Your lessons are truly amazing. My teacher took 34 minutes explaining this and I was left confused, but you took 3 minutes and 34 seconds and taught me more than her. Pretty cool mate!
Anna Pitts, When dealing with square roots, you always try to simplify the number WITHIN the square root sign to the simplest numbers, in order to factor out as many of them as you can, and something that is not easily divisible just leave inside the square root sign, as a whole number, (for the sake of neatness). In the case of the number 20, inside the square root sign, we can break up the 20 into 4 • 5, (because you can separate the numbers within square root into separate square roots, if they are multiplied by one another, and cannot separate them if they are added, or subtracted from each other). So, as we brake up sqrt(20) into sqrt(4) • sqrt(5), we can now have an easily squarerootable 4, which is 2^2, and not easily squarerootable 5, which we leave as it is. And thus, we can simplify the whole expression as follows: sqrt(20) = sqrt(4 • 5) = sqrt(4) • sqrt(5) = 2 • sqrt(5) = 2sqrt(5) which is what he did... If it was, say, sqrt(45), we could do the same: 45 can be broken down into 9 • 5, where 9 is easily squarerootable down to 3. So, we get, sqrt(45) = sqrt(9 • 5) = sqrt(9) • sqrt(5) = 3 • sqrt(5) = 3sqrt(5) That's how we deal with large messy square roots.
Parents: RUclips ROTS YOUR BRAIN!!! Also RUclips: Literally helps me find what Im doing wrong and quite possibly saves my tomorrow’s test grade Thank you man, this is a lifesaver
I assume you'll do this python, so looping over each point in the line and solving it for the curve should do the trick, at the end of the loop you'll have the distances for each point, from there on you can find the min or max distance or whatever you need
Hi sir, just want to ask what if the given ordered pair is like this (x,5) and the distance of a point from a line is already given, but the teacher wants to find the value of x how can we solve it?
(x,5) is one of the points. I'd need to know the other point to do the math but if the other point was (2,8) and the distance was 20, I'd have d=20, x1=x,y1=5,x2=2,y2=8. I'd take the distance formula d= sqrt((x2-x1)^2 + (y2-y1)^2) and I'd plug in my values. And then I'd solve for x. 20=sqrt((2-x)^2+(8-5)^2) Square both sides 400 = (2-x)^2+(8-5)^2 400= (2-x)^2+9 391= (2-x)^2 sqrt to get rid of ^2 19.77=2-x 17.77=-x -17.77=x Obviously mine is made up so I got a decimal. Yours might be a whole number but that is the process.
Thank you so much for this information; I was trying to solve a problem like this for hours using a method prescribed by the school textbook example, and it just wasn't working. I was able to solve the problem using your method within minutes. Nevertheless, I still want to know where I went wrong. Hopefully I'll figure it out.
Your question is a year old, but I think I might be able to answer it quickly. The vertical line going through the given point (5, 5) has equation x=5. Plug that into the equation of the given line, y=2x+5. That's y=2(5)+5=15. So the intersection of the given equation and the vertical line through the given point is (5, 15). Use that point (5, 15) and the given point (5, 5) in the distance formula, like in the video, and you'll get the answer. But actually, if we look at the points, the x values are the same, so the distance between them is just along the vertical line from 5 to 15. 15-5=10. That's the vertical distance.
Your lessons are truly amazing. My teacher took 34 minutes explaining this and I was left confused, but you took 3 minutes and 34 seconds and taught me more than her. Pretty cool mate!
Lol mine went through it in 45 sec and left the whole class confused
well mine took like 30 seconds (fr)
That was plain and simple and straight to the point. Well done good sir. :)
Excellent work agent 47. Now make your way to the extraction point.
😂😂
this man knows everything
Nbs
You are so stupid
Took my teacher 50 minutes and we didn't even finish the lesson, this taught it perfectly in 3
thank you, my teacher had a hard time explaining how to do this
Absolute lifesaver, thank you very much!
Glad it helped!
Impeccable Video! Thank you for you tutorials.
Anna Pitts,
When dealing with square roots, you always try to simplify the number WITHIN the square root sign to the simplest numbers, in order to factor out as many of them as you can, and something that is not easily divisible just leave inside the square root sign, as a whole number, (for the sake of neatness).
In the case of the number 20, inside the square root sign, we can break up the 20 into 4 • 5, (because you can separate the numbers within square root into separate square roots, if they are multiplied by one another, and cannot separate them if they are added, or subtracted from each other).
So, as we brake up sqrt(20) into sqrt(4) • sqrt(5), we can now have an easily squarerootable 4, which is 2^2, and not easily squarerootable 5, which we leave as it is. And thus, we can simplify the whole expression as follows:
sqrt(20) = sqrt(4 • 5) = sqrt(4) • sqrt(5) = 2 • sqrt(5) = 2sqrt(5)
which is what he did...
If it was, say, sqrt(45), we could do the same:
45 can be broken down into 9 • 5, where 9 is easily squarerootable down to 3. So, we get,
sqrt(45) = sqrt(9 • 5) = sqrt(9) • sqrt(5) = 3 • sqrt(5) = 3sqrt(5)
That's how we deal with large messy square roots.
Mario is the goat 😤😤thank you so much math master Mario
Revisit this problem after learning rotations in geometry, vectors in precalculus and optimization in calculus
This is really useful for a project i'm working on- needed a refresher for sure.
Glad it was helpful!
I have a test today and I almost forgot about this, thank you so much 😀
Parents: RUclips ROTS YOUR BRAIN!!!
Also RUclips: Literally helps me find what Im doing wrong and quite possibly saves my tomorrow’s test grade
Thank you man, this is a lifesaver
YOOOOO THIS GUY IS SO HELPFUL, TY SIR. my teacher explained it but i didn't get it. You're a genius
I just used this method to find the nearest distance between a curve and a line!
I assume you'll do this python, so looping over each point in the line and solving it for the curve should do the trick, at the end of the loop you'll have the distances for each point, from there on you can find the min or max distance or whatever you need
Watching this an hour before my math test, I’ve been confused and I think it just clicked! Wish me luck!
bruh my teacher took 3 and a half total hours to explain this completely and you did it better in under 4 minutes
Thank you, this one of the best explanations ever!!!!
so straight forward
thank you so much, sir!
Most welcome!
I do like your style of teaching sir
Thank you so much !
youre a godsend
Thank you for this I was absent for a week and never understood this
Thank you soooo much
Better than my teacher 👍😁
Hi sir, just want to ask what if the given ordered pair is like this (x,5) and the distance of a point from a line is already given, but the teacher wants to find the value of x how can we solve it?
(x,5) is one of the points. I'd need to know the other point to do the math but if the other point was (2,8) and the distance was 20, I'd have d=20, x1=x,y1=5,x2=2,y2=8. I'd take the distance formula d= sqrt((x2-x1)^2 + (y2-y1)^2) and I'd plug in my values. And then I'd solve for x.
20=sqrt((2-x)^2+(8-5)^2)
Square both sides
400 = (2-x)^2+(8-5)^2
400= (2-x)^2+9
391= (2-x)^2
sqrt to get rid of ^2
19.77=2-x
17.77=-x
-17.77=x
Obviously mine is made up so I got a decimal. Yours might be a whole number but that is the process.
@@alexmenke6825 thank you sir i really appreciated 🙏 ❤ 🙌 👏 💕 💛
@@jadealthea2948 You're welcome.
your videos teach better than my teachers 100% of the time
Thank you so much for this information; I was trying to solve a problem like this for hours using a method prescribed by the school textbook example, and it just wasn't working. I was able to solve the problem using your method within minutes. Nevertheless, I still want to know where I went wrong. Hopefully I'll figure it out.
thank you so so much live saver
You're welcome!
Oh my god thank you so much
thank you so much
You're welcome!
Thankyou so much!!!!!
You’re welcome!
Awesome video
Thanks!
math legend
Lol I’m goona pass this test now 😊
Thank you so much.
What's the reason for changing the reciprocal of the slope?
Isaac, Opposite reciprocal slopes - means lines are perpendicular.
Ann the distance between the dartboard and the throwing line
i did ur method and got crazy numbers and i did it right mabye cuz my teacher gave me a bunch of problems she didnt teach
just as video started.... he reminded me of jhonny sins...
Whoever disliked are people who weren't trying to understand.
what if the point is (p,q) and the line is y =mx+b, and my answer must be in terms of p, q, m, and b
Legend
hold on, what if you just want to find the vertical distance between a point and a line?
Your question is a year old, but I think I might be able to answer it quickly.
The vertical line going through the given point (5, 5) has equation x=5.
Plug that into the equation of the given line, y=2x+5. That's y=2(5)+5=15. So the intersection of the given equation and the vertical line through the given point is (5, 15).
Use that point (5, 15) and the given point (5, 5) in the distance formula, like in the video, and you'll get the answer.
But actually, if we look at the points, the x values are the same, so the distance between them is just along the vertical line from 5 to 15. 15-5=10. That's the vertical distance.
Thank it can make me sure .it is the same my idea
What if the line given is only x=1
Gobakh
there is a long way to verify. it is easier but it takes longer.
how would i do it if my line is 3x+4y-5=0 and my point is (-4,5)
You have to write that line in y=mx+b form, then just follow his instructions
We have direct formula to find distance between point and the line
I discuss the formula in this video here: Finding Distance from Point to Line (Formula) ruclips.net/video/h13wI_gi4GA/видео.html
d=|ax1+by1+c|/√a²+b²
this guy looks like the bad guy from the first shazam movie
howd u get 1,7 after plugging it in
1 was the x coordinate, so he plugged in 1 for x in the original equation (y=2(1)+5= 7 which is the Y coordinate and thus (1,7)
👍🏻
One punch math
he went a little fast, but i got it
online geometry is killing me
I can't read your writing, and you are moving way to quickly. You need to slow it down. Thanks for doing this though. I will pause one a time.
im pretty sure this is just supposed to be a review, youre not supposed to rely only on him to learn how to do these problems
This shit makes no sense I have a test in a hour
shouldn't the answer be 5?
IM DOING NOTHING WORNG SND DAISBDNSUAD
I don't understand the way your doing this. I've never been taught that in school
Bro r u trying to show off or teach geez slow down
Thank you so much!