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Great video very much helpful
This is the most comprehensive video on Squeeze theorem i've seen. Great video. New for me is the upper and lower boundaries
This is art !
I thought I had lost my link to this video and was panicking. This is my first choice of all videos on the web for understanding the squeeze theorem.
this finally made sense. thank you!!!
Thankyou so much sir !
thanks for you explanation
Thank you, this was really helpful
Great video! I think at 16:00 you made a slight mistake. Factoring x**2 out of x**2+1 gives you x**2(1+(1/x**2)) not just 1+1/x. But well the limit is and was 1.
Yes, I agree with your comment. Thank you.
Thank you
factoring x2 in the denominator is not 1/x?
I actually thought maybe he applied a rule I'm not aware of. for function f(x) = (x^2 (1-1/x))/(x^2 (1+1/x^2 ) ) not (x^2 (1-1/x))/(x^2 (1+1/x) )
Factoring x**2 out of x**2+1 gives you x**2(1+(1/x**2)) not just 1+1/x
@@_torgeek9108 well, yes, divide the highest denominator power
Hi is'nt x-1 < [x] ≤x?
Yes
Great video very much helpful
This is the most comprehensive video on Squeeze theorem i've seen. Great video. New for me is the upper and lower boundaries
This is art !
I thought I had lost my link to this video and was panicking. This is my first choice of all videos on the web for understanding the squeeze theorem.
this finally made sense. thank you!!!
Thankyou so much sir !
thanks for you explanation
Thank you, this was really helpful
Great video! I think at 16:00 you made a slight mistake. Factoring x**2 out of x**2+1 gives you x**2(1+(1/x**2)) not just 1+1/x. But well the limit is and was 1.
Yes, I agree with your comment. Thank you.
Thank you
factoring x2 in the denominator is not 1/x?
I actually thought maybe he applied a rule I'm not aware of. for function f(x) = (x^2 (1-1/x))/(x^2 (1+1/x^2 ) ) not (x^2 (1-1/x))/(x^2 (1+1/x) )
Factoring x**2 out of x**2+1 gives you x**2(1+(1/x**2)) not just 1+1/x
@@_torgeek9108 well, yes, divide the highest denominator power
Hi is'nt x-1 < [x] ≤x?
Yes