Calculating Effect Size (Cohen's d) for a Paired-Samples T Test

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  • Опубликовано: 6 фев 2016
  • This video demonstrates how to calculate the effect size (Cohen’s d) for a Paired-Samples T Test (Dependent-Samples T Test) using SPSS and Microsoft Excel. Cohen’s d expresses the difference in the sample means using standard deviation units.

Комментарии • 64

  • @joelcagwin3593
    @joelcagwin3593 7 лет назад +3

    Thank you for running this. I particularly appreciated how you showed gathering the information from the SPSS output for the equations in Excel

  • @bradleyfairchild1208
    @bradleyfairchild1208 7 лет назад

    Second time to watch and more stood out on the significance of Cohen's d and how it relates to the p value. Thanks Dr. Grande, very helpful.

  • @felicityneale5703
    @felicityneale5703 7 лет назад

    Thank you so much. This was crystal clear, and extremely helpful for my first unit of stats in my psychology grad dip.

  • @rglueckauf
    @rglueckauf 2 года назад

    Excellent explanation of Cohen's d calculation using paired samples

  • @DanielSolisQuetzal
    @DanielSolisQuetzal 5 лет назад +1

    Thank you for the explanations Dr. Grande, always very useful. This is the second time I see someone referring to =0.8 as large and citing Cohen. But I read the book and its says d=0.2 small, d=0.5 medium, d=0.8 large (p. 25 to 27). I couldn't find any reference of him talking about intervals. Most importantly, in Illustrative Example 2.6 (p. 50) he gets d=0.4 and he himself classifies it as "small to medium value". I've seen other researchers saying 0.7 large, and citing Cohen. And others simply saying that it is "around" 0.2, 0.5 and 0.8, which is what I found in the book. I'm using the "around" version so far, but I'm worried to be wrong. Please, could you tell me on what page of Cohen (1998) is the reference where he says that 0.2, 0.5 and 0.8 are the lower bounds and not anchors around which small, medium and large can be considered?

  • @nikoloztarielashvili6281
    @nikoloztarielashvili6281 5 лет назад +4

    very good explanation, thank you, I was able to understand everything , and great that you have used these two different method! :) Have a good one! :)

  • @Simon-zo1vf
    @Simon-zo1vf 6 лет назад

    Awesome, excellent video! I clicked myself through dozens websites, nowhere I understood how the d is computed. Here you explained it very easy, thank you!

  • @the1andonlytitch
    @the1andonlytitch 8 лет назад +1

    Thanks man this video helped me with my dissertation

  • @barbarabustamante565
    @barbarabustamante565 4 года назад +1

    Otro excelente video! Gracias Dr. Grande!

  • @alexstrauss2313
    @alexstrauss2313 5 лет назад +1

    Super helpful Dr. Grande. Thank you for this!

  • @sarahallen8229
    @sarahallen8229 4 года назад

    This was so helpful, thank you very much!

  • @abeer6187
    @abeer6187 7 лет назад

    The best I have came across, please do more videos , Thanks

    • @DrGrande
      @DrGrande  7 лет назад

      You're welcome, thanks for watching -

  • @hosseinrafiei6465
    @hosseinrafiei6465 5 лет назад +1

    Really helped! Thanks very much!

  • @alejandrodominguezrodrigue2380
    @alejandrodominguezrodrigue2380 4 года назад +1

    Thank you very much! very clear and very helpful. Best regards,

  • @mzsimplybeth
    @mzsimplybeth 6 лет назад

    This video was of great assistance!! Thank you so much!!

    • @DrGrande
      @DrGrande  6 лет назад

      You are quite welcome!

  • @halealkan7940
    @halealkan7940 6 лет назад

    Thank you su much! I learned more from you than my statistics teacher.

    • @DrGrande
      @DrGrande  6 лет назад

      I'm glad to here my videos have been useful - thanks for watching -

  • @S.Ayhan.CALISKAN
    @S.Ayhan.CALISKAN 4 года назад +1

    It was very useful. Thank you very much .
    ✅ 😊👍

  • @mariemccaskill2139
    @mariemccaskill2139 6 лет назад

    Dr. Grande, Thank you! I am post-PhD and found your video very helpful!

  • @samahabdelrahman1702
    @samahabdelrahman1702 6 лет назад

    Thank You, very useful

  • @samuelwest2551
    @samuelwest2551 5 лет назад

    Thanks for the great video - how would I compute the 95% confidence interval around this effect size estimate?

  • @user-gd7lx5zt2n
    @user-gd7lx5zt2n 7 лет назад

    Thank you very much for your excellent videos

    • @DrGrande
      @DrGrande  6 лет назад

      You are welcome - thanks for watching -

  • @cindycedeno5720
    @cindycedeno5720 4 года назад +1

    Thanks for the explanation! May I ask how to apply the effect size to the results of Wilcoxon test? (or what criteria should be considered when it comes to this non-parametric test) Is the computation equal? (d= mean difference/Std. deviation of the difference)
    Thank you

  • @tangeoktin9295
    @tangeoktin9295 6 лет назад

    Thank you so much!
    Is it necessary to calculate cohen's d if we reject hypothesis null? what if i get negative value for the value of cohen's d?

  • @tommoore4565
    @tommoore4565 4 года назад

    Hi, thanks for the explanation. I was wondering if you would be able to explain how researchers present the effect size in academic papers?

  • @becklutz3200
    @becklutz3200 6 лет назад

    Fantastic video, thank you!

  • @arielgoldstien1492
    @arielgoldstien1492 7 лет назад

    Thank you very much for the clear video. Can you give a reference for this calculation?

  • @kimeeshareedwalker3263
    @kimeeshareedwalker3263 7 лет назад

    Again excel required many functions to reach a result. Hands on will provide a better understanding. Good start

  • @jj-et4sj
    @jj-et4sj 6 лет назад

    thank you so much! This video is extremely helpful!!!!! C:

  • @naftalibendavid
    @naftalibendavid 6 лет назад

    You are great!

  • @hectorponce2012
    @hectorponce2012 3 года назад

    What about if i use the formula used by Dunlop et al. (1996)? d = t calculated times the square root of (2*(1-r))/n?

  • @jinghuing1208
    @jinghuing1208 Год назад

    Hi, if i got negative value for my effect size, what does it indicate? My test is significant to test for the increase of gratitude level

  • @lizgoldstein4256
    @lizgoldstein4256 Год назад

    When I want to calculate Cohen's d for two treatments from the same sample and I run a paired t-test in Excel, it doesn't give me the SD, so I don't know how to calculate Cohen's d by the SD by the mean. Any chance you can help?

  • @alexsisccdr
    @alexsisccdr 6 лет назад

    Is it possible to get your excel ?

  • @mercedesandrade
    @mercedesandrade 6 лет назад

    if you fail to reject the null hypothesis in a paired samples t-test, does that mean you don't have to calculate the effect size? Therefore, you only calculate the effect size when you reject the null hypothesis?

    • @DrGrande
      @DrGrande  6 лет назад

      Usually we only calculate the effect size if we can reject the null hypothesis, although it is possible to calculate the effect size either way.

  • @runezahl-olsen1081
    @runezahl-olsen1081 7 лет назад +2

    Could you explain why the effect size is different using the calculation mentioned in Your video than the more commonly used method for calculating Cohen's d: d=(M1-M2)/SD pooled

    • @doctorHJ
      @doctorHJ 7 лет назад

      this also confusing me.

    • @user-gd7lx5zt2n
      @user-gd7lx5zt2n 7 лет назад

      the value 2.34 is (M1-M2) in SPSS

    • @puttle1
      @puttle1 6 лет назад +1

      The pooled SD is commonly used for independent-samples t tests

    • @marjoleinfokkema
      @marjoleinfokkema Год назад

      The proposed computations in the video do not conform to the definition of Cohen's d. With the proposed computation, if each person in the sample would increase or decrease with the exact same amount (however small or large), then this would yield an effect size of (minus) infinity. The proposed 'effect size' says something about the variability of the effect, but nothing about the strength of the effect. To obtain an actual effect size, one should divide the mean difference by the pooled pre- or post-test standard deviation.

  • @danablum539
    @danablum539 6 лет назад +1

    i had a problem calculating cohen's d. my t value is 7.00 and my N=20 and my calculation turned out to be more than 1... how is that possible?

    • @DrGrande
      @DrGrande  6 лет назад +1

      The value of Cohen's d can exceed 1. This statistic is the standardized difference between two means. A value of 1 indicates the difference between the means is 1 standard deviation. Eta-squared and partial eta-squared are also measures of effect size, however, they cannot exceed 1. Perhaps this video will help: ruclips.net/video/n8wEqY_jytg/видео.html

    • @faridalakhel1923
      @faridalakhel1923 5 лет назад

      dana blum hello, I also fonded cohen's d more than 2, tell me please, what is the problem😣😢

  • @maikonunico
    @maikonunico 7 лет назад

    Do you have a reference for second equation? I need to write my paper..

  • @sarahissac2301
    @sarahissac2301 2 года назад

    We need the excel sheet. how can we get it?

  • @kyratulamira
    @kyratulamira Год назад

    but how about if we have more than one pair?

  • @faridalakhel1923
    @faridalakhel1923 5 лет назад

    Hello , I found it more than 2 , what is the problem please.

    • @jannahasnirul7202
      @jannahasnirul7202 5 лет назад

      I am too. Anybody can help to explain that? 😟

    • @marjoleinfokkema
      @marjoleinfokkema Год назад

      Dividing the mean difference by the standard deviation of the differences does not conform with the definition of Cohen's d. With this computation, if each person in the sample would increase or decrease with the exact same amount (however small or large), then this would yield an effect size of (minus) infinity. The proposed 'effect size' says something about the variability of the effect, but nothing about the strength of the effect. To obtain an actual effect size, one should divide the mean difference by the pooled pre- or post-test standard deviation.

  • @marjoleinfokkema
    @marjoleinfokkema Год назад

    Dividing the mean difference by the standard deviation of the differences does not conform with the definition of Cohen's d. With this computation, if each person in the sample would increase or decrease with the exact same amount (however small or large), then this would yield an effect size of (minus) infinity. The proposed 'effect size' says more about the variability than about the strength of the effect. To obtain an actual effect size, one should divide the mean difference by the pooled pre- or post-test standard deviation.

  • @TheKrzyniu
    @TheKrzyniu 5 лет назад

    kind of looks like a dz to me? but I'm not expert