Hello! I'd like to ask you to solve the question 3 of this paper (Suneung test - South Korea - I don't know what year). I don't know why, but RUclips removes my comment whenever I try to link the document, so I will type the problem: "There are 2 students from each of these countries: Korea, China and Japan. These 6 students will each randomly choose to sit in one out of the six seats numbered as in the diagram below. What is the probability that 2 students from the same country sit such that the difference between their seat numbers will be either 1 or 10" DIAGRAM (2x3 table): 11 ------ 12 ------- 13 21 ------ 22 ------- 23 Alternatives: a) 1/20 b) 1/10 c) 3/20 d) 1/5 e) 1/4 First off, I thought the exercise was asking about the cases where AT LEAST two students were sitting in such a way that the condition was satisfied, but I got to 13/15 (through combinatorics), which isn't even an option in the alternatives. Then, I shifted into thinking that maybe I should calculate only the cases where ALL OF THE 6 students were sitting in compliance with the condition and I finally arrived at 1/5 (letter D). Nonetheless, I couldn't find the official answer. So, I'd highly appreciate some help! Thank you!
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You are the king of integral professor
The method you used to solve the first one was time efficient
Very super sir
Still you are uploading such nice integrals
It can be highly useful for me
And provide more your techniques
I wanted to learn!!👍🏻
Same thoughts with you
I am innnnn loooove with your integrals, and your integration skills
Gorgeous
Time for gaokao proffecor
You are the best integration master in RUclips. I know people on X know you are the best
This is so beautifully done professor, you are the best
Hello!
I'd like to ask you to solve the question 3 of this paper (Suneung test - South Korea - I don't know what year).
I don't know why, but RUclips removes my comment whenever I try to link the document, so I will type the problem:
"There are 2 students from each of these countries: Korea, China and Japan. These 6 students will each randomly choose to sit in one out of the six seats numbered as in the diagram below. What is the probability that 2 students from the same country sit such that the difference between their seat numbers will be either 1 or 10"
DIAGRAM (2x3 table):
11 ------ 12 ------- 13
21 ------ 22 ------- 23
Alternatives:
a) 1/20 b) 1/10 c) 3/20 d) 1/5 e) 1/4
First off, I thought the exercise was asking about the cases where AT LEAST two students were sitting in such a way that the condition was satisfied, but I got to 13/15 (through combinatorics), which isn't even an option in the alternatives. Then, I shifted into thinking that maybe I should calculate only the cases where ALL OF THE 6 students were sitting in compliance with the condition and I finally arrived at 1/5 (letter D).
Nonetheless, I couldn't find the official answer. So, I'd highly appreciate some help!
Thank you!
Hello my friend. Thanks for the suggestions! I will find the paper and make a video solution for this problem very soon👍👍👍