Electric Potential of a Conducting Sphere

[@DesmondJamesLincoln]

Thank you, this was helpful.

[@blackhole1222]

Thank you!
Have a lovely day

[@HannahMirsharif]

finally i understand what the integral stuff means!! thank you!!

[@good-luck-ugo]

Thanks, this was really helpful and concise

[@shivrastra9759]

Great explanation, jorden bhau 😊

[@eneskoc3962]

our direction is infinity to surface point. So why we use instead of .

[@connerkai]

Does the graph of V(r) need to have a constant slope for r>R? V(r) goes like 1/r, not 1/r^2.

[@ravikumarchitosiya]

Nice lecture sir

[@ahu1d6y40]

thx man 👍

[@sunnysingh-yc5lp]

thx sir