how to solve the question: Let Es denote the contribution of the surface energy per nucleon in the liquid drop model.The ratio Es(Al(z=13,A=27)):Es(Zn(z=30,A=64)) is:
Since due to surface correction term binding energy is proportional to A to the power 2/3.soratio is (27) to the power /64 to the power 2/3.so result is 9/16
Suppose we have more nucleons in the finite volume that the nucleus occupies. Then as the number of nucleons increase in order to occupy more energy levels the energy gap between successive energy levels will have to decrease. This implies that delta goes as 1/A.
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how to solve the question:
Let Es denote the contribution of the surface energy per nucleon in the
liquid drop model.The ratio Es(Al(z=13,A=27)):Es(Zn(z=30,A=64)) is:
Since due to surface correction term binding energy is proportional to A to the power 2/3.soratio is (27) to the power /64 to the power 2/3.so result is 9/16
The answer should be 4/3
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sir, can we actually take a single proton out?
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thank you professor
Which book one should follow to study more about this semi empirical mass formula?
For this you can follow any general book. Book by Krane is the best. Concepts of Physics by Arthur Beiser also works for basic concepts.
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Are you saying that, protons and neutrons cannot have the same quantum numbers
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sir, how delta goes 1/A ?
Suppose we have more nucleons in the finite volume that the nucleus occupies. Then as the number of nucleons increase in order to occupy more energy levels the energy gap between successive energy levels will have to decrease. This implies that delta goes as 1/A.
@@jassuyou from where comes A to th power 3/4
Nuclear mass and mass spectroscopy pr vodies bnya
17:14
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Damn, why is the video-quality straight outta 90s? :/
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