This is the proof I was looking for, being able to understand the REASON that the derivative is orthogonal is very helpful in remembering it. Thank you
I wish I had seen this video when I was Haydn's age here. I had just graduated high school and already missed some parts of math to understand calculus. I just had a revelation in linear algebra my professors never mentioned. Don't these teacher know how to make math easier? Kudos to Haydn.
Thank Sir!! I have a question: since the squared magnitude of a unit tangent vector is (1). does that mean the normal vector is always equal to the derivative of the unit tangent vector?
The normal vector is not always the derivative of the unit tangent vector. In the definition of N at 6:35, notice that we divide by the magnitude of T', not the magnitude of T. Even if T is a unit vector, T' might not be!
thank you this really helped me I have a question so unit normal vector is second derivative of position vector which is actually acceleration. so is it normal component of acceleration
so in what follows, you said is that unit normal vector is perpendicular to the unit tangent only if the magnitude of the unit tangent vector is constant. What if that is not the case? can you please help me out.TIA
We set the unit tangent vector to always have magnitude 1 by dividing by |r'(t)|. It is called the "unit" tangent vector because it always has magnitude 1 by definition.
This is the proof I was looking for, being able to understand the REASON that the derivative is orthogonal is very helpful in remembering it. Thank you
I wish I had seen this video when I was Haydn's age here. I had just graduated high school and already missed some parts of math to understand calculus. I just had a revelation in linear algebra my professors never mentioned. Don't these teacher know how to make math easier? Kudos to Haydn.
Thank you so much! Straight to the point with algebraic and geometric proofs on why they're orthogonal.
Great video.
I am excited to see how your teaching evolves and grows! Subscribed.
Excellent excellent excellent, I loved how you explained EVERYTHINGGGGGGGGGGGGGG!!!!!!!!!!! Thank you.
This was exactly what I was looking for. Your proofs are simple and easy to understand. Thanks
고정된 상수값을 원으로 생각하니 이해가바로되네요!
Great work ! Ty so mutch . Love from a future chemeng
God bless your soul. This video has been so helpful!
Great video. You explained it the best way possible.
Thanks but do we only need the unit tangent vector? because we just divided r't (vector) with it's magnitude
That was such an excellent explanation, please keep up the good work!
Great video, super helpful! Great work!
He is fast and impressive but I have to continual reverse to process. I just have to subscribe.
Very talented buddy, nice one
Thank Sir!! I have a question: since the squared magnitude of a unit tangent vector is (1).
does that mean the normal vector is always equal to the derivative of the unit tangent vector?
The normal vector is not always the derivative of the unit tangent vector. In the definition of N at 6:35, notice that we divide by the magnitude of T', not the magnitude of T. Even if T is a unit vector, T' might not be!
@@MuPrimeMath Thanks!
Thank you, sir, it has been really helpful!
Brilliant explanation ! Thank you ❤
Enlightnng explanation! Thanks .
really cool video congrats
Damn clean explanation, thank you.
thank you this really helped me
I have a question so unit normal vector is second derivative of position vector which is actually acceleration.
so is it normal component of acceleration
100 times better than my Professor
oo what a way do describe . respect from Pakistan
Awesome video!
Great video man!
good explanation sir.
smashed the like thanks lad
You are best.
In which University are you studying ??
I made this video in high school! I'm currently studying at Caltech.
so in what follows, you said is that unit normal vector is perpendicular to the unit tangent only if the magnitude of the unit tangent vector is constant. What if that is not the case? can you please help me out.TIA
We set the unit tangent vector to always have magnitude 1 by dividing by |r'(t)|. It is called the "unit" tangent vector because it always has magnitude 1 by definition.
@@MuPrimeMath yeah right, thank you
Thank for uploading
why the derivate of the tangent vector is normal to the tangent vector
Thanks bro, from india
❤️❤️❤️
Sir you know Bengali language please please please ektu bolun
Definite integral of 1/sqrt(1-x^4) between 0 to 1 ..please...
save me in college ❤
Definite integral of 1/sqrt(1-x^4) between 0 to 1 ..please...
Definite integral of 1/sqrt(1-x^4) between 0 to 1 ..please...
The only way to do this is with elliptic integrals, which are a type of non-elementary function.