Hi, thank you for doing all this. I found it is easy to understand. I really appreciate it. It is said on the textbook that the equivalent hydraulic conductivity is equal to the √(kz*kx) for anisotropic soil. Could you please explain a bit about why it is √(kz*kx)? thanks a lot!
You saved my ass buddy. Keep teaching the masses
Fantastic 👍👍 ......easy explanation....
keep going , well done bro,well explained, God bless You.. please upload sheet pile design examples also...
Hi, thank you for doing all this. I found it is easy to understand. I really appreciate it. It is said on the textbook that the equivalent hydraulic conductivity is equal to the √(kz*kx) for anisotropic soil. Could you please explain a bit about why it is √(kz*kx)? thanks a lot!
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Concept clear. Thank you very much.
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What is piezometric head? And what is seepage head?
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Isn't our Q @ 16:53 supposed to be 3m^3/s since our k =0.01 ; L= 100m ; delta h= 12m and NFP/NED= 0.75?
made the same observation. I think a wrong conversion factor was used.