For anyone wondering why the axis of symmetry was found instead of the roots of lambda, its because the question wants the midpoint of chord, so this way its a bit faster to get to the vector we want. (I think)
Sir i am a student of mathematics.I am from Bangladesh.Few days ago i saw your first video.It was a very good explanation of that math.It was very helpful for me.I am a big fan of you.My dream is also to be a Mathematician.
I am happy for giving me such lectures Actually i left maths because i thought it was so much burden but still i love math and study it because of you.
My first instinct was to think of the circle as: x=1+3cos(theta), y=-2+sin(theta) and the line as: x=2+lambda, y=1+2lambda Then set them equal and rearrange so cos and sin on one side and everything on the other. Then square both sides, and substitute into cos^2(theta)+sin^2(theta)=1 and solve the resulting quadratic. I actually did the whole calculation with the radical and everything.. and got the same answer (0.6, -1.8) in the end, it felt wrong to substitute lambda (-0.07335...) and (-2.7266499...), and then you just skipped all that decimal work using logic. Just goes to show work smarter not harder lol
At around 6:30, you shouldn't be able to just write lambda = -b/2a as the next line immediately, since it's not really giving a solution to the previous line's quadratic. Should be fine if you clarify further what you're doing, like saying "taking the average of the roots" and using a different name for the variable or writing it as (lambda_1 + lambda_2)/2 though, right?
Now put the circle or make it an eliptical for the fun of it, and have a calculator rotate this around itself without making the calculator heat up. Did this for my HP48GX back in the day; '95/'96 or so, and the screen started fading away after about 15 mins.
For anyone wondering why the axis of symmetry was found instead of the roots of lambda, its because the question wants the midpoint of chord, so this way its a bit faster to get to the vector we want. (I think)
Sir i am a student of mathematics.I am from Bangladesh.Few days ago i saw your first video.It was a very good explanation of that math.It was very helpful for me.I am a big fan of you.My dream is also to be a Mathematician.
I am happy for giving me such lectures
Actually i left maths because i thought it was so much burden but still i love math and study it because of you.
barely no one teaches vectors....
BUT eddie is to the rescue!
Beginning: what's going on?
Middle: oh..
End: OH! That's cool!
My first instinct was to think of the circle as: x=1+3cos(theta), y=-2+sin(theta)
and the line as: x=2+lambda, y=1+2lambda
Then set them equal and rearrange so cos and sin on one side and everything on the other. Then square both sides, and substitute into cos^2(theta)+sin^2(theta)=1 and solve the resulting quadratic.
I actually did the whole calculation with the radical and everything.. and got the same answer (0.6, -1.8) in the end, it felt wrong to substitute lambda (-0.07335...) and (-2.7266499...), and then you just skipped all that decimal work using logic. Just goes to show work smarter not harder lol
👍
❤️
At around 6:30, you shouldn't be able to just write lambda = -b/2a as the next line immediately, since it's not really giving a solution to the previous line's quadratic. Should be fine if you clarify further what you're doing, like saying "taking the average of the roots" and using a different name for the variable or writing it as (lambda_1 + lambda_2)/2 though, right?
Thank you very much for coming out and explaining my doubts as well.
Hey do you do tutoring ???
Now put the circle or make it an eliptical for the fun of it, and have a calculator rotate this around itself without making the calculator heat up. Did this for my HP48GX back in the day; '95/'96 or so, and the screen started fading away after about 15 mins.
👍