Collimation of the X-ray Beam | X-ray physics #8 | Radiology Physics Course #15

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  • Опубликовано: 3 дек 2024

Комментарии • 26

  • @zahraaal-turaihi
    @zahraaal-turaihi 8 месяцев назад +5

    Amazing amazing, 12 min took me to understand this when I tried 2 hours with no luck

  • @maamii777
    @maamii777 6 дней назад

    Such a great explanation🤍!!
    Thank you so much 🤍and keep going🤝

  • @NishantRajF1
    @NishantRajF1 Год назад +3

    Simplest explanation ever. Thanks , helps a lot.

    • @radiologytutorials
      @radiologytutorials  Год назад +1

      I’m so glad it helped Nishant. Simpler the better in my opinion when it comes to physics!

  • @bassma811
    @bassma811 6 месяцев назад +2

    Thank you so much 🤍

  • @Umarkhan-b2r9j
    @Umarkhan-b2r9j 4 месяца назад +1

    Nice explanation❤

  • @courtneyclark5859
    @courtneyclark5859 2 месяца назад

    Vet med online student here thank you thank you thank you!!!

  • @AkhirahSadie3
    @AkhirahSadie3 Год назад +2

    Thank you it was very helpful, I'm a 2nd year college, taking a radiologic technologist,❤

  • @atsedeAddise
    @atsedeAddise Год назад

    I am grateful for you that your teaching is interesting

  • @doctorshwan
    @doctorshwan Год назад

    excellent explanation, thank you.

  • @dylanropert
    @dylanropert 10 месяцев назад

    Your videos are phenomenal! Thank you for all these resources/explanations.
    Just had a question about what you said at 00:04:26 How does collimating improve spatial resolution? Shouldn't it only affect contrast by decreasing scatter (scatter kills contrast)? Especially since our FOV hasn't technically changed (Matrix number, pixel size, etc). Similar to grid spatial resolution - "Because the grid does not change the size of the focal spot or the size of the pixels in the image matrix, it does not influence spatial resolution."

    • @radiologytutorials
      @radiologytutorials  10 месяцев назад +1

      Thank you Dylan! You’re correct ✅ my mistake, meant to say collimation improves contrast resolution! Thanks for letting me know 👌🏼

  • @nerminesaid737
    @nerminesaid737 5 месяцев назад +1

    Thank you very much for your great videos. I have a question though. what do you mean by saying ' Now these gray blocks here represent lead sheets that will attenuate our x-ray beam lay. It has a high atomic number. And we saw with the photoelectric effect, the higher the atomic number, the more likely the photoelectric effect is to occur', I really can't get my head wrapped around this phrase, I heard it in the previous video too but I don't get it. I'd really appreciate a brief explanation

  • @TheNettforce
    @TheNettforce Год назад

    These lectures are 👍 great. Not sure how I just discovered you now.

  • @mohamedhoussemknkr1607
    @mohamedhoussemknkr1607 Год назад

    thank you

  • @ScampBirju
    @ScampBirju Год назад

    Love❤ from india
    You doing great job 👍

  • @MeganSoukup-po9lh
    @MeganSoukup-po9lh Год назад

    Hi! Thank you for the very informative video (they are great!!). I have a question; does the cathode/anode difference in photon projection still apply when collimating since the lead sheets attenuate most of the lateral X-rays being projected? I watched your cathode vs anode photon projection video and was just curious. Sorry if this is common knowledge, I am going to school in July for X-ray school and I am just trying to get a good idea of how things work. Thanks a ton! Your videos are so helpful!

    • @radiologytutorials
      @radiologytutorials  Год назад +2

      Hi Megan. Great question! The cathode anode difference (tube potential) determines both the average energy and number of x-ray photons produced. Collimation attenuates x-rays from the outer portion of the beam but does nothing to the x-rays still reaching the patient. Therefore, if cathode anode difference changes the energy and the number of photons reaching the patient (despite collimation) will still change. Watching the ‘factors that influence the x/ray spectrum’ video should help. Feel free to reach out if you have any more questions 🙂

    • @MeganSoukup-po9lh
      @MeganSoukup-po9lh Год назад

      @@radiologytutorials Perfect! I will give that a watch! Thank you so much for the information!!!