The sine wave drawn in this video more closely resembles a 60° Phase shift instead of the intended 120°. We apologize for the confusion. All the spoken and written information is correct. Thank you for your understanding. The graphic in the blog article has the correct wave form if you are interested in learning more: kebblog.com/how-a-3-phase-ac-induction-motor-works/
at 2:35 you say "apply the current across the stator" - this is incorrect terminology. voltage is "applied" while current "flows" as a result. but, otherwise it is a good explanation :)
Hello I would really appreciate it if you could help me resolve this issue. I have a 1000 rpm 160 kw rated 3 phase Delta connected ac motor hooked to an air compressor feeding an oxygen production plant. our phase to phase supply voltage is 380 volts. our maximum running load current at working pressure is 250 Amps. This motor failed as it was running for more than 10 years. Lately we demanded more continuous load due to high demand for medical oxygen effected by covid19 pandemic. I could not find a similar replacement available. However i found another German made motor with same mounting frame and shaft size and also 1000rpm at 50 Hz the name plate says: Delta connection 660 Volts - 260 Amps - 240 KW. my question is : if i supplied this motor 380V with same delta connection will it be able to give me 160 kw power? because its limiting design current is 260 Amps as it says . Thus if am assuming its rated power will be reduced proportionally to the reduction of supply voltage. i it is rated 240 Kw at 660 Volts is it true that it will become a 160 Kw motor under 380 Volts? I am also assuming it will not overheat as the current will not exceed its rated 260 A at my demanded compressor load. Please help me if you have a definitive answer without any speculations. Best regards
The sine wave drawn in this video more closely resembles a 60° Phase shift instead of the intended 120°. We apologize for the confusion. All the spoken and written information is correct. Thank you for your understanding. The graphic in the blog article has the correct wave form if you are interested in learning more: kebblog.com/how-a-3-phase-ac-induction-motor-works/
This is a great 1000ft view of a 3-phase motor concept. Well done!
at 2:35 you say "apply the current across the stator" - this is incorrect terminology. voltage is "applied" while current "flows" as a result. but, otherwise it is a good explanation :)
Thanks😍👍🏻
You're welcome
Hello I would really appreciate it if you could help me resolve this issue. I have a 1000 rpm 160 kw rated 3 phase Delta connected ac motor hooked to an air compressor feeding an oxygen production plant. our phase to phase supply voltage is 380 volts. our maximum running load current at working pressure is 250 Amps. This motor failed as it was running for more than 10 years. Lately we demanded more continuous load due to high demand for medical oxygen effected by covid19 pandemic. I could not find a similar replacement available. However i found another German made motor with same mounting frame and shaft size and also 1000rpm at 50 Hz the name plate says: Delta connection 660 Volts - 260 Amps - 240 KW. my question is : if i supplied this motor 380V with same delta connection will it be able to give me 160 kw power? because its limiting design current is 260 Amps as it says . Thus if am assuming its rated power will be reduced proportionally to the reduction of supply voltage. i it is rated 240 Kw at 660 Volts is it true that it will become a 160 Kw motor under 380 Volts? I am also assuming it will not overheat as the current will not exceed its rated 260 A at my demanded compressor load. Please help me if you have a definitive answer without any speculations. Best regards