Fluids - Multifluid Manometer Example #2

Another multifluid manometer example. This time the end is not open to the atmosphere. Instead it is connected to a pipe that transports gasoline. All our fluids are given to us in specific gravity, which we can easily convert to density or specific weight.
Picture taken from Thermodynamics 8th Ed. by Cengel Problem
1-112

[@525guy]

I finally figured out what I was doing wrong. I was using kPa in my calculations but now I know we must convert to Pa. Thank you!

[@emiller5929]

In the future could you just zoom out instead of scrolling around

[@alexwalton2132]

why don't you make your own video instead of hustling???

[@ryancopetti3850]

@@alexwalton2132 why are you mad over someone else's suggestion?

[@only_comments]

@@alexwalton2132 he has a right point.. main purpose of making video is to make people understand..
He was just giving suggestion..

[@asoaso5324]

An inverted differential manometer is connected to two pipe A And B carrying water under pressure as shown in fig.2.26.
the fluid in the manometer is oil of specific gravity 0.75 .Determine the pressure dufference between A and B

[@chrisrica6830]

This video helped me relearn manometers for my FE Civil Review. Thanks!

[@kierenhetherington6772]

Hero. Saved me going mad trying to figure this out :-)

[@TheSunshineRequiem]

wow thank you for mentioning why we treat air and liquids differently, I was confused even though its obvious...such details are always helpful

[@mahmutcanufak6895]

SIR , YOU CHANGED MY LIFE

[@stephenfulmer8646]

How would you find the absolute pressure for this problem??

[@NK-iy6if]

Thank you so much the video is very helpful! God bless you!

[@Rose-yw8yf]

Who’s has fluid test? 🤦🏻‍♀️

[@lugh6184]

Was too late to see this.. Now I just got 60%

[@user-iz5eg3nr4l]

Did u have this question for your test lol?

[@Youtuber-rf4oj]

Simply thank you very much 🙏🙏

[@edgarquis6458]

Well explained congratulations.....!

[@Mohsen_Saa]

Thank you! Very useful.

[@jonsnow675]

Good job 👏🏻 doc

[@elnabz4731]

please why did you multiply mercury and gasoline with 9.81 and didnt for others?

[@petepenner938]

Nabeel lee I multiplied all liquids by 9.81 so I could find pressure. Pressure is the density of the fluid(rho)*gravity(g)*difference in height(h). The only term not multiplied by 9.81 is air since it is already given to us in pressure.

[@A.1171G]

Thank you, Sir.

[@ahmedalbalawi2678]

Thank you so so so so so so so so so much :)

[@srinidhins3291]

Thank you sir 🙏🏾

[@Shashin2023]

Thank u sir

[@md.arrafibinarif583]

Whyy is the sound sooo low :)

[@abdallahkhaled1349]

That was very helpful tyyy♥️

[@emmmanuelyartey3628]

thanks for that

[@geofanyrosady]

thank sir

[@xrhst0s2114]

What if we are given air ρ=1.2kg/m^3 then we take height into account?

[@MrThorkell1]

Then you just used that given density. That doesn’t change the process shown in the video.

[@vishaltarte8508]

Nice sir

[@zenzen3655]

thanks