Realizing Full Adder using NAND Gates only

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  • Опубликовано: 20 окт 2014
  • Digital Electronics: Realizing Full Adder using NAND Gates only.
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Комментарии • 61

  • @amribnaas
    @amribnaas 8 месяцев назад +5

    Thanks Neso You Simplified This ❤️

  • @fouziasharmin6218
    @fouziasharmin6218 3 года назад +1

    thank u neso. i was struggling with this.

  • @ShivaKumar-ch2st
    @ShivaKumar-ch2st 7 лет назад +2

    superb and simple explanation..

  • @iftakharalam1650
    @iftakharalam1650 6 лет назад +13

    u r the best man!

  • @saumyasinha9995
    @saumyasinha9995 7 лет назад +1

    Thank you so much

  • @malihamoonwaraoishi5498
    @malihamoonwaraoishi5498 8 лет назад +5

    sir u r just awesome!!! Thank u sooooo much :)

  • @Salmankhan-mi9rn
    @Salmankhan-mi9rn 5 лет назад

    Thanks for the video

  • @DeepakGupta_er
    @DeepakGupta_er 6 месяцев назад +5

    What is the need to implement full adder using nand gate, when we can easily implement it using EX-OR gate

    • @yusrax3
      @yusrax3 5 месяцев назад +1

      maybe because they're universal gates-

  • @kshitijvengurlekar1192
    @kshitijvengurlekar1192 7 лет назад +1

    Thank You

  • @mohanarajendran4332
    @mohanarajendran4332 3 года назад +1

    Thank u so much sir🙏🙏🙏

  • @ravneetsingh6206
    @ravneetsingh6206 8 лет назад +7

    QUITE SATISFACTORY EXPLANTION THANK U VERY MUCH

  • @gargisharma1866
    @gargisharma1866 5 лет назад +5

    Sir did you made lectures on series and parallel adders..please reply

  • @rajanbhandari607
    @rajanbhandari607 8 лет назад +2

    Could you explain full adder using NOR gate only??

  • @just-being-aryan
    @just-being-aryan Год назад +24

    God help me

  • @FarhanAli-xb9nx
    @FarhanAli-xb9nx 5 лет назад

    keep it up Bro....

  • @ibrahimrahim1604
    @ibrahimrahim1604 Год назад

    Thanks a lot ❤❤

  • @7azure
    @7azure Год назад

    Thank you good explanation

  • @lavishgarg4274
    @lavishgarg4274 5 лет назад +3

    Sir pls add a video of full adder using NOR gates if possible

  • @sundarrajuramesh2372
    @sundarrajuramesh2372 2 года назад +1

    Proper explanation

  • @soorajm.d7233
    @soorajm.d7233 4 года назад

    Thankyou sir ❤️

  • @chandangowdachandu1348
    @chandangowdachandu1348 5 лет назад +1

    Osm bro....👌👌

  • @danishbhatia1734
    @danishbhatia1734 7 лет назад +12

    where is full adder by nor gate?

  • @barsilgen120
    @barsilgen120 2 года назад

    Thanks a lot

  • @nitishkumarprajapati6096
    @nitishkumarprajapati6096 2 года назад

    Thanks Sir ☺️☺️

  • @zoyaKhan-ty9dr
    @zoyaKhan-ty9dr 5 лет назад +2

    Plz explain full adder using nor gate

  • @RanaElabd
    @RanaElabd 2 месяца назад

    thanks

  • @kapildeshmukh7878
    @kapildeshmukh7878 4 года назад +1

    Impressive

  • @FredoCorleone
    @FredoCorleone 8 лет назад +11

    How can a nand make the sum? I mean how do you arrived to the fact [(A*B)(A+B)Ci] = (A*B)+Ci(A+B)?

    • @rajendradulal8106
      @rajendradulal8106 2 года назад

      COUT = A B + A CIN + B CIN
      = A B + A CIN + B CIN (A + A)
      = A B + A CIN + A B CIN + A B CIN
      = A B (1 + CIN)+ A CIN + A B CIN
      = A B + A CIN + A B CIN
      = A B + A CIN (B + B) + A B CIN
      = A B + A B CIN + A B CIN + A B CIN
      = A B (1 + CIN )+ CIN (A B + A B)
      = A B + CIN (A B + A B)
      = A B + CIN (A Ex-OR B)
      Therefore, COUT = A B + CIN (A ⊕ B)

    • @PreetiSharma-hv7rl
      @PreetiSharma-hv7rl Год назад +2

      I have same question sir please reply ?

    • @bhaskarjyotimahanta9003
      @bhaskarjyotimahanta9003 Год назад +1

      [(A*B)' . ( (A xor B)*C ) ' ] '
      Using De-Morgans law ,
      A*B + (A XOR B)*C
      Which is the Carry of Full Adder

    • @krishmehra3267
      @krishmehra3267 Год назад

      It’s a nand gate bro ,first sir did the multiplication of the two input and then complimented the both the input

    • @sampurnabanerjee7565
      @sampurnabanerjee7565 Год назад

      De Morgans

  • @C.r.i.m.s.o.n
    @C.r.i.m.s.o.n 2 года назад

    saved my grade, thx

  • @MrJojujojujoju
    @MrJojujojujoju 9 лет назад +2

    Expression plz

  • @user-pz7jx3gd3l
    @user-pz7jx3gd3l 10 месяцев назад

    super sir❤

  • @karan-dt5il
    @karan-dt5il 5 лет назад

    Why we use and gate at last why not just or... To add them ....
    Coz we have both of them why did we just not or them

  • @navalsharma375
    @navalsharma375 8 месяцев назад +1

    Can we design it more easily by giving input A' with B, B' with A??
    It will form a different circuit diagram but the output is same🤔

    • @aadityasuthar2199
      @aadityasuthar2199 5 месяцев назад

      no , we only have inputs and nand gate. In order to get A" we need to use NOT gate which we can't use(not given)

  • @vinaylingam9985
    @vinaylingam9985 7 лет назад

    i need proof for carry from nand gates... ? will the expression included above is same as AB + BC + CA ??

  • @adityabodke6120
    @adityabodke6120 7 лет назад +1

    isn't the carry output supposed to be AB'+BC'+CA' ?
    correct me if I'm wrong please.

    • @NakshatraSaxena
      @NakshatraSaxena 7 лет назад +3

      it is supposed to be A.B + B.Ci + A.Ci which is same as A.B + Ci(A XOR B). Hope that helped.

    • @ziyucheng2518
      @ziyucheng2518 5 лет назад

      U r right, actually these two expressions are equivalent. It depends on convenience.

    • @AnoNymous-po5sx
      @AnoNymous-po5sx 3 года назад

      @@NakshatraSaxena Hi. I know it's three years late.😂 But please let me know how AB+BCi+ACi is equivalent to AB+Ci(A xor B)? Isn't it supposed to be AB+Ci(A or B)??? What am I missing?

    • @ankitpant8765
      @ankitpant8765 Год назад

      @@AnoNymous-po5sx It means that carry is only generated whenever either a and b are 's1 means AB or either A or B are once means A Xor B and c is 1 means C(A xor B).
      So ans is AB + C(A xor B)

  • @suryayeluri4678
    @suryayeluri4678 4 года назад

    How do you get the idea of xor gate to be like that? If iam doing it iam getting one gate extra everywhere.iam writing the expression using and,or gates then converting them using nand gates.is there any other way? Or just we muat remember?

    • @nishanth1828
      @nishanth1828 4 года назад

      It's actually an optimised version.Needs some practice to understand!

    • @suryayeluri4678
      @suryayeluri4678 4 года назад

      @@nishanth1828 I am having assignments on implementing function using only universal gates! Where can I read some examples of these?

    • @nishanth1828
      @nishanth1828 4 года назад

      Maybe this link gives you a bit of confidence while implementing xor gate.

  • @kratigupta80
    @kratigupta80 7 лет назад

    Are A and B two 8 bit numbers?

  • @shubhamverma6672
    @shubhamverma6672 3 года назад

    Why did you don't do Full adder using NOR gate

  • @konarksharma9095
    @konarksharma9095 3 года назад

    Bhai jbh figure ka ss lena hota aapki video ajati hai end mein

  • @user-hl4ji1ey1b
    @user-hl4ji1ey1b 8 месяцев назад

    kuch samjh nhi aaya

  • @GurveerSingh-ls3ms
    @GurveerSingh-ls3ms Год назад

    ❣️❣️

  • @akshaydasm.k9388
    @akshaydasm.k9388 7 лет назад +2

    where's the goddamn boolean expression of HA using nand gate???

    • @rishavkashyap325
      @rishavkashyap325 7 лет назад

      Akshay Das M.K khud b pdh liya kro kuch to 😝😂😂

  • @schitlipz
    @schitlipz 9 лет назад

    In the title, using the word "Gate" in plural form ("Gates") would have been more clear.

  • @amribnaas
    @amribnaas 7 месяцев назад

    Full Adder NOR Gate Please 🥹