real analysis//sequence and series Bsc first semester//iitjam/csirnet maths/upsc maths/L20//by Hdsir
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- Опубликовано: 14 дек 2024
- real analysis//sequence and series Bsc first semester//iitjam/csirnet maths/upsc maths/L19//by Hdsir
real analysis//sequence and series Bsc first semester//iitjam/csirnet maths/upsc maths/L19//by Hdsir
limit n tending to infinity (1+1/2+1/3.......1/n) not exists convergent sequence real analysis
Great teacher
❤❤❤❤🎉🎉🎉 amazing 😍😍 God blessed you more
Thank you SIR,Sir Please if u can
teach complex analysis 🙏 🙏🙏🙏
How to solve (-1)^n÷n in the same way?
Nice sir happy Dhantarus
Sir , if we compare n+1 ,n+2,n+3.........with n in
place of 2n then the sequence would be cauchy
as |Am-An|
Thank u sir 🙏🏻🙏🏻🙏🏻
Sir ye to series hoga na .... 🤔
Isme addition ka symbol use kra hua hai .....
Sequence to =
Aise hona chahiye na ?? 😵
Ye sequence ka nth term hai
Sequence kuch aisa hai
u1 = 1
u2= 1+1/2
u3= 1+1/2+1/3
Upto
un = 1+1/2+1/3+1/4+1/5+…………+1/n
@@RR_theproahole thnx for the reply but it's too late 😂
Thanks sir
🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Thankuuu... Soo much sir jii
Welcome
Sir sequence monotonic hai but bounded nahi hai .
That implies not convergent.
That implies is not a cauchy sequence.
ahi se bhi bol sakte hai na sir ?
भाई bounded hai sequence, upper bound 1 aur lower bound 0 exist kar raha hai
@@onlinestudywithBhavesh0204 bounded nahi hai bhai kyu ki iska lower bound 1 but upper bound does not exist.
Explanation : a sequence ka nth term hai.
A1=1
A2=1+1/2
A3=1+1/2+1/3
A4=1+1/2+1/3+1/4
................................
Aur = a sequence alag hai.
B1=1/1
B2=1/2
B3=1/3
.............
A sequence bdd hai kyu ki iska uper bound 1 aur lower bound 0 hai.
Sir I love your mathmatics
Thank you
Great sir
Thank you ❤️ sir
Very nice sir
Sir sequence toh convergent hai kyuki lim n tending to infinite pr value finite aa rhi hai toh cauchy kyuu nhi hai
Thank you sir
Brilliant idea
Sir would you please upload the videos of projective geometry (axiomatic approach)
How it is a sequence?
Sir real analysis Ka objective books bataye
Sir it is like a series
Sir the first tream off [a(n+1)] =1/2 not because n=1,2,3..... Not n=0 sir why € not=1 or 2
Sir kya ye seq bounded nahi hai
Kyoki ye monotonic to hai
Or bounded or monotonic hone par ye convergent ho jayega or tab Cauchy bhi hoga na theorem se
Please sir help me in my doubt
It is not bounded therefore not convergent
Yes monotonic but not convergent
Sir series infinite series ke playlist mei. Hai n
Yes
1+1/3+(1/3)^2+....+(1/3)^n-1+... converges sir what about this
I will discuss in convergence of series
Sir 1/n convergent h ya divergent...plz explain
Is it sequence or series
if limit exists for a sequence then is it convergent necessarily (eg (n+ (-1)^n)/n limit=1 but sequence is not convergent) Sir pls confirm
Ok i will see it please wait
🙏🏻🙏🏻🙏🏻
why e=1/10???
e can Take any value just the condition is e>0 and e is so small
salute sir🫡
Sir apka csir net clear hai
Bhai is se kya test krega tu, NET to गधे bhe clear kr lete h
How 1/n+3 > 1/2n for n =1
Please rply sir
Beedhe coaching classes
Thank you sir
Thank u sir