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Good question sir waheeb SAB 🎉❤
(x + y)³ = 10√10x + y = √10xy(x + y) = 2√10xy = 2x + 2/x = √10x² - x√10 + 2 = 0x = (√10 ± √2)/2(x, y) = [(√10 + √2)/2, (√10 - √2)/2](x, y) = [(√10 - √2)/2, (√10 + √2)/2]
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Good
Good question sir waheeb SAB 🎉❤
(x + y)³ = 10√10
x + y = √10
xy(x + y) = 2√10
xy = 2
x + 2/x = √10
x² - x√10 + 2 = 0
x = (√10 ± √2)/2
(x, y) = [(√10 + √2)/2, (√10 - √2)/2]
(x, y) = [(√10 - √2)/2, (√10 + √2)/2]
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