Lifesaver, actual lifesaver. Taking a fully online, non-interactive course. You've single-handedly returned my sanity and for that, I thank you, so much.
I'm so glad I was able to help! I know online courses can be really tough when you're trying to get through all the material completely by yourself. :)
I spent almost an hour trying to find an explanation for this type of problem, including my calculus book, and this is the best explanation/example by far
Thank you! I have a test in 45 minutes and this was a real lifesaver :))) I've been so confused because I kept thinking that for the normal plane you would need to use the normal vector (I mean it makes sense lol) but this clarified everything for me!
Why is r'(t) being evaluated at t=pi as the normal vector on the normal plane and not N(t)? Because I recall you saying at the beginning that N(t) lies within the normal plane, so we'd have to take its components to plug in for a, b and c.
+Noelle Marie Villanueva , I think! its because a plane is described using a normal vector, so the normal vector of the NORMAL plane would be the equivalent of the tangent of the curve, or r`(t). The N(t) does not describe the plane, its just a vector that lies within the plane. Remember a normal vector is just an orthogonal/perpendicular vector. She could have used T(t), and get the same equation with just scaled co-efficents.
I still don't get why we use the coefficients of r'(t) to find our normal plane equation. My instinct would say to use the coefficients of N(t) (the same way we use the coefficients of B(t) to find the equation of the osculating plane). Help? :(
I would give you two thumbs up if I could Krista, you are a Great Teacher! but graphing out the formulas in Geogebra 3d it looks like for the Normal Plane y = 6x+pi.
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Rarely do I comment on things, but this video was perfectly laid out. I watched this an hour before my quiz and I remembered everything. Thank you!
You’re so welcome! And I’m so glad it helped on the quiz!! 🫶
the normal vector equation should be y=6x+pi, just a tiny sign error
Lifesaver, actual lifesaver. Taking a fully online, non-interactive course. You've single-handedly returned my sanity and for that, I thank you, so much.
I'm so glad I was able to help! I know online courses can be really tough when you're trying to get through all the material completely by yourself. :)
@@kristakingmath Why haven't you posted in a while?
In just the first 2 min I finally understood how to find the normal and osculating equations. Thank you!!
I spent almost an hour trying to find an explanation for this type of problem, including my calculus book, and this is the best explanation/example by far
+RAymond Impara Thank you so much, I'm glad it helped!
Thank you! I have a test in 45 minutes and this was a real lifesaver :))) I've been so confused because I kept thinking that for the normal plane you would need to use the normal vector (I mean it makes sense lol) but this clarified everything for me!
Oh good! I'm so glad it helped! :D
Why is r'(t) being evaluated at t=pi as the normal vector on the normal plane and not N(t)? Because I recall you saying at the beginning that N(t) lies within the normal plane, so we'd have to take its components to plug in for a, b and c.
+Noelle Marie Villanueva , I think! its because a plane is described using a normal vector, so the normal vector of the NORMAL plane would be the equivalent of the tangent of the curve, or r`(t). The N(t) does not describe the plane, its just a vector that lies within the plane. Remember a normal vector is just an orthogonal/perpendicular vector. She could have used T(t), and get the same equation with just scaled co-efficents.
Thank you so much! This helped me immensely on my Calc 3 homework.
I still don't get why we use the coefficients of r'(t) to find our normal plane equation. My instinct would say to use the coefficients of N(t) (the same way we use the coefficients of B(t) to find the equation of the osculating plane). Help? :(
You did a remarkable job:)
Powerful work,it has greatly helped me
FYI "osculating" is not the same as "oscillating," you were saying "oscillating."
agreed
Not to pick nits but the pronunciation is \ˈäs-kyə-ˌlāt\. The 'c' is a hard c.
Oh no... 15:45 she forgot to make the sign in front of 6sin(3t) positive because they cancel out, and she goes forward with that later on.
Shouldn't the equation of the normal plane be y=6x+pi since you are solving for y when you have -6x+y-pi=0?
Excellent explanation. Thank you so much for clear and concise procedure.
You're welcome, Les, I'm so glad it made sense! :)
Thank you soo muchhh 🤗🤗🤗 I got every single question's answer regarding this topic.. Welldone and keep it up!
Thanks, Maths! I'm glad it helped! :)
Thanku mama
That curve is not unit speed curve. How are you using Frenet-Serret for unit speed curves?
thank you for your great videos on calc 2
Thank you so much for the help 🤗🤗🤗🤗🤗😇😇😇🤖🤖
I would give you two thumbs up if I could Krista, you are a Great Teacher! but graphing out the formulas in Geogebra 3d it looks like for the Normal Plane y = 6x+pi.
For the osculating plane, don't you have to distribute the 1/sqrt37 to a, b, and c?
thank you so much. you helped me out a lot
+J Ferro You're welcome, I'm glad I could help!
Why do you use the values of r'(pi) for a,b,c instead of the values of the normal_vector(pi)?
This is the same question which was asked in our midsems at bits pilani, india. Can you tell me from which book you have taken this question
Thank you for the video, It really helps a lot
Yay! Thanks for letting me know.
WOW! Thanks a lot! It's very easy and clear to undestand!
+Moldir Kenzhekulova So glad I could help!
For the normal plane: it should be y=6x+Pi.
Good catch, thanks! I've added an annotation to clear up any confusion.
My y = 12t. How do I proceed?
Amazing job! Perfect presentation.
+Michael Gibbons Thank you so much!
You saved me! Bless.
Excellent video, excellent explanation. Thank you!
You're welcome, thank you so much!
Thank you 😄
1:00
Y=6X+π and not -π in the final normal equation
Phenomenal thank you
How to find equation of rectifying plane?
Thank you!!
i have a curious question, does calc 3 get any messier than this ? lol
yes
Helped so much!
Well presented
Khabisang Lekena Thanks!
Amazing
you are the baaaaas!!(that's boss! in Afrikaans)
thank you so much for this! a lifesaver!
So glad it helped!
what program do you use?
+Kwasi Fahie kristakingmath (dot) com / my-videos
Small typo on the video, you put y=6x-pi when it should be y=6x+pi for the equation of the normal plane
Since 10th grade I have been finding your solutions to my hw problems. Im now second year of attaining my degree and still here. How time moves by 😢
Wow that’s awesome!! Congrats on working toward finishing your degree, I’m so happy for you!! ❤️☺️
What if you were just given t=pi
wow,,you are so smart,,,
Y= 6x+pi.
Thank you! You made this very easy to understand!
I'm so glad I could help!
thank u mam
cross product is wrong
you a G
Kick ass
You have saved me from failing! THANK YOU!
I'm glad I can help along the way! 😊
ذكتور نريد التواصل معكم على الخاص
disregard last comment, im on a phone so i didnt know there were annotations whoops
Why even bother finding N(t)?
The osculating plane is the plane spanned by n and t
Since the osculating plane is perpendicular to B(t), you need to first find B=TxN, then use B to find the osculating plane.
I love u, lol.
Jesus is LORD!
Bruh
not funny
didn't laugh