8.3 Torque and Rotational Equilibrium | General Physics

Chad provides a comprehensive lesson on Torque and Rotational Equilibrium and explains in detail how to solve rotational equilibrium problems. He begins with the conditions for rotational equilibrium. First, the net torque acting on the system is zero. Second, the net force acting on the system is also zero. For a 2-dimensional problem, the net force must be broken into x and y components. Chad then solves three torque and rotational equilibrium practice problems. The first rotational equilibrium problem is a straightforward example involving children playing on a see-saw. The second rotational equilibrium problem is a little more complex, involving more forces, but is still a 1-dimensional problem. The third rotational equilibrium problem is a classic physics problem with a 'boom' attached to a wall from which a sign is hung. It is a little more challenging as it is a 2-dimensional rotational equilibrium problem.
00:00 Lesson Introduction
00:44 Conditions of Rotational Equilibrium
02:06 Rotational Equilibrium on a See-Saw Problem
12:43 More Complex Rotational Equilibrium Problem
24:58 2-Dimensional Rotational Equilibrium Problem
Check out Chad's General Physics Master Course: courses.chadsprep.com/courses...

[@williamburris6000]

hey Chad from the bottom of my heart thank you, I'm planning on using you for my MCAT prep. Whether you know it or not you've been with me my whole premed journey and I'm really thankful such high quality content is available.

[@ChadsPrep]

Very kind words - glad the channel has been helping you so much. Happy Studying and best to all of your educational endevors.

[@mohammadaskari3033]

Hello! Why do we not include the normal forces for each person in the first problem?

[@are2515]

At 24:46, why is the tension positive and the other torques negative? Why do we not consider clockwise and counter-clockwise rotation? Thanks!

[@MilkTheBigCat]

Hey, not to get too picky, but when solving for tension in the 2 dimensional problem, did you forget to divide by (sin30)(2.0m) when solving for T?

[@KarenMwelwa]

Thank you ❤

[@Priyanshu.G]

Hi chad,
I don't understand the part where you choose the axis- of rotation.
why for instance, the mass and Fn of seesaw neglected when you chose that area as the axis of rotation?

[@ChadsPrep]

Hey Priyanshu, as I mentioned in the video I choose the pivot point in the center as the axis of rotation because we don't know the mass of the seesaw, but at that point (if there were no additional weights on the seesaw) the torque clockwise due to the seesaw is balanced by the counterclockwise torque, as the pivot point is in the center of the seesaw, similarly at this point Fn balances the weight of the seesaw. So by choosing the center where those unknown quantities cancel out to zero it makes life much easier for the calculation

[@scitamil4193]

Sir, we are expecting only advanced organic chemistry, because you are only a expert in this field ❤

[@user-sp8js2pi2i]

👍👍👍

[@ChadsPrep]

Thanks!

[@IsabelRodriguez-gg2pn]

The tension is 784N, you forgot divide sin30 on both sides. Good video tho.

[@sleepsy1522]

sin (30 deg) is 1/2 and times 2 is 1 so he removes those terms and just subtracts the other group of terms. Even if he did not do the shortcut the sin30 is multiplied by 2 so you forgot to divide by 2

[@masternobody1896]

i hate college

[@ChadsPrep]

you can do it! :)

[@l1.1107]

im still in highschool😔

[@ChadsPrep]

@@l1.1107Well, wherever you are...Happy Studying!