Sir I have also seen a different form like this: x-x1/l = y-y1/m = z-z1/n Where l, m , n are the direction cosines of the line But I don't know how did we get those I mean the actual equation has direction ratios of parallel vector in the denominator a = l * magnitude of parallel vector But in the book it has knly written l , m , n which are not equal to direction ratios a b c of the parallel vector
@@hrmsmathclass no, you didn't understand my question If you have the ncert book of math you can see that in the topic "Equation of line from a given point and parallel to a vector" There they have derived the Cartesian/symmetric form from the vector form And it is like this: x-x1/a = y-y1/b = z-z1/c Where a, b, c are the direction"ratios" of the "parallel vector" However after the derivation it has written another way of this form with direction "cosines" of the "line" l, m, n in the denominator Like this: x-x1/l = y-y1/m = z-z1/n Even though a ≠ l, b ≠m, c ≠n It is only possible if the magnitude of parallel vector is one There is not much information available in the book and even in the internet
Tomorrow is my exam I m practising night before 😂
Same here
Me too😅
😄👌
Me too
Me too 😂
Thank you sir, just one little feedback.....i kindly request you to increase your mic volume because even with full volume it's barely heard.
In upcoming videos it will be 👍
Nice explanation 👍👍
Sir I have also seen a different form like this:
x-x1/l = y-y1/m = z-z1/n
Where l, m , n are the direction cosines of the line
But I don't know how did we get those I mean the actual equation has direction ratios of parallel vector in the denominator
a = l * magnitude of parallel vector
But in the book it has knly written l , m , n which are not equal to direction ratios a b c of the parallel vector
Yes what you said that's right we prove by using direction cosines every line as a set direction cosine and infinity many direction ratios
@@hrmsmathclass no, you didn't understand my question
If you have the ncert book of math you can see that in the topic "Equation of line from a given point and parallel to a vector"
There they have derived the Cartesian/symmetric form from the vector form
And it is like this:
x-x1/a = y-y1/b = z-z1/c
Where a, b, c are the direction"ratios" of the "parallel vector"
However after the derivation it has written another way of this form with direction "cosines" of the "line" l, m, n in the denominator
Like this:
x-x1/l = y-y1/m = z-z1/n
Even though
a ≠ l, b ≠m, c ≠n
It is only possible if the magnitude of parallel vector is one
There is not much information available in the book and even in the internet
Sir vioce not listening so plz make voice little louder😢 that it may help everyone to listen clearly❤
Nale exam Alva?😂
Yo you done a good explenation thanks
I am too studing now😅😅
Sir make a video on probability ipm questions
Thank you sir 🙏
Most welcome
Thank you thankyou thankyou so much sir the video is very help full for me again thank you sir😇
1hour for exam 😂
ನಮಸ್ತೆ sir 🙏
Gotaita nan yar anta
No
15 min for exam
🙈
Tks sir
ಧನ್ಯವಾದಗಳು ಸರ್
Request a video if any needed
@@hrmsmathclass sir maths important questions exam ge kodi sir
Share what's app number I will send
@@hrmsmathclass sir pls bega kalsi
Lo number send mado madtini pdf ede
Thankyou sir 😶
thank you
Final exam today
All the best
sir speak louder kela
In the upcoming videos I will
😂