Quantum Chemistry 2

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  • Опубликовано: 18 ноя 2024

Комментарии • 1

  • @jacobvandijk6525
    @jacobvandijk6525 Год назад +1

    @ 1:33 "No PE"? I think the condition is that the PE = constant. Here (1:57) the PE is not zero (and it can still move in the x-directions)! And yes, PE = 0 = constant.