Condition from A and B were about parity so you get the full information regadless of choice of first guess., Ruel had a bit of luck in getting also C right in the first guess but getting this puzzle in 2 guesses and 4 or 5 tests was doable. It would be harder if if there was 3 different numbers. But there is one important meta information - the information you get from verifiers are enough to exactly get the number so 3 different numbers probably wasn't the option - there would be not enough information to determine all numbers.
6:10 Ah, I see, nevermind… So it must be verifying whether the purple number is larger than the other 2, because that is the case in this particular number combination.
I solved it at the exact same time as Paulo, yeah! I hit pause right after Ruel's first question of round 2 because I felt we had all the info needed and sure enough, Paulo put the same answer in subtitles immediately after. Just got the game and I love it.
i also got in 4 questions: Since circle is bigger, it can't be a triple (because circle wouldn't be bigger, it would be the same). So it must be a double with other numbers being equal. Since triangle is a 2 or 4, square is also a 2 or 4. Since the sum is even, you can't have the circle be uneven or the sum would be uneven. So circle must be 2 or 4 and bigger than other numbers, which makes 224 the only possible solution
I don't know if anyone else posted this, but you didn't need the 4th query. Here's the explanation: We know that Triangle is Even, Circle is the biggest, and the sum of all 3 digits must result in a even number. The 4th verifier must be used in such a way to deduce number of combinations down to 1. Let's hypothesize that there is no repetition: The numbers 213 would result in a success, but so does 215. Because of this we can cross out that condition being the condition it chose since that condition doesn't deduce the number of possible combinations down to 1. And since circle has to be the biggest number, we know that there can't be a triple number. This leaves the only condition that it had to pick is "There are 2 repetitions". From there we can deduce the number down to 224 since 445 would make verifier C false.
Thanks for watching! I'm a big fan of the solo game. It's easy to setup with the app and plays quickly. And it's fun to solve a puzzle during the day. 😊
Thanks for watching! Yes, this was an easier puzzle. In the rulebook there are different difficulty levels and online you can select Easy, Standard, or Hard and you can also select how many verifiers you'll play with, from 4 to 6.
One big nitpick about nitpicking subtitles :) If it is a rules correction or another subtlety it definetely should be VULCAN (eventually Romulan) not Klingon :)
There are 95 verification cards and 48 criteria cards. Each game consists of a combination of 4-6 out of these criteria cards with the same amount of verification cards. Since the order does not matter (combination instead of permutation), this should be in the range of 4-7 million valid games. The formula for all possible criteria combinations is C(n,r) = P(n,r)/P(r,r) = P(n,r)/r! = n!/(n-r)!/r! with n being 48 and r being the 4, 5 and 6. Not taking the verification cards into account, there would be 14 million combinations of those. Not all would result in valid game. I therefore assume, that round about a third to half of them should be valid and some have three instead of two options they check. But you are right, that there are only 125 (5 to the power of 3) possible codes as the numbers range from 1 to 5. But different criteria lead to different games that might result in the same code as result. Still a totally different play with different difficulty.
@@Falco20019 There is two rules in the game that severely limit possible combinations. 1. only one code from 125 that is correct on all verifiers. 2. All verifiers are necessary to crack the code. If some set of verifiers implicates a unique solution , you don't get (proper) superset in game setup. On the other hand the advanced modes with multiple or mixed verifier cards really add a lot of combinations and complexity.
6:41 Question: What if 2 or all 3 numbers were equal? For example, what if the code was 222? How would they indicate that they were equal? Would they just not inform you based on that test - and just have an “X” for that combination?
My only concern is - are the questions always the same? I feel that the puzzle could get very samey/repetitive after awhile, after doing a bunch of these puzzles.
Like Sudoku, this is a puzzle of a game. You're doing the same thing every game: pick a starting code, then use the verifiers to deduce the secret code. That's it. So in that sense, yes, it is samey/repetitive. Obviously, I'm not the best at these type of deduction games, but that hasn't stopped my enjoyment of it. After recording the runthrough, I've logged nearly a dozen plays. Like any game, your mileage may vary. But personally, when I get nearly two dozen plays from a game, I consider it a worthwhile purchase. :)
It would have been helpful to have shown setup. For those of us not entirely hip to this stuff, it would have been good to see the source of the game-yness, as it were
well it's pretty simple: pick a puzzle, there's 2 cards that go in each slot for the puzzle so pull them out of the box and place them, and then start guessing :) if you go to turingmachine.info and hit generate, you can see the particulars!
@@rahdo well I'm a philosopher and not mathematician. I guess I'm not getting what the game is in fact doing; how the _game_ works? But thanks for the video. I'm still at intrigued.
![Turing Machine [Solo Playthrough]](http://i.ytimg.com/vi/-tlfnuQXajE/mqdefault.jpg)
![Turing Machine [Solo Playthrough]](/img/tr.png)
I love that Paulo's subtitles solved the number halfway through the video. :)
:)
Condition from A and B were about parity so you get the full information regadless of choice of first guess., Ruel had a bit of luck in getting also C right in the first guess but getting this puzzle in 2 guesses and 4 or 5 tests was doable. It would be harder if if there was 3 different numbers. But there is one important meta information - the information you get from verifiers are enough to exactly get the number so 3 different numbers probably wasn't the option - there would be not enough information to determine all numbers.
6:10 Ah, I see, nevermind… So it must be verifying whether the purple number is larger than the other 2, because that is the case in this particular number combination.
I solved it at the exact same time as Paulo, yeah! I hit pause right after Ruel's first question of round 2 because I felt we had all the info needed and sure enough, Paulo put the same answer in subtitles immediately after. Just got the game and I love it.
20:58 Great job, Paulo - for solving the code!!! 🎉
i also got in 4 questions:
Since circle is bigger, it can't be a triple (because circle wouldn't be bigger, it would be the same).
So it must be a double with other numbers being equal.
Since triangle is a 2 or 4, square is also a 2 or 4.
Since the sum is even, you can't have the circle be uneven or the sum would be uneven.
So circle must be 2 or 4 and bigger than other numbers, which makes 224 the only possible solution
Well done! 👍🏽
I don't know if anyone else posted this, but you didn't need the 4th query.
Here's the explanation:
We know that Triangle is Even, Circle is the biggest, and the sum of all 3 digits must result in a even number.
The 4th verifier must be used in such a way to deduce number of combinations down to 1.
Let's hypothesize that there is no repetition: The numbers 213 would result in a success, but so does 215. Because of this we can cross out that condition being the condition it chose since that condition doesn't deduce the number of possible combinations down to 1.
And since circle has to be the biggest number, we know that there can't be a triple number. This leaves the only condition that it had to pick is "There are 2 repetitions".
From there we can deduce the number down to 224 since 445 would make verifier C false.
Woot 213 area code! Thanks for the runthrough, Ruel!
L.A. represent! :)
Thanks for the run through! I have been wondering about this game - especially the solo version!
Thanks for watching! I'm a big fan of the solo game. It's easy to setup with the app and plays quickly. And it's fun to solve a puzzle during the day. 😊
I heard about this one and am really keen to try this one
The logic behind the verifier D about the repetition was hard for my brain.
Thanks for the runthrough! Just to get an idea of the level for the puzzles, was this one of the easier puzzles?
Thanks for watching! Yes, this was an easier puzzle. In the rulebook there are different difficulty levels and online you can select Easy, Standard, or Hard and you can also select how many verifiers you'll play with, from 4 to 6.
One big nitpick about nitpicking subtitles :) If it is a rules correction or another subtlety it definetely should be VULCAN (eventually Romulan) not Klingon :)
13:26 We don’t know it is a 5… We just know that it is the greatest number of the 3…
17:38 Except it didn’t take you 4 rounds, since the 3rd round never happened… Give yourself the benefit of the doubt when you finally figured it out!
I really enjoyed Paulo's mocking of Ruel's thought processes.
And there's only 125 possible combinations, not millions.
Cheers! :p
so the app you can download that randomly generates new puzzles... it's not really doing that and can only create 125 total? are you sure about that?
There are 95 verification cards and 48 criteria cards. Each game consists of a combination of 4-6 out of these criteria cards with the same amount of verification cards. Since the order does not matter (combination instead of permutation), this should be in the range of 4-7 million valid games.
The formula for all possible criteria combinations is C(n,r) = P(n,r)/P(r,r) = P(n,r)/r! = n!/(n-r)!/r! with n being 48 and r being the 4, 5 and 6. Not taking the verification cards into account, there would be 14 million combinations of those. Not all would result in valid game. I therefore assume, that round about a third to half of them should be valid and some have three instead of two options they check.
But you are right, that there are only 125 (5 to the power of 3) possible codes as the numbers range from 1 to 5. But different criteria lead to different games that might result in the same code as result. Still a totally different play with different difficulty.
@@Falco20019 There is two rules in the game that severely limit possible combinations.
1. only one code from 125 that is correct on all verifiers.
2. All verifiers are necessary to crack the code. If some set of verifiers implicates a unique solution , you don't get (proper) superset in game setup.
On the other hand the advanced modes with multiple or mixed verifier cards really add a lot of combinations and complexity.
6:41 Question: What if 2 or all 3 numbers were equal? For example, what if the code was 222? How would they indicate that they were equal? Would they just not inform you based on that test - and just have an “X” for that combination?
Yes, there would be an X and you'd have to deduce using the other verifiers.
12:23 And you know it CAN’T be a triple repetition, because you know that the purple circle is greater than the other numbers…
9:03 Therefore, the purple circle cannot be a 1.
My only concern is - are the questions always the same? I feel that the puzzle could get very samey/repetitive after awhile, after doing a bunch of these puzzles.
Like Sudoku, this is a puzzle of a game. You're doing the same thing every game: pick a starting code, then use the verifiers to deduce the secret code. That's it. So in that sense, yes, it is samey/repetitive. Obviously, I'm not the best at these type of deduction games, but that hasn't stopped my enjoyment of it. After recording the runthrough, I've logged nearly a dozen plays. Like any game, your mileage may vary. But personally, when I get nearly two dozen plays from a game, I consider it a worthwhile purchase. :)
@RuelGaviola OK, Thank you...
BTW, I heard something about an Extreme mode, with 6 verifiers. Perhaps this helps mix things up?!
11:46 Don’t do it, Ruel…
First! Also when and where can you buy?
i don't think the publisher sells it directly so you've got to just check game stores and online retailers :)
9:41 But 4+ 4 + 5 add up to 13, which is ODD, not EVEN!!!
It would have been helpful to have shown setup. For those of us not entirely hip to this stuff, it would have been good to see the source of the game-yness, as it were
well it's pretty simple: pick a puzzle, there's 2 cards that go in each slot for the puzzle so pull them out of the box and place them, and then start guessing :)
if you go to turingmachine.info and hit generate, you can see the particulars!
@@rahdo well I'm a philosopher and not mathematician. I guess I'm not getting what the game is in fact doing; how the _game_ works? But thanks for the video. I'm still at intrigued.
well to be honest, it's not really a game so much as a puzzle generator. closer to sudoku than ticket to ride :)
The fourth round was unnecessary. You already knew that a double is correct.
easier said when you're not filming yourself! :)
You're right and I realized this the second I stopped filming.
I did manage to beat the machine on my next non-filmed game! :)
@@RuelGaviola Nice!
@@rahdo no criticism here.