Dixon's Identity

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  • Опубликовано: 4 ноя 2024

Комментарии • 25

  • @rasherbilbo452
    @rasherbilbo452 6 месяцев назад +6

    Holy cow, this is a criminally under-subscribed channel.

  • @karanshome
    @karanshome 6 месяцев назад +11

    Another vid, another banger 😮‍💨

  • @AryanKumar-vo1ic
    @AryanKumar-vo1ic 6 месяцев назад +4

    love your work.

  • @amalirfan
    @amalirfan 6 месяцев назад +15

    No idea what I am watching, looks pretty though 🥺

  • @samueldeandrade8535
    @samueldeandrade8535 6 месяцев назад +5

    Brilliant ...

  • @corbinsmith5015
    @corbinsmith5015 6 месяцев назад

    Very cool video, I love sign reversing involutions

  • @pawebielinski4903
    @pawebielinski4903 6 месяцев назад

    Very very nice

  • @Grateful92
    @Grateful92 6 месяцев назад +9

    It won't be wrong to call you Grant Sanderson of combinatorics (but I appreciate you as a unique individual and your efforts and time that you put to beautifully simplify maths)
    Should we expect to get a full playlist on combinatorics by you?

    • @enumerable345
      @enumerable345  6 месяцев назад +1

      So kind, thanks! I definitely have ideas for a few more videos.

  • @MichaelDarrow-tr1mn
    @MichaelDarrow-tr1mn 2 месяца назад

    Can you do a combinatorial proof that 5 plus 17 isn't 24? I seem to keep making that association for some reason

  • @caspermadlener4191
    @caspermadlener4191 6 месяцев назад +3

    I love homological combinatorics

  • @mMaximus56789
    @mMaximus56789 6 месяцев назад +7

    Me in my combinatorial class: DIE

    • @zyklos229
      @zyklos229 6 месяцев назад +2

      Underrated 😂

  • @MichaelDarrow-tr1mn
    @MichaelDarrow-tr1mn 6 месяцев назад

    These trinomial coefficients... (a+b+c a,b,c)=(a+b+c a)*(b+c b). This can be used to make many identities, such as the Team-Leader identity from the derangement video i think?

    • @enumerable345
      @enumerable345  6 месяцев назад

      There are indeed tons of analogous identities/proofs with trinomial coefficients.

  • @MichaelDarrow-tr1mn
    @MichaelDarrow-tr1mn 2 месяца назад

    Can you do a combinatorial proof that 10 choose 3 equals 16 choose 2?

  • @misraimburgos7461
    @misraimburgos7461 6 месяцев назад +1

    I was here at 1k subscribers and less than 5k views.

  • @joebucket1471
    @joebucket1471 6 месяцев назад

    What software is he using to write the formulas and animate them ? Manim ?

  • @sillygoofygoofball
    @sillygoofygoofball 4 месяца назад

    woah

  • @warguy6474
    @warguy6474 6 месяцев назад +1

    i would rather DIE than count

    • @enumerable345
      @enumerable345  6 месяцев назад +1

      Matching is so much easier than counting!