Major & Minor Products (11/11) | Organic Chemistry - NCEA Level 2 Chemistry | StudyTime NZ

[@mrkoala5127]

I cannot express how helpful this video is! Super clear! Super to the point!

[@nalinaswani536]

Thank you! A separate video focusing on major and minor products was really helpful :)

[@farahelfaramawy4353]

life saver. i was like how do i know the differences , and how to remember it, you saved me the stress, and its soo easy to remember , i usually am up in the clouds thinking about stuff like life,rich, poor, sad stuff. an happy stuff too but, whatever. thank you. its something that will keep me confidant during the exam.

[@meghbanerjee4259]

I was confused with this video about the elimination reactions at first but now I get it thank u!

[@amirashrafzuraimi4771]

On minute 2:58 , there is a typo . It should be 1-bromopropane instead of 1-bromopropene . So I hope you can edit it to prevent misunderstanding esp among students and btw thanks for the knowledge.

[@KillaKelzz]

Shouldn’t it be propene cause of the double bond?

[@vanillabros2867]

@@KillaKelzz No because the product is a bromoalkane as the double bond is broken.

[@yomoma4291]

Thanks for clearing explaining the law! This helped me understand the concept a lot better. Can't thank you enough!

[@trnk1dsfdsf859]

For a reaction with multiple products, can there be more than one major/minor product?

[@renee_chu]

Thank you for this video. It cleared up all my confusions in lectures.

[@gretace2474]

That was so straightforward and simple to understand!!!
Thank you so so so much I have an exam in an hour and this helped

[@justshan2413]

You're still saving lives.

[@sandile8264]

thnks sir u made that part very easy for me i was strugling

[@srm4435]

For Saytzeff rule...what should I do if both the beta carbons have same no of hydrogen atoms?

[@onyeakusiobivalentine9620]

Thanks a lot. I'll have a test today am this is very helpful.

[@theamazer9176]

Padhlo pehle fir comments dekhna...

[@bharathivenkat9401]

Thank you sir that was really helpful !!!

[@srm4435]

How to apply Markovnikov rule if both the c atoms having double bonds between them have same no of hydrogen atoms?.... Like Pent-2-ene ?

[@_NotSevenOP]

When pent-2-ene reacts with HBr, HBr gets added to the double bond by the Markovnikov rule and 2-Bromo pentane is formed

[@_NotSevenOP]

When HX is added to an unsymmetrical alkene, the hydrogen becomes attached to the carbon with the most hydrogens attached to it already.

[@onyeakusiobivalentine9620]

Thanks a lot. I'll have a test today and this is very helpful.

[@TarunKumar-fk3nh]

❤️ from india

[@selvakumarrajamanickam6332]

Great application

[@eliseaspinall4148]

One question, why are the minor products formed in this reaction?

[@mansiyadav4253]

Elise Aspinall

[@infiltron8227]

Because there would be molecules that have enough energy to react down the minor pathway

[@nirjalasonar2969]

Why 2 bromobutane is major product

[@RedstoneDerp]

Wow that really helped me. Thanks a lot

[@user-kl8vj2qy9w]

But why ..
Isn't there a scientific explanation to it?

[@_Alpha]

The carbons around the main (reacting) carbon stabilises against the electronegativity, which is the electron pulling power of the incoming halide eg chloride or bromide. so the overall molecules is more stable.

[@nisacele5351]

Thank this was very helpful

[@ninjapirate123]

Is ncea chemistry hard

[@wendytoyle7081]

Thank you so much 😊

[@09ak31]

NZ UP!

[@maxospovat8959]

Great vid, thank you

[@Feurns]

Thanks! Good video.

[@rimagupta5205]

thankyou really helpful video

[@weeeyah_7883]

Thank u so much

[@hala_hasan8551]

Thanks alot

[@karansankhat4802]

Thanks

[@mothekgimantjane1299]

🔑🙏

[@simmiahuja8324]

Don't you even know markovnikov's rule

[@siddhantdamre1589]

This video has wrong examples!!

[@aaarhhh4341]

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[@ollienokynhafilintos2966]

This guy is terrible!!

[@infiltron8227]

so are trolls like you

[@juanjuan5698]

@@infiltron8227 You had the perfect chance to say, "no you" :(

[@infiltron8227]

@@juanjuan5698 no you

[@mothekgimantjane1299]

🔑🙏