Why I don't teach LIATE (integration by parts trick)

Поделиться
HTML-код
  • Опубликовано: 2 окт 2024

Комментарии • 562

  • @blackpenredpen
    @blackpenredpen  3 года назад +1059

    It doesn’t matter if it’s ILATE or LIATE. Since if you have an integral with both log and inverse function, then it’s most likely not doable in the first place 😆

    • @electrocode4095
      @electrocode4095 3 года назад +21

      Yup 👍

    • @electrocode4095
      @electrocode4095 3 года назад +19

      What's your qualifications
      Are you a PhD holder?

    • @AbhishekKumar-jg7gq
      @AbhishekKumar-jg7gq 3 года назад +75

      In india it is called ilate 🤔🤔

    • @_AadiDevSharma
      @_AadiDevSharma 3 года назад +7

      @@AbhishekKumar-jg7gq ya..you ar right..

    • @Gg-ij7li
      @Gg-ij7li 3 года назад +8

      @@AbhishekKumar-jg7gq mere ko LIATE sikhaya hai lol

  • @gcewing
    @gcewing 3 года назад +2709

    I prefer the LATTE method. If the integral looks hard, go and make yourself a coffee.

  • @sudoheckbegula
    @sudoheckbegula 3 года назад +208

    12:50
    The smile of cancellation

  • @japotillor
    @japotillor 3 года назад +94

    I agree in not using LIATE, it's not about memorising a mechanic, I like having the openness of realising a mechanic doesn't always work. When I teach integration by parts, I always teach find the function to integrate first

  • @shehnazsalahuddin6053
    @shehnazsalahuddin6053 3 года назад +613

    I believe that by inspection we can easily see which one is easier to differentiate and which one to integrate. This idea or sense helps students in the long run. Tricks might help for short term, but not for the long run. This also helps students to recognise different patterns and get familiar with mathematics.

    • @Jlang-es9lc
      @Jlang-es9lc 3 года назад +28

      I agree. It’s better to understand why you shouldn’t do a certain thing, instead of just learning a rule to say you shouldn’t do it.

    • @angelmendez-rivera351
      @angelmendez-rivera351 3 года назад +8

      AMEN. Preach it. Ok, but seriously, these are the exact same words I had in mind as soon as I started the video, and I am glad I am not the only one, and I am glad you beat me to it.

    • @jeeteshabrol
      @jeeteshabrol 3 года назад +5

      Yes this helps a lot in integrating products of similar functions. Like in sec³(x), one can easily say that we will integrate sec^2(x)

    • @gregorymorse8423
      @gregorymorse8423 3 года назад +6

      Define formally and mathematically what "easier" to integrate or differentiate means. Otherwise it is bringing some pseudoscience argument into the mix. As far as I can tell there are dozens of patterns which work by trial and error, and a few of them are very common. But the patterns should ultimately be well defined and not rely on intuition. A computer program should be fed thousands of these problems applying pattern rules until a "perfect" pattern is found at least for those in the dataset

    • @angelmendez-rivera351
      @angelmendez-rivera351 3 года назад +12

      @@gregorymorse8423 The patterns need not be well-defined. LIATE is merely mnemonic, not a mathematical theorem. You are reading too much into this, and nearly everyone else knows what exactly is being meant by "easier".

  • @reidpattis3127
    @reidpattis3127 3 года назад +105

    I feel like most Mathematicians do this anyways subconsciously. And it is a good first instinct to have to quickly solve problems. But there are cases that don't quite work, and I think it's up to the student to discern for themselves.

    • @mathevengers1131
      @mathevengers1131 3 года назад +3

      I agree with you of doing these subconsciously.

  • @turtledruid464
    @turtledruid464 3 года назад +259

    My calc 2 teacher taught us the LIATE method but didn't make us use it if we didn't want to. Same with the DI method. I personally never used it but for some people it did help. IMO it's just about teaching the tools, not telling the students which ones to use.

    • @anonymous_4276
      @anonymous_4276 3 года назад +7

      Yeah same. Looking back at it, I think it was better that I never used methods like LIATE as this forced me to think more about which function to integrate and which to differentiate when using integration by parts. After some practice, I could calculate the second term quickly without a pen often and I could see if there was any way to integrate that term or if it was similar somehow to the original integral (like in case of sec³(x)) or if I had to do repeated integrations by parts which were getting even more complicated etc.

    • @prithwishsen4710
      @prithwishsen4710 Год назад +1

      I had a question?
      Is there like a proof to the ilate rule

  • @alessiodaniotti264
    @alessiodaniotti264 3 года назад +44

    Another way to deal with sec^3 is:
    sec^3(x)= 1/cos^3(x)= cos(x)/cos^4(x)= cos(x)/(cos^2(x))^2=cos(x)/(1-sin^2(x))^2
    and with a substitution: sin(x)=u ; cos(x)dx=du
    we have the integral of 1/(1-u^2)^2 wich is a rational funcion, so quite easy to integrate.
    Is a method that works for 1/cos^n(x)and 1/sin^n(x) for every odd n.

    • @MarieAnne.
      @MarieAnne. 2 года назад

      But is that really simpler?
      ∫ sec³x dx = ∫ 1/cos³x dx = ∫ cos x/cos⁴x dx = ∫ cos x/(1−sin²x)² dx → sin x = u, cos x dx = du
      = ∫ 1/(1−u²)² du = 1/4 ∫ ( 1/(1+u)² + 1/(1−u)² + 1/(1+u) + 1/(1−u) ] du
      = 1/4 ( −1/(1+u) + 1/(1−u) + ln|1+u| − ln|1−u| ) + C
      = 1/4 ( 2u/(1−u²) + ln|(1+u)/(1−u)| ) + C
      = 1/2 ( sinx /(1−sin²x) + 1/2 ln|(1+sinx)/(1−sinx)| ) + C
      = 1/2 ( sinx/cos²x + 1/2 ln|(1+sinx)²/(1−sin²x)| ) + C
      = 1/2 ( secx tanx + 1/2 ln|(1+sinx)²/cos²x| ) + C
      = 1/2 ( secx tanx + ln|(1+sinx)/cosx| ) + C
      = 1/2 ( secx tanx + ln|secx + tanx| ) + C
      The solution above doesn't even include the work required to find partial fraction decomposition.

    • @venvi
      @venvi Год назад

      @@MarieAnne.Hey who are you.
      .
      .
      .
      .
      you really an god gifted child.

  • @lutherlessor4029
    @lutherlessor4029 Год назад +2

    This video is great. There's always that tension between "tools that are very helpful most of the time" and "concepts that work nearly all the time," and you balanced this excellently in this video with examples to both sides. 💪

  • @richardryan5826
    @richardryan5826 3 года назад +81

    Excellent video. Before I retired, I told my students that LIATE is a nice "rule of thumb" but, when integration by parts is applicable, LIATE does not work 100% of the time. The example I used to demonstrate this fact is the integral of (xe^x)/(x+1)^2. in this case, the factor to be differentiated is xe^x and the factor to be integrated is 1/(x+1)^2.

    • @clementfradin5391
      @clementfradin5391 8 месяцев назад +2

      I think the answer is e^x/(x+1)+c

    • @richardryan5826
      @richardryan5826 8 месяцев назад +1

      @@clementfradin5391 You are correct!

    • @jamescollier3
      @jamescollier3 8 месяцев назад

      we said U times V - the integral of V du. ... How math geeks make poems

    • @shmkrar1153
      @shmkrar1153 7 месяцев назад +1

      Thanks @richardryan5826 ! This problem helped me!

  • @shubhankurkumar
    @shubhankurkumar 3 года назад +101

    My first class of calculus was in 11th grade in India, that's Junior Year in America. We were always taught ILATE, explanation was "Choose whichever is the harder to integrate" and like you said, it works in almost all scenarios.
    Wherever there was an exception we were given the solution and were told the specifics.
    It's the first time I'm hearing of DI method. Pretty amazing!!

    • @rupakchanda3503
      @rupakchanda3503 2 года назад +3

      By parts ke kaam asan ho jaata hai...

    • @DiverseDose11
      @DiverseDose11 11 месяцев назад

      Hame
      LATEC padhaya Gaya hai

  • @TheTriggor
    @TheTriggor 3 года назад +16

    Small brain: memorize this rule
    Big brain: recognize the easier integral like a boss

  • @DarkBoo007
    @DarkBoo007 2 года назад +3

    I never seen the LIATE method before. Like you said, I tell the students that they must figure out what to integrate first since finding the derivative is the easiest (sometimes). Unfortunately, many students of mine have trouble doing so.

  • @seanbastian4614
    @seanbastian4614 3 года назад +24

    The way I learned the LIATE method was that you should use it when first attempting the question. They said it won't always work, but it can help you start working out the problem.

  • @cristofer2794
    @cristofer2794 3 года назад +8

    Integration by parts:
    int udv=uv-int vdu
    One day i see a cow doing i dont know what.... a engineer cow with uniform xd
    "Un Día Vi a Una Vaca Vestida De Uniforme"

    • @cookieman2028
      @cookieman2028 3 года назад

      wtf xd

    • @carultch
      @carultch 11 месяцев назад

      @@cookieman2028 That says "one day I see a cow dressed in a uniform"

  • @mayurchaudhari850
    @mayurchaudhari850 2 года назад +6

    I never thought LIATE as a rule or as a method. It's more like an advice from experienced mathematicians, "In most of the integrations, you'll find yourself integrating in this pattern."

  • @tambuwalmathsclass
    @tambuwalmathsclass 3 года назад

    For the past 3 years before I started my own RUclips channel, I ever called you Father of Calculus 💪

  • @YuvrajChowhan
    @YuvrajChowhan 3 года назад +4

    -cos(x^2)/2+C will be the answer to the last question. No need to apply LIATE or ILATE. It can easily be done by substitution by substituting x^2=t.

    • @Katoto112
      @Katoto112 3 года назад +1

      K genieass

    • @yatogami7393
      @yatogami7393 3 года назад +1

      Whenever i see x^2 and x together , always do it

    • @yatogami7393
      @yatogami7393 3 года назад

      @@Katoto112 why do you even care lol

  • @makemymarket1772
    @makemymarket1772 Год назад +1

    Integration by parts felt impossible until i found this video, thanks!

  • @yatogami7393
    @yatogami7393 3 года назад +11

    I am lucky that I got a good Mathematics Teacher . When we came across this stuff , he taught us this method but suggested not to use it . He told us to integrate by parts by choosing which expression is "easier to integrate" by our intuition. And for real , in some questions even this rule fails(as in takes longer time ). And you sometimes can use different methods to integrate a function that seems harder to integrate but is easier than the other one.

    • @yatogami7393
      @yatogami7393 3 года назад +3

      The last line was a twister lmao.

  • @theedspage
    @theedspage 3 года назад +2

    Very insightful. I like the DI method for IBP.

  • @Samir-zb3xk
    @Samir-zb3xk Год назад +9

    For integral of xsin(x^2)dx in the end card: its easier to do u-sub then by parts
    u=x^2 , dx=du/2x
    integral of xsin(x^2)dx
    =1/2 * integral of sin(u)du
    =1/2 * -cos(u)
    =-1/2 * cos(x^2)+c

    • @thekingdragon6660
      @thekingdragon6660 4 месяца назад

      dont forget the C 😅
      welldone, it's a right ans. I got it too

    • @Samir-zb3xk
      @Samir-zb3xk 4 месяца назад

      @@thekingdragon6660 damn how did i forget the c 😰
      Thanks lol

  • @shadeblackwolf1508
    @shadeblackwolf1508 3 года назад +8

    We learned "choose one, and check if you've reduced the mess. Back out if you have not." Would a substitution on u = lnx not help on the 4th case?

  • @abdelkaderzeramdini7461
    @abdelkaderzeramdini7461 3 года назад +29

    For the integral of xsin(x^2) there is no need of integration by parts. Just U-substitution let u=x^2 so du=2xdx
    It becomes integral of-1/2cos(u) and the final answer is-1/2cos(x^2)+C

    • @megauser8512
      @megauser8512 3 года назад +8

      Yep, and in fact, if you do LIATE integration by parts on this integral, then you'll have to differentiate x and integrate sin(x^2), the latter of which is impossible!

  • @drhubblebubble7
    @drhubblebubble7 3 года назад +4

    In my 6 years of knowing integral calculus this is my first time that I've heard of LIATE. At this point I would trust my intuition more than LIATE.

  • @shmkrar1153
    @shmkrar1153 7 месяцев назад

    For the bonus problem, i think we can use u substitution u=x^2

  • @marco-vz5kv
    @marco-vz5kv 3 года назад +18

    Well... I've been taught ILATE as integration by parts

  • @overlord_actual3739
    @overlord_actual3739 3 года назад +1

    when you put +C it makes me happy

  • @destroyer2247
    @destroyer2247 2 года назад

    The last bonus question can be done by substitution

  • @advaymayank1410
    @advaymayank1410 Год назад

    The third integral came in handy when i was computing distance traveled by a projectile. Glad I did it right

  • @tortillajoe
    @tortillajoe 3 года назад +22

    My teacher didn’t like the idea of restricting us to LIATE so we instead subscribed to a some rules of thumb. These are the ones I remember, still use, and are almost always enough to make the right choice.
    A) If one of the functions has cyclic (sines, cosines, exponentials, etc.) or terminal derivatives (polynomials), let that one be the one you differentiate. Unless the other function’s integral is unknown or unsolvable by you, in which case…
    B) Let the most difficult of the functions that you CAN use integrate be the one you integrate.

  • @tholod
    @tholod 3 года назад +31

    It's fun, in France we have ALPES, for arccos/arcsin ; log ; polynomial ; exponential ; sinusoidal. At the time I learnt integration, my teacher said like you that it is better to search which part is better to integrate than use this tip.

    • @pushkarrakhe385
      @pushkarrakhe385 3 года назад +1

      Wow that's such a cool acronym!

    • @goodplacetostop2973
      @goodplacetostop2973 3 года назад +3

      Well I guess this acronym really… alp-ed you out!

    • @pushkarrakhe385
      @pushkarrakhe385 3 года назад

      @@goodplacetostop2973 lol

    • @bobnavonvictorsteyn9017
      @bobnavonvictorsteyn9017 3 года назад

      @@goodplacetostop2973 you’re a celebrity on this part of RUclips.

    • @teo_rc
      @teo_rc 3 года назад

      In Mexico we use ALPES too and it's dope

  • @venky3656
    @venky3656 3 года назад

    for the sex^3(x) qn we can use the result of int root(a^2 + x^2) dx = x/2 root(1+x^2) + a^2/2 ln |x + root(1+x^2)| + c to get quick ans

  • @davcaslop
    @davcaslop 3 года назад +6

    In spanish we say ALPES:
    A=arcsin, arccos, arctan, etc.
    L=logs
    P=polynomios
    E=exponential
    S=sin, cos, tan, etc.
    It's said that not always work but it has always work for me with this set.

  • @cornationboot8690
    @cornationboot8690 Год назад

    5:23 actually it helps u need to know an identity of integration of root of x^2 + a^2

  • @NevlaIshan
    @NevlaIshan 13 дней назад

    6:24 secx=under root(1+tan²x)
    So eqn becomes underroot(1+tan²x)×sec²x
    Let t=tanx then subsitution you also get answer

  • @Bhuvan_MS
    @Bhuvan_MS 7 месяцев назад

    In my college, they had taught us about the ILATE rule but they also mentioned that it is not always necessary to follow the order and gave us the examples. So we just had to understand which function was easily integrable and which wasn't. I guess it is more sort of, an intuitive method of solving.

  • @juliuspulido5980
    @juliuspulido5980 8 месяцев назад +1

    The feeling being ready before diving to Calculus 2 this upcoming 2nd sem.😌

  • @egillandersson1780
    @egillandersson1780 3 года назад +7

    The 4th is amazing !

    • @deadlyfury6317
      @deadlyfury6317 3 года назад

      Let me tell you another approach to the same problem
      we assume lnx=t
      dx=e^xdx
      integral reduces to e^t[ t/(t+1)²]dt
      e^t [ 1/1+t - 1/(1+t)²]dt
      this becomes d(e^t/1+t) using the product rule and the derivative and integral cancel out.
      so we get the same answer substituting t back

  • @christopherarevalo1010
    @christopherarevalo1010 2 года назад +1

    They way he solved the hard integral blew my mind! I've never heard of LIATE, so this entire video is just me learning.

  • @easyfundbles2608
    @easyfundbles2608 6 месяцев назад +4

    for guys lived in morocco 🇲🇦, they have been using a technic called "ALPES" istead of laatte
    A -Arctan ,arcsin,arcos
    L - ln
    P - polynomial
    E - Exponential
    S -Sin , cos , tan

    • @Ray.096
      @Ray.096 5 месяцев назад

      the same as ILATE

  • @SuperYoonHo
    @SuperYoonHo 2 года назад +1

    Thank you!

  • @Kiwinov
    @Kiwinov 3 года назад +7

    I completely agree, you can't exactly impose strict rules for calculus. It always matters the type of problems you are solving and thinking a few steps ahead is the key. I always hated that rule

  • @twakilon
    @twakilon 3 года назад +15

    I personally hate those sort of "tricks". Make the students think by themselves.

    • @harleyspeedthrust4013
      @harleyspeedthrust4013 3 года назад +7

      Me too. Unfortunately, general chemistry is riddled with them. The entire class is about learning a bag of tricks and rules to solve contrived problems from every different area of chemistry. There's no natural structure or flow to the class. For example, in a calc class, you'll typically start with a motivation for derivatives, then discuss the definition of a derivative, then learn how to arrive at derivative "rules" by using what you already know, then repeat for integrals. It flows very nicely, and there's a general structure to the class. Not so in gen chem. You start with the absolute basics, then learn stoichiometry for two weeks, then some organic chemistry for the next two weeks, then nuclear chemistry for another two weeks, etc. The lack of flow in such a class necessitates the use of black-box tricks and rules to complete the problems. In short, you never learn where the tricks come from, why they work, or how to work without them, because you never go far enough into a subject to be able to understand such things. This is why general chemistry is so badly done across the board, the nature of the class attracts people who are drawn to arbitrary rules and control (the types who tell you to follow a procedure without any explanation for WHY you should follow the procedure). I despise any class that teaches an arbitrary set of tricks and rules instead of the skills necessary to develop your own tools.

    • @evanurena8868
      @evanurena8868 3 года назад

      You can thank high school math for those "tricks". Heck, most AP calculus classes do not even have the courtesy to teach epsilon and delta proofs. Not including the precise definition of a limit is the biggest detriment of high school calculus because it's the heart of college level calculus and analysis where such arguments are the foundations for proving derivatives and integrals. If want to know why the definition of a derivative is the limit of a difference quotient you need epsilon delta arguments and likewise for an integral as a limit of a riemmann sum.

    • @183lucrido_ase
      @183lucrido_ase 3 года назад

      Looks like you don't know how to cook them: first show trick than explain why it works. There are no math olympiad winners who dont know endless row of tricks. Yes, they are clever but not " invent method of general sulution of a*cosx+b*sinx = c in 1 second"-clever.

  • @Dalton1294
    @Dalton1294 3 года назад +1

    The bonus question let u=x^2 and you have to solve 1/2∫sin(u)du

  • @yourdad602
    @yourdad602 Год назад

    I tried to use LIATE in the bonus example. So I chose sin(x^2) to be integrated. When I tried to do that found out it becomes soooo easy if you just use the form 1/2∫2xsin(x^2)dx.

  • @TkK1122
    @TkK1122 3 года назад +4

    I haven't finished the video, but I'm so much satisfied by the way you change markers (so Smooth dude) 😂❤️

  • @elquesohombre9931
    @elquesohombre9931 8 месяцев назад +2

    Moral of the story is just do whatever sounds like less of a nightmare and fuck around if you’re stuck. Liate is just a way to get you moving if you’re a hesitant student. Only way to solve a hard problem is to try solving it, even if there’s no clear solution.

  • @МаксимАндреев-щ7б
    @МаксимАндреев-щ7б 2 месяца назад

    I usually write
    Int x^2 ln(x) dx = Int ln(x) d(x^3/3) = ln(x) x^3/3 - Int x^3/3 d(ln(x))= ln(x) x^3/3 - Int x^2/3 dx = ln(x) x^3/3 - x^3/9 + C

  • @EprhaCarvajal
    @EprhaCarvajal 3 года назад +3

    It’s actually funny that in my education in Dominican Republic we use the method but the order is different, for us is ILATE, all the letters stands for the same.

  • @theartisticactuary
    @theartisticactuary Год назад +2

    In the bonus example, just substitute u=x^2
    I know the question is what if I try to integrate by parts but:
    - maths is about getting to the right answer and spotting the quickest way is always a valuable skill
    - according to the rules of logic ("if today's Sunday I'm the pope" according to the late Doctor Richard Maunder, or "if my granny had wheels she's be a bike" according to Gino Cappucino), any answer to your question is correct if I'm not going to integrate by parts. If I integrate that by parts then I'll climb Nelson's Column naked.

  • @opufy
    @opufy Год назад

    Scandalous! I just was taught this on Monday!

  • @Satori_kun
    @Satori_kun 3 года назад

    I never heard of this rule of thump but the use of sec disturbs me very much. Here in germany I never saw someone using sec, csc or cot, they just use the normal sin, cos, cot representation.

  • @yanwu8758
    @yanwu8758 2 года назад +2

    I don't mention LIATE. Let students explore on their own. If their u fails, then go back and try a different u. My tip for students is to find the u-term first. The u-term in the original integrand is usually the term you want to change or get rid of through differentiation.

  • @chessematics
    @chessematics 3 года назад

    The last screen integral is u-sub, just let u=x² and we it autopilots on itself.

  • @hemandy94
    @hemandy94 3 года назад +2

    I never heard of this LIATE method and maybe it was for the best. Instead of giving us another "trick" to memorize, they just told us to choose which to integrate and which to differentiate.

  • @omjoglekar3677
    @omjoglekar3677 3 года назад +4

    YAY ! Just took membership ! (both channels)

  • @theoddonceextraordinary7172
    @theoddonceextraordinary7172 9 месяцев назад +2

    In India we have ILATE ....

  • @paesanng
    @paesanng 3 года назад +11

    I often tell my students, "We artificially adjust things to fit into standard forms we can use."
    Especially with situations we are integrating constant/quadratic or linear/quadratic.

  • @kjl3080
    @kjl3080 2 года назад

    the virgin LIATE vs the chad Tabular integration vs the gigachad bessel function

  • @zcrimson4735
    @zcrimson4735 3 года назад

    In Malaysia syllabus we used LPET , logarithm, polynomial, exponential and trigo.

  • @fanofabdevillersandmathslo5960
    @fanofabdevillersandmathslo5960 3 года назад +2

    We indians learned ILATE rule
    this also we don't use maximum cases
    We apply integration by parts
    By just checking which is more preferable to integrate

  • @julianamaths
    @julianamaths Год назад

    I have never taught that LIATE method and I get slightly annoyed when students ask me about it. That is because integration by parts is SUPPOSED to be difficult, you are supposed to struggle to make that choice because the struggle is how you learn and become gradually comfortable with the concepts. If it becomes just an algorithm to memorize and apply, then there is literally no point to studying this, you might as well just ask Photomath to do your integrals for you because you are not learning anything.

  • @unkennyvalley287
    @unkennyvalley287 3 года назад +2

    The way i teach it, its usually usable if there is no composite function involved in the integrand.

  • @hiiamelecktro4985
    @hiiamelecktro4985 2 года назад +1

    Never heard of LIATE. Though for a sec that was an weird English abbreviation for “Integrating by parts” because I didn’t learn math in English (also never had an equivalent to LIATE taught to me).
    So I thought this video was about why you didn’t teach integrating by parts. Lmao

  • @practical_ducky
    @practical_ducky 8 месяцев назад +1

    sir u look like a "LAOXIAN"- for those who don't know(laoxian means oldmonk with crazy abilities.)

  • @joshuapaulorigenes1936
    @joshuapaulorigenes1936 3 года назад +1

    he's morphing to an ancient philosopher video by video lol

  • @dave-bk6vt
    @dave-bk6vt 3 года назад +2

    Another (UK) who hasn't seen this before
    As I understand it, it helps in a lot of occasions, but you can't always see when it *won't* work

  • @Ug_TRADERs_OFFICIAL
    @Ug_TRADERs_OFFICIAL 6 месяцев назад +2

    It's not LIATE IT'S ILATE

  • @chetanrawat8848
    @chetanrawat8848 Год назад +1

    liate is typical in this question . So,Without using liate answer is comming --(1/2) cos(x^2 ) +c

  • @schnitzel9003
    @schnitzel9003 2 года назад

    I feel like another way of integration people should start utilizing more often is identifying forms of derivatives within the integrand. Whenever I can, I prefer to skip using some sort of U-sub or By Parts simply because I have the opportunity to use algebraic manipulation to force the integral in the form of a derivative. With the integral of lnx/(1+lnx)^2, I couldn't help but to think it may be some quotient rule in disguise, so you can end up rewriting the numerator as 1*(1+lnx) - x*(1/x), 1 being the derivative of x and 1/x being the derivative of (1+lnx), so from there you can identify that its the derivative of x/(1+lnx) by the quotient rule.

  • @realmetatainment1242
    @realmetatainment1242 Год назад +1

    Off by a minus sign on that last integral.
    My students call LIATE Larbage.

  • @HeavyMetalMouse
    @HeavyMetalMouse 3 года назад +1

    We shall call your method the Beach Boys method, because... "Wouldn't it be nice?" :)

  • @Luigi_Luigi2401
    @Luigi_Luigi2401 8 месяцев назад +1

    4:49 we just took this in class today and a student kept integrating by parts till he had about 10 terms because he didn't add the integration of sec^3 x on both sides 😂

  • @phanhunghieu2001
    @phanhunghieu2001 3 года назад

    Just follow the first trick, log second polynomial trigonometric trigonometric quadrangular

  • @potatomine5253
    @potatomine5253 2 года назад +1

    My math teacher was very simple about this, "try to find what would be the most convenient way to solve it"

  • @pradoalan6818
    @pradoalan6818 Год назад

    3:15 5:50 10:20 12:32

  • @bhuvaneshwarmarri4184
    @bhuvaneshwarmarri4184 3 года назад +1

    I use the easy method one not like ilate or liate . We can get same answer by any method.

  • @refilweramahlo8532
    @refilweramahlo8532 Год назад

    WHAT TO INTERGRATE USE *DETAIL* METHOD D-DX, E- EXPONENT,T -TRIG,A-ALGEBRA, INVERSE,LOG
    😃😃😃😃WATCHING FROM SOUTH AFRICA

  • @howardhsiao6530
    @howardhsiao6530 2 года назад +1

    1:53 blackpenredpen becomes blackpenredpenbluepen 😂

  • @Peter_1986
    @Peter_1986 Год назад

    One thing that I like about studying the later math courses in university is that the teachers for those courses don't care how I solve an integral - they are basically like "just solve this integral in some way", and only care about the answer. I am even allowed to use Wolfram-Alpha for example problems during classes if I feel like it, lol.

    • @carultch
      @carultch Год назад

      That's pretty much what you'd do in the real world anyway. Unless you are competing in MIT's integration bee, or discovering new mathematics, chances are, you'll have access to Wolfram Alpha in any situation outside an academic exercise, where you'd need to compute an integral.
      The reason teachers who initially teach the method, want you to use the method they teach, is to make it easy to grade. Once it's no longer the main substance of the topic you're working with, no one will care what specific method you choose.
      In computer science, you might need to know how to strategically pick the method that is least computationally intensive, to make your program more efficient, when it will have to do hundreds if not thousands of repeats of it, but that's the only time I can see a right or wrong choice of method, when faced with two options that get you the same solution.

  • @Salah-fn
    @Salah-fn 2 года назад +1

    OMG the integral at 9:05 I just didn't solve it with LIATE I solved it using partial fractions can't believe it 😋😋😋😋 wish u can see my solution it gave the final answer directly 😂😂

  • @flacko263
    @flacko263 2 года назад +1

    you are a GOAT..... the beard makes sense now

  • @Julian_Ree_Kyrell
    @Julian_Ree_Kyrell 10 месяцев назад +1

    The hardest integral I solved with integration by parts was x*sin(x)*e^x - I did it with a double D-I-method, idk if it could have been easier

    • @carultch
      @carultch 8 месяцев назад +2

      There are two ways for this triple product of x, sin(x), and e^x. One method is to use complex numbers, to rewrite sin(x)*e^x as a sum of two complex exponential functions, which will be i/2*e^([1 - i]*x) - i/2*e^([1 + i]*x). Pull the i/2 out in front as a constant, and assign constants N = 1 - i and P = 1 + i, to simplify our writing. Now you can integrate i/2*x*[e^(N*x) - e^(P*x)], with only one IBP table, after pulling i/2 out in front as a constant, and it is a simple ender. Then convert it back to the real world.
      Another way you can do it, is to assign J and K such that:
      J = integral sin(x)*e^x dx, and
      K = integral cos(x)*e^x dx
      Suppose we've previously solved these two integrals. The results are:
      J = 1/2*[sin(x) - cos(x)]*e^x
      K = 1/2*[sin(x) + cos(x)]*e^x
      We'll use J & K, as we construct our IBP table. Let sin(x)*e^x be integrated, and x be differentiated:
      S _ _ D _ _ I
      + _ _ x _ _ sin(x)*e^x
      - _ _ 1 _ _ J
      + _ _ 0 _ _ integral J dx
      Construct our result:
      x*J - integral J dx
      Since J is a linear combination of sin(x) and cos(x), this means integral J dx is a linear combination of J & K:
      integral J dx =
      1/2*J - 1/2*K
      Thus, our result is:
      x*J - [1/2*J - 1/2*K] =
      (x - 1/2)*J + K/2
      Fill in J & K:
      (x - 1/2)*1/2*[sin(x) - cos(x)]*e^x + 1/4*[sin(x) + cos(x)]*e^x
      Consolidate and simplify, and add +C:
      1/2*[x*sin(x) - x*cos(x) + cos(x)]*e^x + C

  • @abhijiths5237
    @abhijiths5237 3 года назад

    I mean ILATE is easier to memorize and teach to students and u can identify the integral faster rather than trying to find which one can be integrated. Also integrals having both as same function are rarely seen in school level math at least in my schools

  • @wellcubed9626
    @wellcubed9626 3 года назад

    "wudanibinais"gets me everytime

  • @imRJD14
    @imRJD14 3 года назад

    ILATE is not useful at all
    It's always better to understand the problem by intuition
    This helps more

  • @TozzaYT
    @TozzaYT 10 месяцев назад +1

    7:15 how did you know to stop there?

  • @michelleteresaantony
    @michelleteresaantony 7 месяцев назад +5

    Was anyone else taught ILATE instead?

  • @RughsterOscar
    @RughsterOscar 3 года назад +1

    Someday I want to learn english totally to learn about Calculus 2. It's too difficult for me. TY for your videos

  • @NonTwinBrothers
    @NonTwinBrothers 3 года назад

    Remember when bprp had a whole university whiteboard to make his videos?

  • @blankbuffer8996
    @blankbuffer8996 3 года назад +1

    Well for the integral(ln(x)/(1+ln(x))^2 ,x) you can solve this with just u sub and integration by parts using the LIATE method. No need for creativity on that one
    Let u = 1+ln(x)
    integral( ln(e^(u-1))*e^(u-1)/u^2 ,u)
    this simplifies and expands to
    integral(e^(u-1)/u ,u)-integral(e^(u-1)/u^2 ,u)
    then integral(e^(u-1)/u^2 ,u) use integration by parts by integrating 1/u^2 turning into -e^(u-1)/u+integral(e^(u-1)/u ,u)
    this means the integral(e^(u-1)/u ,u)-integral(e^(u-1)/u^2 ,u)=integral(e^(u-1)/u ,u)-( -e^(u-1)/u+integral(e^(u-1)/u ,u))
    that simplifies to e^(u-1)/u
    putting x back you get the x/(1+ln(x))

    • @chanuldandeniya9120
      @chanuldandeniya9120 Месяц назад

      Nah it's wrong. You get ((u-1)×e^(u-1))/u² which again needs to be solved with a "creative" integration by parts😂

    • @blankbuffer8996
      @blankbuffer8996 Месяц назад

      @@chanuldandeniya9120 Expand the expression (u-1)*e^(u-1)/u^2 into two fractions and you get e^(u-1)/u-e^(u-1)/u^2. One of these fractions can be integrated separately as I have shown above using Integration by parts. I should have made the step where I separated them more clear but yes what you have is an intermediate step. I guess what makes my solution creative is that the integrals cancel out rather than being fully computed.

  • @debanjanchakraborty9946
    @debanjanchakraborty9946 3 года назад +1

    There is somerhing called the reduction formula in integration so reduction formulae is a special case for integration by parts

  • @dr_rich_r
    @dr_rich_r 2 года назад +1

    For most of our IBP problems, when we have a transcendental function and a power function, if the derivative of the transcendental function becomes algebraic, then it is u, if it stays transcendental, then it is with dv.

  • @juanjuan-mi4gi
    @juanjuan-mi4gi 3 года назад

    You can with integral zero-infinity x^2 e^-x^2 /1-e^-x^2 ?

  • @vijaykulhari_IITB
    @vijaykulhari_IITB 3 года назад +2

    Sir you are the lord of mathematics 😀😀🥳🥳

  • @santoshmishra5993
    @santoshmishra5993 2 года назад +1

    At 10:00 assume lnx to be t. dx equal to e^t dt and then apply by parts
    THAT'S IT

  • @chriswong7928
    @chriswong7928 3 года назад +1

    you better remove your beards.

  • @alberteinstein3612
    @alberteinstein3612 3 года назад +17

    Integrals will always remain my favorite part of Calc I and II
    They’re so fun to do! ❤️🥳

    • @EatonArrsenik
      @EatonArrsenik 2 года назад +1

      🧐😈Canon

    • @kepler4192
      @kepler4192 2 года назад +2

      I find derivatives more fun imo

    • @fantiscious
      @fantiscious 2 года назад +1

      @@kepler4192 ok. differentiate sin(cos(tan(csc(sec(cot(sinh(cosh(tanh(csch(sech(coth(arcsin(arccos(arctan(arccsc(arcsec(arccot(arcsinh(arccosh(arctanh(arccsch(arcsech(arccoth(x))))))))))))))))))))))))

    • @fantiscious
      @fantiscious 2 года назад +1

      in respect to x

  • @vijaykulhari_IITB
    @vijaykulhari_IITB 3 года назад +1

    Right LIATE rule is (3rd example) assume secx a and assume sec^2x b and solve [a (integral b)-[integral (derivative a).(integral b)]]