Sir its better to speak in english bcz every part of world can u understand u r brief teaching i m enjoying u r videos a lot thanks khan academy try to make a clear schedule to neet also sir plz🙏🙏🙏
11:57 the number density (no.of electrons per volume) increases as the area of cross-section decreases, so the current is undeniably same through the conductor Thanks for the great vedio sir ❤
I think!! We can relate that Puzzle question with Bernoulli's principle --> # Area of wire decrease but with this Vd will increase so overall current will same.
Regarding the last question, we see that the area decreases as we go to the second point, now, if the area decreases, the metallic ions should get closer and closer to each other, so, the relaxation time decreases, if relaxation time decreases, obviously the drift velocity will increase, thus, the current passing remains the same
Hello! So, for alternating currents like the one flowing through your light. The drift velocity that you calculated, is still the same for AC or DC, but, the electrons flow back and forth depending on the frequency of your electrical current, right? As, for the question you posed at the end of your video, the current flowing out of point or terminal #2 is the same as the current flowing into terminal #1, but, the drift velocity for terminal 2 is higher then the drift velocity for the current flowing into terminal #1. You have to use the equation A1*Vd1=A2*Vd2, from fluid dynamics. A1 & A2 are the cross sectional areas at terminals #1 & #2 and Vd1 & Vd2 are the drift velocities at terminals #1 & #2. Its the same current in #1 & #2, but, different A's and Vd's, right?
Sir at last you gave the question and asked for us to derive and we did and the result is 1/A=Vd but how this make sense sir bcz if less area then more collision and reduce in the drift velocity and this leads to reduce in the current right sir Plz explain sir
if Vd is average velocity of a electron,, shouldn't we get an average current?? THIS AVERAGE THING IS BOTHERING ME ,,IF VELOCITY IS AVERAGE THAT MEANS CURRENT ALSO AVERAGE ,, MEANS ON A CERTAIN POINT CURRENT IS SUPPOSE 5 AMP AND ANOTHER POINT 6 AMP ON AVERAGE ITS A PARTICULAR AMPS???
Technically, you are right! But these electrons are zooming at such high speeds that when you consider even timescales of a few milliseconds, you already end up with averaged values!
why the f dont you explain about dq/dt=neavd and that vd*dt=l for volume( A*l) (l) I was confused then I looked for it in my notebook and got myself clear!
mind blowing and an eye opener explanation. i dont understand why my teachers never explained in such a beautiful manner.
Teaching is a high level art, and not everyone knows that
Sir its better to speak in english bcz every part of world can u understand u r brief teaching i m enjoying u r videos a lot thanks khan academy try to make a clear schedule to neet also sir plz🙏🙏🙏
At 9:29, It reminds me of Sal's Euler Identities videos where he said, "If this does not blow your mind, you really have no emotions."
It reminds me of sal's euler identities videos 📷 where he said if this does not blow your mind 😲 you really have no emotion ❤️
11:59, actually as area increases, the drift velocity decreases, and as area decreases drift velocity increases , hence current remains constant
you open my eyes sir ... extremely intuitive and conceptual.. salute you sir .. You are my all time favourite teacher.
thank you so much for this sir.I like how excited you are to teach how and the way you teach is very imaginative and conceptual.
5:06 The distance has the same numerical value as Vd, but it would be clearer to write it as (Vd)*(1s) so the units are correct.
your enthusiasm is everything, really, made me excited abt a formula I was dreading \
It's so interesting to study with these 3d visualisation about the concepts..thank u so much for this wonderful way of teaching...
Sir l love to learn from your videos as it is very easy to understand .
I think he is Mahesh... FloatHeadPhysics
yes he is mahesh sir
11:57 the number density (no.of electrons per volume) increases as the area of cross-section decreases, so the current is undeniably same through the conductor
Thanks for the great vedio sir ❤
Nope. The number of electrons may increase, but the number density - the number of electrons per volume - stays the same!
Brilliant intuitive explanation !!! Physics is way easier when taught by people who are passionate about physics
Sir is the reason I am starting to like physics this much
Sir aap best ho baas aap aisahi video banata raho 😊😊
I would say this is one of the best video on this topic.
You are great bro, I have never seen such great explanation
Superb sir, thanks a lot 👍🏻
I think!!
We can relate that Puzzle question with Bernoulli's principle -->
# Area of wire decrease but with this Vd will increase so overall current will same.
As area increases no of collisions decrease as a result of which Vd decreases
Regarding the last question, I assume Vd increases to make up for the lost "A"?
An example of a piece of EXCELLENT WORK
I want to give this a thousand likes
Awesome . I was looking for this explanation everywhere. Great work.
Your teaching is authentic
Regarding the last question, we see that the area decreases as we go to the second point, now, if the area decreases, the metallic ions should get closer and closer to each other, so, the relaxation time decreases, if relaxation time decreases, obviously the drift velocity will increase, thus, the current passing remains the same
Thank you ❤
Amazing🔥🔥
Hello! So, for alternating currents like the one flowing through your light. The drift velocity that you calculated, is still the same for AC or DC, but, the electrons flow back and forth depending on the frequency of your electrical current, right? As, for the question you posed at the end of your video, the current flowing out of point or terminal #2 is the same as the current flowing into terminal #1, but, the drift velocity for terminal 2 is higher then the drift velocity for the current flowing into terminal #1. You have to use the equation A1*Vd1=A2*Vd2, from fluid dynamics. A1 & A2 are the cross sectional areas at terminals #1 & #2 and Vd1 & Vd2 are the drift velocities at terminals #1 & #2. Its the same current in #1 & #2, but, different A's and Vd's, right?
😶
But for AC electric current is generated by change in flux,
I have watched all three of your videos on this topic and understand very well. Many many thanks brother. Can I connect with you.
Mind blowing explanation
Just amazing 👌👌👏
Waiting for u r videos
Wow it is so good lecture
for the last puzzle question, might be the force on electron decrease in larger area?
Sir u are really great in explaining
thank you for sharing
When electrons flows in a wire how do they flow, I'd they jump from atom to atom or space between them??
Really superb sir
Can I use Ohm's Law to find the Voltage (V=IR) ? I mean: I= (V/R) and the substitute and solve for 'V' ?
Sir at last you gave the question and asked for us to derive and we did and the result is 1/A=Vd but how this make sense sir bcz if less area then more collision and reduce in the drift velocity and this leads to reduce in the current right sir
Plz explain sir
I'm the first veiw and first like
If the A decreases then the no. of charge density will increase to remain the reaction same
Sir, so what changed when same charged passed through different Cross sectional area
Drift velocity or charge density 🥺?
Charge density
because n is inversely proportional to radius of curvature !!!
Sir
How was electricity generated before the invention of Generators?
Electrochemistry padhi hai
-6:00
Hi, drift velocit= - e E /m (dow)
Isn't it????
if Vd is average velocity of a electron,, shouldn't we get an average current?? THIS AVERAGE THING IS BOTHERING ME ,,IF VELOCITY IS AVERAGE THAT MEANS CURRENT ALSO AVERAGE ,, MEANS ON A CERTAIN POINT CURRENT IS SUPPOSE 5 AMP AND ANOTHER POINT 6 AMP ON AVERAGE ITS A PARTICULAR AMPS???
Technically, you are right!
But these electrons are zooming at such high speeds that when you consider even timescales of a few milliseconds, you already end up with averaged values!
Sir Khan academy india par next video kyu nhi aarahe hai
We don't have a Hindi creator currently :-(. And I find it hard to speak and record in Hindi.
Sir kya videos translate nhi kar sakte hai hindi me ?
@@KhanAcademyIndiaEnglish I always want to get your reply but you never reply me 😭😭😭😭
@@bandanasuar9598 Oh, I am so sorry! I will reply next time :)
@@KhanAcademyIndiaEnglish Sir this means a lot to me....I am your big fan sir.... Hats off to you
Nice try with faking an accent...... Loved the video
why the f dont you explain about dq/dt=neavd
and that vd*dt=l for volume( A*l) (l)
I was confused then I looked for it in my notebook and got myself clear!
Ur explaining....but how can we write....
You Channel do have No More Views
indian room? i thought u would be american
-6:00