Diffraction Lecture 15: Reciprocal Space

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  • Опубликовано: 12 сен 2024

Комментарии • 11

  • @corpushypercubus4587
    @corpushypercubus4587 Год назад +8

    Clarified this concept for me in the first 45 seconds. Thank you!

  • @bogdanorlioglo6126
    @bogdanorlioglo6126 2 года назад +9

    Dear Professor Woodward, there's a typo on the 'Hexagonal Lattice' slide, b* should be perpendicular to a, not to b. Thank you for the videos, they are very helpful!

  • @Melisaakcm
    @Melisaakcm 10 месяцев назад +5

    Hi Prof., in hexagonal reciprocal lattice space why b* is perpendicular to b, and a* to a, but in orthagonal systems b* is parallel to b and vice versa?

  • @ΚωνσταντίνοςΛαζαρίδης-ξ9ι

    Thank you sir! Well expained.

  • @Jason-sq7cc
    @Jason-sq7cc Год назад +1

    Hi Professor, in lecture 14, you said in 3d the condition of diffraction on the detector looks like circles. Could you elaborate on why it is true? And why does that coincide with the fact that the diffraction peaks are located on the reciprocal lattice? Thank you!

  •  Месяц назад

    is there a wrong about position of the a* and b* in 11:07?

  • @JK-kh1co
    @JK-kh1co 3 месяца назад

    Dear Professor,
    I have a simple question:
    Kroneker's delta is defined based on the cubic lattice?

  • @kaushikumarihami1982
    @kaushikumarihami1982 Год назад

    excellent explanation

  • @ThangPVan_
    @ThangPVan_ 9 месяцев назад

    thanks, sir

  • @qqokhann
    @qqokhann 5 месяцев назад

    What is the value of 'V' ?