Moment of Inertia of an equilateral triangular plate | JEE Advanced Concept Shots | Chetan Mishra

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[@Lakshya_Raj07]

This is what I was searching for. 🎉🎉
Thanks ❤

[@iitians000]

(L/2 root3) hoga na do centroid ke beech ka dist
Then usse to alag aaj jata hai?

[@rishabhshetty4304]

Why didn't you use this standard result :
Moment of Inertia of a triangular lamina with mass uniformly distributed on it about any axis of rotation is equal to the moment of inertia of 3 point masses having one third mass of the triangular lamina placed at the midpoint of each side of the triangular lamina about the same axis of rotation .
This is the best and easiest approach .

[@SharadMishra-c2n]

Superb explaination❤❤

[@Lakshya_Raj07]

Me after method 2:-
Aapke solve karne ka tarika thoda casual h 😂😂

[@namanarora2005]

First method Explanation was good but the 2nd method wasn't convincing and usme feel ni ayaaisa lagra tha wrong approach hai lol😂
Edit:2nd method mai
Joh 3× hua hau outer triangle ke liye , usme basically humne Sare triangle ka moment of inertia about center axis ki nikala hai and outer triangle la I+Distance from their com ..... Bruh

[@utkarshGrows]

Thank You very much

[@soumya5633]

Sir, we know that for any triangle, the moment of inertia about its base is mL^2/6, so if we replace 'h' by Lsin60 , we get mL^2/8...Sir where am i making a mistake??

[@maanvigupta5462]

that result is valid when the axis passes through one of the sides. here, the axis passes through the centroid. hope it helps :)

[@sujalpatel3565]

Thank you sir

[@ashmitsharma2668]

Sir which is the best time for the jee preperation
Currently I am studying in class 10th but if I start my prepration from class 11 can I score in jee then?
Please answer sir.

[@vivektiwari709]

Ofcourse

[@AbhishekMishraiitkgp]

Yes. You can do well even if you start in class 11th. All you need is being serious regarding your studies and being honest to the process. I started in class 11th and ended up with an AIR of 793. If I can do that much you can do even better. All the best. :)

[@ashmitsharma2668]

@@AbhishekMishraiitkgp thank you sir.

[@Shogun507]

@@ashmitsharma2668 How did it go for you?

[@sitanshunaik6157]

very good explanation sir❤

[@PiyushKumar-gv4bi]

OP sir

[@omnisdomain6416]

Nice video

[@ramgobindram7402]

Just awesome sir

[@udayrajgupta4880]

nice nice 😀

[@Adarshkumar-hu9iq]

Sir best💗💗💗💗 explanation & all concept in a very short video......u r also best.....
Sir if possible I would be very happy if you Collab with 💓💓💗💗PHYSICS WALLAH in future

[@sandeepshaw2099]

Thanku sir😀