That scale gives you the length of 5 m (in the real world) on the graph. For instance, if say that scale is 2 cm (on the graph), which we know represents 5 m (in the real world), and you measured the distance of the specific point to the datum is 4 cm on the graph. This means the real-world distance of that point to datum is 10 m.
Thank you ...
Why are you saying that the total head difference is 5.6 --- shouldnt it be 5.6 -2.2=3.4????
i'm surprised too
how will i use the scale to find the distance of the specific point to the datum
That scale gives you the length of 5 m (in the real world) on the graph. For instance, if say that scale is 2 cm (on the graph), which we know represents 5 m (in the real world), and you measured the distance of the specific point to the datum is 4 cm on the graph. This means the real-world distance of that point to datum is 10 m.
@@uSeeGeo still unclear
Can you please give me the file pdf.
Send me link in the comint
who r u bro
Anyways, you made a mistake on (i) when calculating ◇h.
It's (3.4/6) =0.567, not 0.576, as u wrote😅