Amazing! I love engineering and what it can do for people and the environment. It's amazing to see how engineers come up with solutions to make the world better and innovate new technologies. As an engineer myself, I appreciate the hard work that goes into developing new products and ideas, and I'm impressed by the creative minds behind them. I love to code and see the uses of engineering in technology and how it benefits people in their everyday lives. Keep up the great work!
Sir @18:44 We are substituting the current value as 4.95A. But if there is a drop at switch which means there is an additional resistance to the thyristor which is added to the circuit along with the load. Hence Req = R + Rthyristor. By this the current value drawn will be higher than 4.95A. But we are taking 4.95 for both Pout & Pin. Please explain Sir I'm so confused.....
Sir input voltage to a chopper is a constant DC ( straight line ) , given 200V in the numericals So average value or dc value of input voltage to the chopper must be Vs itself right?....🤔 Thank you in advance
hello sir i was actually confused in the problem part of output power becoz when i was solving question from a book instead of taking avg output voltage ,the power was calculated using rms value of voltage please help me in this
Sir, but here only average value is become low, but for small instant of time i. e. Ton, main supply voltage is come across the load, for short time and then it becomes zero. So for short time, load has high voltage, so how can we say it step down the supply voltage properly.
Amazing! I love engineering and what it can do for people and the environment. It's amazing to see how engineers come up with solutions to make the world better and innovate new technologies. As an engineer myself, I appreciate the hard work that goes into developing new products and ideas, and I'm impressed by the creative minds behind them. I love to code and see the uses of engineering in technology and how it benefits people in their everyday lives. Keep up the great work!
Your videos are very helpful ,thank you sir
Sir at 10:44 we are supplying constant dc supply of 200V then what's the meaning of avg source voltage???
Sir @18:44 We are substituting the current value as 4.95A. But if there is a drop at switch which means there is an additional resistance to the thyristor which is added to the circuit along with the load. Hence Req = R + Rthyristor. By this the current value drawn will be higher than 4.95A. But we are taking 4.95 for both Pout & Pin.
Please explain Sir I'm so confused.....
Sir input voltage to a chopper is a constant DC ( straight line ) , given 200V in the numericals
So average value or dc value of input voltage to the chopper must be Vs itself right?....🤔
Thank you in advance
But If inductor in series with load then it will be different na
hello sir i was actually confused in the problem part of output power becoz when i was solving question from a book instead of taking avg output voltage ,the power was calculated using rms value of voltage please help me in this
Very good. Thanks 🙏🙏🙏🙏
Sir to calculate chopper efficiency in case R-L load what we will take rms value of output voltage or average value of output voltage
Sir average source voltage will 200 as given how it will become 100V. We can change output voltage but does input voltage will be change?
Sir why the load current is not zero after inductor gets discharged through freewheeling diode ?
Sir, but here only average value is become low, but for small instant of time i. e. Ton, main supply voltage is come across the load, for short time and then it becomes zero. So for short time, load has high voltage, so how can we say it step down the supply voltage properly.
ruclips.net/video/WyIFPL3H32k/видео.html
Sir, Why is the current, not starting from zero initially, but from some value?
ruclips.net/video/WyIFPL3H32k/видео.html
At starting it will start from 0 , but gradually it will start the rising from the point where the waveform stopped falling, which may not be 0....