Complex Analysis | Unit 2 | Lecture 13 | Example of Cauchy's Integral Formula

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  • Опубликовано: 9 ноя 2024

Комментарии • 42

  • @ShekinahChristianMusic
    @ShekinahChristianMusic Год назад +3

    OMG THANK YOU SO MUCH!! I understood nothing in class. This was so clear and made me understand so well. God bless you

  • @jessicakhoza4784
    @jessicakhoza4784 Месяц назад +1

    You just made me understand something my lecturer failed to make understand for a week. U the best🤞

  • @roviambagolla7954
    @roviambagolla7954 Год назад +7

    Really well explained thank you !

  • @rajnisaini4193
    @rajnisaini4193 Год назад +3

    Thank you for such a good explanation

  • @mylifemyruleyou
    @mylifemyruleyou Год назад +22

    you are the first Indian ever that I decided to watch

  • @vishu6328
    @vishu6328 Год назад +2

    Thankyou so much sir really well explained ❤🙏

  • @tankhaiinh1729
    @tankhaiinh1729 14 дней назад

    Thank you so much Sir 😎

  • @yashvishwakarma2710
    @yashvishwakarma2710 3 месяца назад +1

    Underrated 💥

  • @Anamikas_story
    @Anamikas_story Год назад +2

    Thank you sir

  • @ghulambahu8508
    @ghulambahu8508 6 месяцев назад +2

    Strongly axplained.

  • @narunstorm
    @narunstorm 11 месяцев назад +2

    thank you sir😊

  • @abhaypatel1018
    @abhaypatel1018 Год назад +1

    Thanks sir

  • @augustoallignani3260
    @augustoallignani3260 4 месяца назад +1

    nice video, nice explanation, the pronunciation was magnifique my pana ranjan. Saludos bro

  • @sankardhakal7466
    @sankardhakal7466 6 месяцев назад +1

    Thankyou sir❤

  • @shahzaib.graphy
    @shahzaib.graphy Год назад +1

    Thanks a lot sir ❤

  • @benzene979
    @benzene979 11 часов назад

    we have the same question in our tutorial sheet,sem3 nit calicut

  • @sebaranibiswal4536
    @sebaranibiswal4536 2 года назад +5

    Really it made a huge difference in my study....may now u don't have much views...but keep trying sir because one day your channel become a huge channel for sure..... Don't get demotivate..🙏🙏🙏

    • @ranjankhatu
      @ranjankhatu  2 года назад +1

      Thank you so much for your comment

  • @Student-t3z
    @Student-t3z 6 месяцев назад

    using residue theorm evaluate the integrals 1+z/z(2-z)

  • @harishrawat07
    @harishrawat07 Год назад +1

    Thank you

  • @kheithkay
    @kheithkay Год назад +1

    Thankyou

  • @304_b.harshitha3
    @304_b.harshitha3 Год назад +1

    Sir y did u take on y axis points -2i and 2i ??? Should not we take on x axis

    • @ranjankhatu
      @ranjankhatu  Год назад +1

      2i and -2i are purely imaginary numbers and Y is an imaginary axis. So those points should be on Y Axis

  • @binishabhattarai8895
    @binishabhattarai8895 7 месяцев назад

    Sir please do tell me how to solve e^5z/(z-i)^4 my answer was same qs cauchy integral

  • @krupalsuthar1732
    @krupalsuthar1732 7 месяцев назад

    What if my circle is |z-1|=2?, it will be still z+2i z-2i?

  • @comic8451
    @comic8451 Год назад

    Why it is not passing through 2 in x axis

  • @saadazam9098
    @saadazam9098 2 года назад

    keep it up ❣❣❣

  • @HarshSingh-jm4in
    @HarshSingh-jm4in Год назад

    Sir I am not able to find the complete Playlist of complex analysis unit 2 please help

  • @AbuBakkar-ue2tb
    @AbuBakkar-ue2tb 7 месяцев назад

    sir kindly tell me the name of book

    • @ranjankhatu
      @ranjankhatu  7 месяцев назад

      Brown and Churchill, John Conway

  • @sebaranibiswal4536
    @sebaranibiswal4536 2 года назад

    Keep making videos sir🙌🙌

  • @Antarah525
    @Antarah525 11 месяцев назад +1

    Even my dumbass understood it, thanks

  • @esthermurugi7900
    @esthermurugi7900 2 года назад

    why is the radius not (0,-1)

    • @esthermurugi7900
      @esthermurugi7900 2 года назад +1

      i mean centre

    • @ranjankhatu
      @ranjankhatu  2 года назад

      The standard form of equation of circle is |z-a|=r where a is centre and r is Radius. If you compare the given equation with this standard form you will get centre i that is (0,1) and Radius 2