Electrochemistry - Free Formula Sheet: bit.ly/3NLeylq Chemistry 2 Final Exam Review: ruclips.net/video/lSmJN1_uVpI/видео.html Chemistry PDF Worksheets: www.video-tutor.net/chemistry-basic-introduction.html Next Video: ruclips.net/video/lUXP856WluE/видео.html
Professor Organic Chemistry Tutor, thank you for showing How to Draw Galvanic and Voltaic Cells in AP/General Chemistry. The drawings and explanation of the Galvanic and Voltaic Cells are excellent from left to right in the video. I am very familiar with anode and cathode from Electronic Circuit Design/Advanced Electronics. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.
OMGGGG the way you said “Iron” My heart ♥️ I kept thinking while watching the video what is iRON but then noticed you meant Fe as in iron lol Literally same, and my bf always makes fun of me for it 😭 because I pronounce Iron as IRAN lmao
I have a question, in the last problem, you wrote that the sulfate anions travel from the right solution, through the salt bridge, to the left solution. But where do these sulfate ions come from in the right solution? Aren't they only produced from the nickel sulfate in the left solution?
Sorry I'm late af but, note that the Bromide Cathode is in a Bromide-Sulfate (Br2SO4) solution. When there are free electrons on the cathode, the bromide detaches from the sulfate, *to add more mass to the cathode* leaving a buildup of sulfate ions (and hence a negative charge) at the cathode. However, these sulfate ions are attracted to the anode's zinc ions, travel through the salt bridge and attach to them. Hope this makes sense :)
Consider the Galvanic cell whose setup is schematized below at 298 K. Al(s) | Al3+(aq) || H+(aq), H2(g, 1 atm) | Pt(s) The aluminium solution is prepared by dissolving 200.0 mg of Al(NO3)3 in 20.00 mL of water. The acidic solution is prepared by diluting 0.20 mL of HClO4 (70% w/w.; density rho = 1.67 gmL-1) with pure water. When the cell is connected via a salt bridge, an electrochemical potential of 1.58 V is measured. Using the provided E data below, calculate the amount of pure water added to the concentrated HClO4. 2H+(aq) + 2e- -> H2(g) Enode red = 0.00 V Al3+(aq) + 3e- -> Al(s) Enode red = 1.66 V
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02:12
please God add more years of life for him
@Gilbert Streeton haha yeah no one cares so kindly go away :)
@@timothyc2346 its a year old comment bruv.....
Aaminn
🙏🙏🙏
This was an amazing video, it made understanding galvanic cells so much easier! Thank you!
Thanks for this, you're helping so many people. Chemistry is made easy here
thanks for always helping me survive chem... 2 years in a row now HAHA
same and i’m going to uni next year!!
Saved me from hours of work. Much love
Professor Organic Chemistry Tutor, thank you for showing How to Draw Galvanic and Voltaic Cells in AP/General Chemistry. The drawings and explanation of the Galvanic and Voltaic Cells are excellent from left to right in the video. I am very familiar with anode and cathode from Electronic Circuit Design/Advanced Electronics. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.
OMGGGG the way you said “Iron”
My heart ♥️
I kept thinking while watching the video what is iRON but then noticed you meant Fe as in iron lol
Literally same, and my bf always makes fun of me for it 😭 because I pronounce Iron as IRAN lmao
I have a question, in the last problem, you wrote that the sulfate anions travel from the right solution, through the salt bridge, to the left solution. But where do these sulfate ions come from in the right solution? Aren't they only produced from the nickel sulfate in the left solution?
Sorry I'm late af but, note that the Bromide Cathode is in a Bromide-Sulfate (Br2SO4) solution. When there are free electrons on the cathode, the bromide detaches from the sulfate, *to add more mass to the cathode* leaving a buildup of sulfate ions (and hence a negative charge) at the cathode. However, these sulfate ions are attracted to the anode's zinc ions, travel through the salt bridge and attach to them.
Hope this makes sense :)
in the last example, where did we get the SO42- anion (going to the anode through the salt bridge) from a bromine and sodium bromide solution?
Same how?
How do I know what electrolyte to use for a certain half cell?
You're amazing😭
Consider the Galvanic cell whose setup is schematized below at 298 K.
Al(s) | Al3+(aq) || H+(aq), H2(g, 1 atm) | Pt(s)
The aluminium solution is prepared by dissolving 200.0 mg of Al(NO3)3 in 20.00 mL of water.
The acidic solution is prepared by diluting 0.20 mL of HClO4 (70% w/w.; density rho = 1.67
gmL-1) with pure water. When the cell is connected via a salt bridge, an electrochemical
potential of 1.58 V is measured. Using the provided E data below, calculate the amount
of pure water added to the concentrated HClO4.
2H+(aq) + 2e- -> H2(g) Enode red = 0.00 V
Al3+(aq) + 3e- -> Al(s) Enode red = 1.66 V
You are a life saver ❤
very useful video for this topic)thanks
tq bro form malaysia
I understand it well thanks❤
You are a fucking legend my man! thanks !!!
Super love it❤
please can you make a video on symmetry???
The cell potential working out, is it correct 😮
Question? Is it possible to use 2 nonmetals like CI and Br?
No I don't think so
why do we need both bromide and bromine solution?
Why did you use NaBr in cathode side
bro be soloing khan academy atp-
The Organic Chemistry Tutor should teach university professors how to do their jobs.
2024
How abt same electrode
Why did it go from bromide to platinum?
Can’t use br2 as an electrode since it’s non metal
Where did the +0.76 come from? anyone can give me the formula pls :(
You would get this value from a redox table of 1/2 reactions. Essentially this number is the standard electrical potential for Zn
What the fuck
Same bro
You is no understanding us
LOL