This can be recognised as the result of applying Abel's Summation formula (often used in analytic number theory). Make the substitution t = x^(-1/2) and we have 2 \int_1^\infty [t]/t^3 dt. This is equal to the sum from n = 1 to \infty of 1/n^2. The extra term [x]/x^2 vanishes as x tends to \infty. The sum equals pi^2/6 due to a result by Euler.
Pretty nice solution. I thought the problem was for round(1/sqrt(x)). Isn't that what [ ] means? I thought floor was |_ _|. Is that not the convention?
This can be recognised as the result of applying Abel's Summation formula (often used in analytic number theory). Make the substitution t = x^(-1/2) and we have 2 \int_1^\infty [t]/t^3 dt. This is equal to the sum from n = 1 to \infty of 1/n^2. The extra term [x]/x^2 vanishes as x tends to \infty. The sum equals pi^2/6 due to a result by Euler.
Thanks so much!!
Thank you for showing us this. I think it's very cool also!
I love this!
you forgot the dx in the thumbnail!
His arm was covering it /hj
Fantastic
Why in the 90s nobody ever mentioned floor functions in math classes?
Thank you my nigga dr peyam
Learn how to talk.
Thanks
Pretty nice solution. I thought the problem was for round(1/sqrt(x)). Isn't that what [ ] means? I thought floor was |_ _|. Is that not the convention?
The convention is that [ ] and |_ _|mean floor
@drpeyam good to know. I get confused with the symbols. Is ceil(x) |`x'| ? (Imagine ` is a horizontal line at the top, like a "bar")