The Final Answer Was Wrong When You're Writing Yp=A.U(x)+B.V(x) You Have Written Only Half Off The Value Of A.U(x) You Skipped To Write (1/a^)sinax The Final Answer Will Be: Y=C1Cosax+C2Sinax-(1/a^)Log(secax+tanax).
Maam at 7:32 you missed to write the second term for A which is 1/a^2 cosax sinax…..Therefore the last term you wrote at 8:18 should be cancelled and should not be there
1.Calculate yc for example yc=C1cosα+C2sinβ Now take U=Cosα V=sinβ 2.Calculate UV¹+U¹V 3.yp=AU+BV 4.A=-VR/UV¹+U¹V B=UR/UV¹+U¹V 5.General Solution y=yc+yp
Mam your way of explanation is good but need to slowdown a bit not even giving a second to note it down and also explain it on board then it will be clear to understand
Really nice mam
Way of presenting the problem and solution is excellent madam
Thanks 🙂
Mam answer lo A value full ga ledhu
The Final Answer Was Wrong
When You're Writing Yp=A.U(x)+B.V(x)
You Have Written Only Half Off The Value Of A.U(x) You Skipped To Write (1/a^)sinax
The Final Answer Will Be: Y=C1Cosax+C2Sinax-(1/a^)Log(secax+tanax).
Ok...plz continue ..
Bro final answer is : y=c1cosax+c2sinax-(1/a^2) log(secax+tanax) cosax.
@@bitupankalita2833 where is 1/a^2 sinax went
@@srinithchary5012 yes same question
Super mam awesome
Super thanks for the explanation madam
Clear explanation mam thank you ❤️
🎉🎉
Where the 1/a^2sinax?
Tqq mam
Thank u mam
🎉💐🎉💐
very nicely explained
🎖️💐💐
Thanks for this video mam I am satisfied
💯
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Thank u madam , your videos was very helpful to my supply exams. Do more videos for students❤🎉
All the best🏆✨
Maam at 7:32 you missed to write the second term for A which is 1/a^2 cosax sinax…..Therefore the last term you wrote at 8:18 should be cancelled and should not be there
👍👍
Thanqq so muchh mam .😇
✨🎉✨🎉
Very good 🎉🎉🙏teaching Medam.... 🎉🎉
Satish..It's wonderful to see you in this channel🎉🎉
@@btechmathshub7050 wonderful teaching Medam.. I don't see this type of teaching 🎉🎉👍👍👍👍🙏🙏
Very useful
Love you mam
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Thank you so much for explanation mam❤❤
Happy to help💝
Thank-you so much mam
Keep watching plz..✨✨
Thanks madam
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Nice mam
Thank you mam 💙
Nailed it madam 🙌
Tinku💐
Nice 👍 explanation
Tq..🎉🎉
We love your teaching mam
Thanks you very much mam 💐
Mam solve (d^2+4^2)y=tan2x by the method of parameters how to solve mam
In place of a put 2 and proceed same method
Mam I wil be the producer for ur stationary mostly on papers 😁😁
Ganesh....I need best score from you💯💯✨✨
Can you explain about curve tracing and function of several variable
Last step totally confused pls explain clearly
pls keep a link for working rule of this method variation of parameters
1.Calculate yc for example yc=C1cosα+C2sinβ Now take U=Cosα V=sinβ
2.Calculate UV¹+U¹V
3.yp=AU+BV
4.A=-VR/UV¹+U¹V B=UR/UV¹+U¹V
5.General Solution y=yc+yp
Mam make a video on CAUCHY- EULER EQUATION
tomorrow...
Srinivas...posted videos! Practice n definitely you will feel easy.
Mam your way of explanation is good but need to slowdown a bit not even giving a second to note it down and also explain it on board then it will be clear to understand
Abhi...definitely I'll follow✨
Excellent explanation ❤️
Rohith..tq🎉
Please improve the handwriting madam .. some words / letters are so hard To understand
Certainly ✨
Bro madam hand writing is good bro
Mam please solve my doubt , you have told" A " value to be substitute in general solution" y " in this Yc is not substitute completely why
yp=AU+BV
Madam ... I have one doubt.. in A value, Last +1/a square.sinax mam but at the end Au(x)+B(v)x U didn't written Last value mam...Y???
AU+BV=-1/a²log(secax-tanax).cosax+1/a²sinax.cosax -1/a2.cosax.sinax see last two terms got cancelled
Mam u don't cancel B value in Y at last
Super explanation
Total simple substitution mistakes
Mention the minutes where you found mistake I will clarify