How to predict products for combustion reactions, including hydrocarbon combustion

Поделиться
HTML-код
  • Опубликовано: 13 сен 2024

Комментарии • 20

  • @aphidsfirst
    @aphidsfirst Год назад +1

    Thanks again for your videos in this series on reactions! You explain it so much better than the book.😊❤

  • @jonnyg7629
    @jonnyg7629 4 года назад +3

    you explain things SO clearly

  • @chuckcarlson2314
    @chuckcarlson2314 4 года назад +3

    Thanks for posting such useful vids. beautiful!

  • @gokuldoctor3019
    @gokuldoctor3019 4 года назад +2

    keep uploading many videos these are very useful

  • @jarretberenson1214
    @jarretberenson1214 4 года назад +1

    This is great! thanks so much for posting!!

  • @villavilla2377
    @villavilla2377 3 года назад +1

    Thanks Very much 😄

  • @tristanmoore7340
    @tristanmoore7340 4 года назад +2

    thank you

  • @mosesguveya1828
    @mosesguveya1828 4 года назад +1

    Thanks so much

  • @Plus815
    @Plus815 11 месяцев назад

    How about incomplete combustion? Idk how to do it

  • @kikiandgigi9585
    @kikiandgigi9585 Год назад

    Do all of the oxidized hydrocarbons form in to Co2 and H20 only? or can there be other biproducts when combusted. I'm trying to figure out the products released in the combustion of glyoxylic acid (C2H2O3) to see if formaldehyde are released

    • @CrashChemistryAcademy
      @CrashChemistryAcademy  Год назад

      In a highly oxygenated environment, I think that would be true. For example if you burned glyoxylic acid in potassium chlorate or some other high oxygen content oxidizers then the products would be CO2 and H2O. In air, which is only 21% oxygen as well as far lower density, side reactions can reasonably be expected. I do not know if a formaldehyde product could be expected in glyoxylic acid combustion--that would require some rearranging that I don't think would be thermodynamically favorable, but that is a guess.
      Also, my reaction mechanism for burning methane is simplified for the sake of the video. In reality there are far more steps involved to get from reactants to products.

    • @kikiandgigi9585
      @kikiandgigi9585 Год назад

      @@CrashChemistryAcademy thank you so much for this explanation!

    • @CrashChemistryAcademy
      @CrashChemistryAcademy  Год назад

      You're welcome!

  • @ashishraj5042
    @ashishraj5042 4 года назад +1

    From which country you are

  • @returnofthemomos
    @returnofthemomos 4 года назад +1

    First

  • @hitiktokmissyou2789
    @hitiktokmissyou2789 4 года назад +1

    👍👍💋❤❤💖🇵🇰