of question 10 is 3013 when put k=6...
Love u sir.. From Kashmir..... 🥰🥰
Orzu ❤
Sir ak Hcf ke jaga 75 se 225 devide hone wala tha bho 300 ho gaya..kya main sahi hu?question number 5
Vaha prr 300 kyu aya .. mujhe ye smjh nahi aya ...225 ana chahiye tha ander 300 kyu aya
We really needed this .....❤
Thank u sir for all ur efforts 🙏
Nice lecture sirr❤❤
a)3013
504×k-11/23=3013
Q6 option elimination se zaida asan bnta...ty nywyss
Infact q7 q8 b elimte ho rha....
Disclaimer " dono question me ye trick satisfy hua "
I found that , agr multiple of x ko options se divide kre th Jo least no. Completely divisible h wahi answer aarha h
Eg, 2nd last question 7÷ options -> 728 & 364 both divisible but 364 is least so answer is 364
Same in last question also
Great work Sir.
Option A.... 3013
The right answer is 3013.
Option A is a right ans
Antar kahane ka kya matlab h sir batayiye
Get well soon sir