TRICK TO FIND OUT NO.OF LONE PAIRS with 👉 NEET, JEE questions👍

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  • Опубликовано: 15 янв 2025

Комментарии • 89

  • @ganeshjaggineni4097
    @ganeshjaggineni4097 4 года назад +2

    Nice super excellent motivated

  • @manishayadav8426
    @manishayadav8426 Год назад +1

    Thanks a lot sir

  • @MrAbhishek-nn7ld
    @MrAbhishek-nn7ld 2 года назад +2

    Understood sir tq

  • @m.vsubbareddy7686
    @m.vsubbareddy7686 3 года назад +9

    I have seen this trick before Feb jee, forgotten. Before July jee, confused. And in August now, for my Eamcet. I think, I will get it to my mind.thanks sir. But, this is so sweet trick. It saved me Alot times. I mean, you saved me alot and lot times. So I have given such importance and watched thrice and thrice. Glad to have online teachers like you sir. Bless me finally sir , please

  • @SayedMuhammadMuhammadSayed
    @SayedMuhammadMuhammadSayed 9 месяцев назад +1

    Thanks😊😊😊😊

  • @silverstarkhonglahofficial4517
    @silverstarkhonglahofficial4517 2 года назад +2

    Great explain sir💕💟

  • @SumpathK
    @SumpathK Год назад +1

    thank you sir.

  • @anuverma4698
    @anuverma4698 3 года назад +2

    Very informative ⭐

  • @MrAbhishek-nn7ld
    @MrAbhishek-nn7ld 2 года назад +1

    Tq sir this Vido very helpful

  • @chokkakulayerrinaidu5083
    @chokkakulayerrinaidu5083 4 года назад +2

    Excellent explanation sir

  • @rishijoseph3534
    @rishijoseph3534 3 года назад +2

    Thank you so much.. All these years. I didn't understand.. Just 16mins video I could understand the concept

  • @kabitajena2622
    @kabitajena2622 3 года назад +1

    nice trick for jee and neet aspirants

  • @meghanaganapathy408
    @meghanaganapathy408 3 года назад +1

    Tnq sir

  • @udayphanindrakanamarlapudi4437
    @udayphanindrakanamarlapudi4437 3 года назад +4

    Thank you so much sir and your Explaination is soo good 👌👌

  • @shivanim8461
    @shivanim8461 4 года назад +1

    Super explanation sir upload more vedios

  • @vijaytalladi9315
    @vijaytalladi9315 9 месяцев назад

    Very useful

  • @vijaytalladi9315
    @vijaytalladi9315 9 месяцев назад

    Very good

  • @pragnachowdary6228
    @pragnachowdary6228 3 года назад +3

    Really ossum sir 😍😍 Understood very clearly tq sir ...keep doing more videos...

  • @Yashini-j17
    @Yashini-j17 3 года назад +1

    The way of giving tricks and teaching is wonderful Sir.... Overwhelmed by your teaching Sir.... Thankew sir🙏

  • @supriyasingh7800
    @supriyasingh7800 11 месяцев назад

    Good

  • @Asgard126
    @Asgard126 8 месяцев назад

    Holy frickin underrrratedddd ... All the best brother... Nice vdo

  • @ganeshjaggineni4097
    @ganeshjaggineni4097 4 года назад +3

    I WATCHED MANY VIDEOS ON CHEMISTRY BUT TILL THE TIME, I DONT KNOW WHY FLOURINE, CHLORINE CONTRIBUTES 1 ELECTRON FOR BOND AND WHY OXYGEN CONTRIBUTES 2 ELECTRONS FOR THE BOND.. AFTER WATCHING YOUR VIDEO, I UNDERSTAND IT.

  • @gobegas9751
    @gobegas9751 2 года назад

    Super sir

  • @raviravikumar6030
    @raviravikumar6030 Год назад +1

    Please do more videos on inorganic chemistry

  • @naveentamilvanan7000
    @naveentamilvanan7000 3 года назад

    Supper

  • @anushaneha7302
    @anushaneha7302 3 года назад +2

    Sir please upload more videos for tricks to solve questions in NEET .

    • @asnchemistry
      @asnchemistry  3 года назад +2

      Sure
      Please share to your friends

  • @inspirationalvideo1833
    @inspirationalvideo1833 4 года назад +2

    Sir your teaching skill is awesome 👌👍 that beyonds compare....thank you sir ...

  • @prabhakara7340
    @prabhakara7340 3 года назад +5

    Thank you so much sir, this helped me a lot.

    • @shivangisharma3927
      @shivangisharma3927 2 года назад

      How to calculate lone pair and bond pairs easiest trick. . . ruclips.net/video/1Menuw8iMFw/видео.html

  • @althurumasthanaiah6631
    @althurumasthanaiah6631 2 года назад +6

    For sf6 - 4bond pairs, 1 lone pair
    For C-H3 - 3 bond pairs, 1 lone pair
    For BrF5-5 bond pairs, 1 lone pair
    Is it correct sir

  • @kumarisweta1611
    @kumarisweta1611 Год назад

    Oh my God.......best teacher ever I had seen till now 🙏🙏🙏🙏🙏🙏

  • @garimarajput7750
    @garimarajput7750 2 года назад +2

    Thank u soo much sir for such an amazing explanation 🤩😇

  • @Mluke5822
    @Mluke5822 3 года назад +1

    Thanku

    • @shivangisharma3927
      @shivangisharma3927 2 года назад

      How to calculate lone pair and bond pairs easiest trick. . . ruclips.net/video/1Menuw8iMFw/видео.html

  • @basicstudyuse2041
    @basicstudyuse2041 4 года назад +2

    XeF4 = 8+4/2 = 6
    So lone pain e- = hybridation - bond pair e-
    Lone pain = 6-4 = 2

  • @adeneetha9125
    @adeneetha9125 Год назад +1

    Thnks alott😊

  • @Asgard126
    @Asgard126 8 месяцев назад

    Homework
    1) sf4 1lp+4bp
    2) ch3- 1 lp+3bp
    3) Brf5 1lp+5bp

  • @avinashhipparge9312
    @avinashhipparge9312 2 года назад

    than kn you

  • @arnavsingh2677
    @arnavsingh2677 4 года назад +6

    u explained it in most easiest way
    thank u for uploading these videos😃

    • @asnchemistry
      @asnchemistry  4 года назад

      Now,
      I am uploading videos in examsatozplus channel
      Please subscribe 🙏
      This is the link
      ruclips.net/video/lsgXifA1kHU/видео.html

  • @krishijain7300
    @krishijain7300 3 года назад

    Sir upload more videos you yeach so well

  • @naveenmydur9724
    @naveenmydur9724 3 года назад

    Thankyou

  • @kpandu6152
    @kpandu6152 2 года назад

    sir for oH- (hydroxyl ion)and NAOH tooo???

  • @premrajjadhav8871
    @premrajjadhav8871 День назад

    SF4 (l.p=1) (b.p=4), CH3- (l.p=1) (b.p=3), Brf5 (l.p=1) (b.p=5)

  • @kpandu6152
    @kpandu6152 2 года назад

    thank you soo much sir....as ur vedios very useful....now iam preparing for eamcet....these r vry vry helpful...thanks alot....

  • @Yashini-j17
    @Yashini-j17 3 года назад

    If valency of surrounding atom is 4 means? Then 4*monovalent atom?

  • @dreampeak9364
    @dreampeak9364 2 года назад

    thankyou sir finally i found such amazing explanation

  • @Krishna77508
    @Krishna77508 3 года назад

    So2 ki cheppandi

  • @arunaaakula226
    @arunaaakula226 3 года назад

    Sir corrector kado chepandi

  • @keerthanakeerthana7022
    @keerthanakeerthana7022 4 года назад

    sir plz make more video like this....now only i found your channel sir....
    for me i need your help sir for neet 2020 sir plz sir plz make more videos for us sir plz pzl

  • @dr.entropy3444
    @dr.entropy3444 3 года назад

    Thank you❤❤❤🌹

  • @neermita7587
    @neermita7587 4 года назад +1

    Sir, how will we find the lp and bp of NO3- with this trick?

    • @vipinyt3233
      @vipinyt3233 Год назад +1

      No3- means No is least in no. So negavitive charge so 6 e , oxygen make double bond so 0 lone pair

  • @jayapandey8940
    @jayapandey8940 3 года назад

    No2+ mei lone pair 1 aa rha mera is technique se but ye kese hoga please answer sir

  • @rafsumsarsad
    @rafsumsarsad 3 года назад

    Thank you sir it helped me a lot

  • @ganeshjaggineni4097
    @ganeshjaggineni4097 4 года назад +7

    SF4 : BP=4, LP=1 . C^-H3: BP=3, LP=1 . BRF5 , BP=5 , LP =1.

  • @infinity1933
    @infinity1933 5 месяцев назад

    Why does the lone pair of Nf3 come to 10?

  • @pankajneetwarrior5228
    @pankajneetwarrior5228 3 года назад

    Come and teach in Allen sir

  • @LKS_PRODUCTION
    @LKS_PRODUCTION 3 года назад

    Tq sir doubt clear 🌻

    • @shivangisharma3927
      @shivangisharma3927 2 года назад

      How to calculate lone pair and bond pairs easiest trick. . . ruclips.net/video/1Menuw8iMFw/видео.html

  • @poonamschitchats6695
    @poonamschitchats6695 4 года назад

    Please upload full chapter question solving videos sir

  • @arunaaakula226
    @arunaaakula226 3 года назад

    Sf4-4 bonds,1 loanpair.NH3-3 bond pair,1loanpair,Brf3-3 bondpair,2loanpairs

  • @selvarathinam6828
    @selvarathinam6828 3 года назад

    In I3- no of lp=9

  • @floraagastinagastin3613
    @floraagastinagastin3613 3 года назад

    Sir iodine 13 pls clear pannuga sir 3 iodine thaana podanum

  • @swathi536
    @swathi536 Год назад

    Sir Xe03 lo oxigen 3 unnaye kadha sir
    Naku ardham kaladhu sir

    • @asnchemistry
      @asnchemistry  Год назад

      Each Oxygen forms 2 bonds
      So XeO3 has one lone pair

  • @venkatroyalcreations4451
    @venkatroyalcreations4451 3 года назад

    1answeris 4bp + 1 lp

  • @jadalaprashanth9404
    @jadalaprashanth9404 3 года назад

    BRF5 =5bp-1lp

  • @gobegas9751
    @gobegas9751 2 года назад

    Sir lone pair of HNO2 hno3

  • @venkatroyalcreations4451
    @venkatroyalcreations4451 3 года назад

    2 answer is 3 bp + 1lp

  • @venkatroyalcreations4451
    @venkatroyalcreations4451 3 года назад

    3 answer is 5 bp + 1 lp

  • @jadalaprashanth9404
    @jadalaprashanth9404 3 года назад

    SF4 =4 bp-2lp

    • @mini5282
      @mini5282 3 года назад +1

      No its 4bp nd 1lp check once ☺️nd all the best

  • @jangakeerthana
    @jangakeerthana 2 года назад

    Is this trick applicable for NO3-

  • @amarjyotitripathy491
    @amarjyotitripathy491 3 года назад

    We can't found no3 minus 1 structure in this trick

  • @rachanabshetty7822
    @rachanabshetty7822 4 года назад

    Sir u told 5th-8th group element have 3,2,1,0... valence electrons..but You writtn for phosphorus 5 ..🙄🧐🤔🤔🤔

    • @asnchemistry
      @asnchemistry  4 года назад

      Those are valances (3, 2,1,0)

    • @tharuniyaaumachander5279
      @tharuniyaaumachander5279 3 года назад

      Because phosphorous is a central atom you have to consider no. Of valence electrons which is 5 .

  • @bharathiepuri9650
    @bharathiepuri9650 2 года назад

    Sf4=1- lp, 4-bp
    Ch negative 3= 1-lp, 3bp
    BrF5= 1-lp, 5-bp

  • @Studyndexplorenew06
    @Studyndexplorenew06 3 года назад +3

    SF4:- 4bp and 1 lp
    CH3negative :- 3 bp and 1 lp
    BrF5:- 5 bp and 1lp

    • @shivangisharma3927
      @shivangisharma3927 2 года назад

      How to calculate lone pair and bond pairs easiest trick. . . ruclips.net/video/1Menuw8iMFw/видео.html

  • @sunitanayak3562
    @sunitanayak3562 4 года назад

    Sir,if iam not wrong in XeF2 there is one bond pair n 3lone pair but you wrote 2bond pair by mistake.