Hello MS,god bless you !! ,please post more vids on topology,havin tough time goin thru it ,kindly upload more vids on different types of topology ,basis, connectedness, compactness etc . ,
If you mean that you believe that that is the definition of a continuous mapping, then the answer is no: for a continuous mapping, the preimage of any open set in the codomain of said mapping is open, and not necessarily the other way around.
![How to Prove that the Interval (a, b] is Not an Open Set](http://i.ytimg.com/vi/aAYMxtLjNc0/mqdefault.jpg)
Buen canal, mas videos de Topologia
Hello MS,god bless you !! ,please post more vids on topology,havin tough time goin thru it ,kindly upload more vids on different types of topology ,basis, connectedness, compactness etc . ,
the definition you give for an open function is for continuous mappings is it not?
no it's just for mappings in general, the concept is one from topology if you are curious
If you mean that you believe that that is the definition of a continuous mapping, then the answer is no: for a continuous mapping, the preimage of any open set in the codomain of said mapping is open, and not necessarily the other way around.