I have to give a presentation about the efficiency of solar cells, with special emphasis on the Shockley Queisser limit the next days and your video helped me a lot to understand the original paper. Thank you very much ;)
Hey..could someone please clear my doubt? I am not getting the part where it was explained that Rabs=Remiited. Because any body at a certain temperature emits radiations. How can we attribute it to radiative recombination? e.g: Imagine any other body(rock, metal piece etc.) kept in the place at that exact spot. According to stefan's law, that body will also emit radiation and be in equilibrium with the surroundings. Since it is at a non zero temperature, it will emit energy. There is no recombination or such phenomenon here. So how did we say that radiations emitted by this semiconductor are because of recombinations?
Wondering the same...Did you ever figure it out? I think that maybe the process of radiative recombination adds to this blackbody radiation and thus the inherent radiation described by stefan's law decreases so as to keep the cell at thermal equilibrium with its surroundings. Basically, I think that in order to maintain equilibrium, the material would radiate less to balance the additional radiation of recombination. Just an idea. I don't know for sure. Let me know if you know the actual reason.
Just found something: courses.edx.org/c4x/DelftX/ET.3034TU/asset/solar_energy_v1.1.pdf If you go to page 118-119 and read the portion under 10.2.2 , it says that electron-hole recombination is actually caused by the absorption of thermal radiation. The release of those photons is what keeps thermal equilibrium in the semiconductor. Basically from what I understand, if the panel was at 0K, this process wouldn't occur. The fact that we consider the panel to be at 300K (room temp) means that it has to absorb and emit thermal radiation and electron-hole recombination is the mechanism by which it does this. To answer your question though, I think that electrons, of any element, can be excited to a higher state. The converse is that any electron in an excited state can lose its energy and drop down to a lower energy level. The result is the emission of phonons. Thus, whether it is a metal, a human being's skin, or a semiconductor, the process of electron excitation and de-excitation is similar. (I don't know the last part for sure...)
I have to give a presentation about the efficiency of solar cells, with special emphasis on the Shockley Queisser limit the next days and your video helped me a lot to understand the original paper. Thank you very much ;)
Thanks for your work. Great explanation.
Great Video.
Could you answer Aniruddh Shrivasta's comment and see if my explanation is correct?
Hey..could someone please clear my doubt?
I am not getting the part where it was explained that Rabs=Remiited. Because any body at a certain temperature emits radiations. How can we attribute it to radiative recombination? e.g: Imagine any other body(rock, metal piece etc.) kept in the place at that exact spot. According to stefan's law, that body will also emit radiation and be in equilibrium with the surroundings. Since it is at a non zero temperature, it will emit energy. There is no recombination or such phenomenon here. So how did we say that radiations emitted by this semiconductor are because of recombinations?
Wondering the same...Did you ever figure it out?
I think that maybe the process of radiative recombination adds to this blackbody radiation and thus the inherent radiation described by stefan's law decreases so as to keep the cell at thermal equilibrium with its surroundings. Basically, I think that in order to maintain equilibrium, the material would radiate less to balance the additional radiation of recombination.
Just an idea. I don't know for sure. Let me know if you know the actual reason.
Just found something: courses.edx.org/c4x/DelftX/ET.3034TU/asset/solar_energy_v1.1.pdf
If you go to page 118-119 and read the portion under 10.2.2 , it says that electron-hole recombination is actually caused by the absorption of thermal radiation. The release of those photons is what keeps thermal equilibrium in the semiconductor.
Basically from what I understand, if the panel was at 0K, this process wouldn't occur. The fact that we consider the panel to be at 300K (room temp) means that it has to absorb and emit thermal radiation and electron-hole recombination is the mechanism by which it does this.
To answer your question though, I think that electrons, of any element, can be excited to a higher state. The converse is that any electron in an excited state can lose its energy and drop down to a lower energy level. The result is the emission of phonons. Thus, whether it is a metal, a human being's skin, or a semiconductor, the process of electron excitation and de-excitation is similar.
(I don't know the last part for sure...)
@@VishveshDhar Thanks for sharing that PDF document!