Watch Part-2 here : ruclips.net/video/G6btBIKpr6Y/видео.html Hi There is a calculation mistake @9:42 The anode to cathode voltage will come out to be positive hence after re solving all the four diodes will be on V1 = V2 = V3 = V4 = 0v & ID1 = 1.6 mA ,ID2 = 0.12 mA , ID3 = 2.44 mA , ID4 = 1.58 mA ,This would be the correct answer also @15:50 , V4 = 2.833 Volts.Also a small calculation mistake @51:45 V1 should be 3.75 not 6.25.Sorry about all the mistakes Was really tired that day.Everything else remains same.
Watch Part-2 here : ruclips.net/video/G6btBIKpr6Y/видео.html
Hi There is a calculation mistake @9:42 The anode to cathode voltage will come out to be positive hence after re solving all the four diodes will be on V1 = V2 = V3 = V4 = 0v & ID1 = 1.6 mA ,ID2 = 0.12 mA , ID3 = 2.44 mA , ID4 = 1.58 mA ,This would be the correct answer also @15:50 , V4 = 2.833 Volts.Also a small calculation mistake @51:45 V1 should be 3.75 not 6.25.Sorry about all the mistakes Was really tired that day.Everything else remains same.
At 32:16 i think i(t) would be 0.43ma.plz check and confirm it
Yes correct!
for D2 diode v2 is cathode and v3 is anode so , vd2 should be vd2 = v3-v2 which is greater then zero but you mention vd2 less than zero @ 9:42
Yes all 4 Diodes will be ON. Thanks!
Then doide will D2 will be ON right
At 53:57 the value of the i2 current is wrong, so that the current through the diodes will be negative and diodes will be open circuited
See the pinned comment their is a calculation mistake before that states will remain same.
For analog vlsi internship point of view are all kind of feedback topologies important or not?
Will not the 3 rd question of b part be the short circuit??
Nice lecture😊
pr0 bhiyya