Really it made a huge difference in my study....may now u don't have much views...but keep trying sir because one day your channel become a huge channel for sure..... Don't get demotivate..🙏🙏🙏
The standard form of equation of circle is |z-a|=r where a is centre and r is Radius. If you compare the given equation with this standard form you will get centre i that is (0,1) and Radius 2
OMG THANK YOU SO MUCH!! I understood nothing in class. This was so clear and made me understand so well. God bless you
You just made me understand something my lecturer failed to make understand for a week. U the best🤞
Really well explained thank you !
Thank you for such a good explanation
you are the first Indian ever that I decided to watch
Who tf are you bruh 😭
No one cares lil bro
😂@@InvinciblePepe
Thankyou so much sir really well explained ❤🙏
Thank you so much Sir 😎
Underrated 💥
Thank you sir
Strongly axplained.
thank you sir😊
Thanks sir
nice video, nice explanation, the pronunciation was magnifique my pana ranjan. Saludos bro
Thank you
Thankyou sir❤
Thanks a lot sir ❤
we have the same question in our tutorial sheet,sem3 nit calicut
Really it made a huge difference in my study....may now u don't have much views...but keep trying sir because one day your channel become a huge channel for sure..... Don't get demotivate..🙏🙏🙏
Thank you so much for your comment
using residue theorm evaluate the integrals 1+z/z(2-z)
Thank you
Thankyou
Sir y did u take on y axis points -2i and 2i ??? Should not we take on x axis
2i and -2i are purely imaginary numbers and Y is an imaginary axis. So those points should be on Y Axis
Sir please do tell me how to solve e^5z/(z-i)^4 my answer was same qs cauchy integral
What if my circle is |z-1|=2?, it will be still z+2i z-2i?
Why it is not passing through 2 in x axis
keep it up ❣❣❣
Thank you
Sir I am not able to find the complete Playlist of complex analysis unit 2 please help
Not prepared completely yet
sir kindly tell me the name of book
Brown and Churchill, John Conway
Keep making videos sir🙌🙌
Even my dumbass understood it, thanks
why is the radius not (0,-1)
i mean centre
The standard form of equation of circle is |z-a|=r where a is centre and r is Radius. If you compare the given equation with this standard form you will get centre i that is (0,1) and Radius 2