Calculation of the nuclear binding energy and mass defect

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  • Опубликовано: 29 дек 2024

Комментарии • 38

  • @gursevak.
    @gursevak. Год назад +2

    i have physics exam on 6march thank you for the help budd

  • @charlesbesa7755
    @charlesbesa7755 4 года назад +5

    how did he get the 9.65

  • @kobbystudio
    @kobbystudio 3 года назад +3

    How did you get the energy in Mev

  • @alimimuhammes5258
    @alimimuhammes5258 8 месяцев назад +1

    How did yoy converter from joules to Mev

  • @yotanakamura5191
    @yotanakamura5191 4 года назад +12

    damn this would've been helpful an hour ago

  • @kisho2679
    @kisho2679 Год назад

    How can the energy of a chemical element be calculated from its electron configuration instead?

  • @vukaninqubekogcabashe4801
    @vukaninqubekogcabashe4801 5 лет назад +3

    from where do you find the masses that you put on the table

  • @MohamedGamal-rv3cm
    @MohamedGamal-rv3cm 5 лет назад +3

    You can multiply the mass defect by 931.5 then divide by A to cut short , instead of converting to Kg then J

    • @denvill267
      @denvill267 5 лет назад +1

      What is the "A" please define it I'm stupid

    • @yourthickneighbor2792
      @yourthickneighbor2792 4 года назад

      @@denvill267 A is the atomic mass, number of protons+neutrons

    • @judeohaji638
      @judeohaji638 4 года назад

      Thanks
      I needed to know how to use that other constant

    • @judeohaji638
      @judeohaji638 4 года назад

      I don't still get though

    • @charistorres3625
      @charistorres3625 2 года назад

      does this actually work

  • @simplyelite7063
    @simplyelite7063 5 лет назад +1

    when did he incorporate the mass of electron in change of mass

  • @kisho2679
    @kisho2679 Год назад

    How is M (here 7u) derived?

  • @justinross3338
    @justinross3338 5 лет назад +9

    how are you writing this backwards and with your left hand bro like what

  • @kiranbharti8898
    @kiranbharti8898 2 года назад +2

    it helpful for me 🇮🇳🇮🇳🇮🇳

  • @martirenedaljeetolim3825
    @martirenedaljeetolim3825 7 лет назад +3

    the video was nice. but could you more examples? Because this one was very straightforward and not very challenging...

  • @chaturmutha
    @chaturmutha 6 лет назад +2

    You say the mass of proton is 1.007825 amu.
    Google says the mass of proton is 1.00727647 amu.
    With that value, BE comes out to be 37.673MeV which way off than your value of 54.28 Mev.
    WHICH ONE IS CORRECT?!? And what's wrong?

  • @luisgarabito8805
    @luisgarabito8805 2 года назад

    Do you have to work in kg or can you multiply by 931.49 MeV/ u

    • @drkenz0tenma
      @drkenz0tenma 2 года назад

      Yeah you can multiply ∆m (in amu) by 931.49MeV .
      If your ∆m (is in Kg) multiply by c^2

  • @franc1159
    @franc1159 5 лет назад +3

    I swear he smoked a pot right before making this video

  • @garythornberry4820
    @garythornberry4820 7 лет назад +1

    I'm a little hazy on how you converted Joules to MeV. Do you have another video explaining how this is done?

    • @emx2369
      @emx2369 7 лет назад +5

      Joules to MeV:
      J/1.6x10^-19 =eV
      eVx10^-6= MeV
      (1.6x10^-19 is the charge of one electron used to convert J to eV)
      (x10^-6 is to convert eV to MeV)

    • @satrickptar6265
      @satrickptar6265 6 лет назад +1

      Just simply divide it by 1.6×10^-13

    • @SN-edits4u
      @SN-edits4u 3 года назад

      For J to eV, divide joule by magnitude of charge on an electron,i.e 1.6×10^-19

  • @dominicondieki7848
    @dominicondieki7848 3 года назад

    good work son ❤

  • @rheamaebumanglag8809
    @rheamaebumanglag8809 5 лет назад

    Is the Mp and Mn given??

    • @raht9578
      @raht9578 5 лет назад

      Yup, but you still must know that

  • @RajeevKumar-ls3cq
    @RajeevKumar-ls3cq 4 года назад +1

    Thanks A lot sir

  • @ayamarokaantje589
    @ayamarokaantje589 Год назад

    Thank you so much

  • @rahimofficial6959
    @rahimofficial6959 Год назад

    energy with joul bro... not Mev

  • @divya-c6v
    @divya-c6v Год назад

    thanks

  • @denvill267
    @denvill267 5 лет назад +1

    How he get the 54.28 MeV please explain it in more likely to a dummy dumdum like me

    • @raht9578
      @raht9578 5 лет назад

      Just divide it by 1.6×10^-19
      It will give you value in terms of eV.

  • @reshmanbaniya3221
    @reshmanbaniya3221 6 лет назад

    Oh interesting