Dear Sir: Thank you very much. I'm asking about two things: 1- How to calculate spin quantum number ( I) to 1/2 or 3/2 or.... 2- Why should neutron affect the NMR ? I mean H has one proton but it's charged and it affect and affected by magnetic filed, while D has one proton and one neutron but we can see it by NMR, why? while the difference is Neutron ( which is not charged)???
Consider lower energy state A(110 A) and higher energy state A*(100 A)(higher energy level already have 1 hv). We have to give 210 hv (RF), 110 A + 110 hv => 110 A* 100 A* +100 hv => 100 A + 2OO hv (de-excitation with emission of hv ) total absorption 10 hv
When I using JEOL delta software to do proton integration, I found that -COOMe (methyl acetate), this ester methyl or methoxy is not around 3, but 2, why? The other methyls of this molecule is around 3. I thinking was it because one hydrogen loss?
For example, a solution have total 210 molecules. 100 molecules are spin down (high energy) and 110 molecules are spin up (low energy). So when resonance, 110 spin up absorb energy to flip and become 110 spin down? Or only 10 spin up as excess population will absorb energy to flip and become 10 spin down?
I've been always told that the theory of NMR is very difficult; it was really clear and simple the way professor Nowick explained. Thanks a lot!!
Although it's the graduate course, it's still crystal clear about the basic concepts of NMR ! Very helpful!
Thank you so much and could you please, where can i get this serious of lessons collectively?
Dear Sir: Thank you very much. I'm asking about two things:
1- How to calculate spin quantum number ( I) to 1/2 or 3/2 or....
2- Why should neutron affect the NMR ? I mean H has one proton but it's charged and it affect and affected by magnetic filed, while D has one proton and one neutron but we can see it by NMR, why? while the difference is Neutron ( which is not charged)???
Consider lower energy state A(110 A)
and higher energy state A*(100 A)(higher energy level already have 1 hv).
We have to give 210 hv (RF),
110 A + 110 hv => 110 A*
100 A* +100 hv => 100 A + 2OO hv (de-excitation with emission of hv )
total absorption 10 hv
When I using JEOL delta software to do proton integration, I found that -COOMe (methyl acetate), this ester methyl or methoxy is not around 3, but 2, why? The other methyls of this molecule is around 3. I thinking was it because one hydrogen loss?
Thanks, it is perfect explain. what are good references(book) for this topic?
I'm again wondering how do we calculate that ( I)? whee did come from ? what is its rule
Pleeeeeeeeaaaaaaaaaseeeeeee
Sir, Thanks... . I always pray for you.
Who knows the textbook used in this course? Thanks.
It is in the 1st lecture at the beggining
mike krigg Thanks. Get it!
Xu Du levine physical chemistry
Thanks a lot!
For example, a solution have total 210 molecules. 100 molecules are spin down (high energy) and 110 molecules are spin up (low energy). So when resonance, 110 spin up absorb energy to flip and become 110 spin down? Or only 10 spin up as excess population will absorb energy to flip and become 10 spin down?
i enjoyed watching this and at same time learnt a lot. Thank you for this video
Great lecture, very useful! Thanks for sharing.
thanks this helps me a lot
aawesome, very nice dear
nice class
a big thank you...
Thank you sir....
in NMR its always the excess I believe
chemistry videos, the only usefull videos at this channel
Thank you, very helpful.
thnxs very wonderful lecture
thanks ..
why nucleus spin? please answer this question!
thank you
thanks a lot!!
Thanks!!!
thnx